Problem 62
Question
Draw the structure of the open-chain form of fructose. Circle all chiral carbons, and then calculate the number of stereoisomers with the same formula as fructose.
Step-by-Step Solution
Verified Answer
The open-chain form of fructose has the following structure:
O
||
H-C-OH
|
H
C-OH
|
C-OH
|
H-C-OH
|
CH2OH
There are three chiral carbons, as indicated by asterisks (*):
O
||
H-C-OH *
|
H
C-OH *
|
C-OH *
|
H-C-OH
|
CH2OH
Using the equation 2^n, where n is the number of chiral carbons (3 in this case), there are 2^3 = 8 possible stereoisomers with the same formula as fructose.
1Step 1: Drawing the open-chain form of fructose
Fructose, also called D-fructose or dextro-fructose, is a monosaccharide with the chemical formula C6H12O6. In its open-chain form, fructose has a structure as follows:
O
||
H-C-OH
|
H
C-OH
|
C-OH
|
H-C-OH
|
CH2OH
2Step 2: Identifying and circling the chiral carbons
A chiral carbon atom is a carbon that has four different groups attached to it. In the structure of fructose, there are three chiral carbons which can be marked as follows:
O
||
H-C-OH *
|
H
C-OH *
|
C-OH *
|
H-C-OH
|
CH2OH
Each asterisk (*) represents a chiral carbon atom.
3Step 3: Calculating the number of stereoisomers
To find the total number of stereoisomers for fructose, we will use the equation 2^n, where n is the number of chiral carbons. In fructose, we have identified three chiral carbons:
Number of stereoisomers = 2^n = 2^3 = 8
So, there are 8 possible stereoisomers with the same formula as fructose.
Key Concepts
Chiral CarbonStereoisomersOpen-Chain FormMonosaccharide
Chiral Carbon
A chiral carbon, also known as an asymmetric carbon, is a carbon atom that is bonded to four different atoms or groups of atoms. This unique structural feature makes it capable of existing in two non-superimposable mirror image forms, known as enantiomers. In the open-chain form of fructose, certain carbon atoms meet these criteria and thereby become chiral.
- For fructose, each chiral carbon is represented with an asterisk in the molecular structure.
- These chiral centers are crucial for the molecule's stereochemistry and significantly impact its biological properties and functions.
Stereoisomers
Stereoisomers are molecules that have the same molecular formula and sequence of bonded atoms, but they differ in the three-dimensional orientations of these atoms in space. They can exhibit very different properties despite having similar structures.
- Two main types of stereoisomers are enantiomers and diastereomers.
- Enantiomers are mirror images of each other and cannot be superimposed, like left and right hands.
- Diastereomers, on the other hand, are not mirror images.
Open-Chain Form
The open-chain form of fructose is one way in which the molecule can appear, depicting its structure with a linear arrangement of atoms. In this form, fructose shows its backbone consisting of carbon atoms, each bonded with hydrogen and hydroxyl (OH) groups.
- The open-chain structure is important for understanding the molecule's potential to form ring structures, such as the five-membered furanose ring typical of fructose.
- It also aids students in identifying the location of the chiral carbons more easily, as displayed in the linear form of the molecule.
Monosaccharide
Monosaccharides are the simplest form of carbohydrates, consisting of a single sugar molecule. They serve as building blocks for more complex sugars like disaccharides and polysaccharides. Fructose is a prime example of a monosaccharide, characterized by its sweetness and role in various biological processes.
- Monosaccharides can exist in different forms, such as the open-chain and cyclic ring structures.
- They can combine through glycosidic bonds to form disaccharides, like sucrose, or polysaccharides, which are important for energy storage and structural components of cells.
Other exercises in this chapter
Problem 60
The hydrolysis of cellulose, glycogen, and starch produces only one monosaccharide. Why is this so? What monosaccharide is produced?
View solution Problem 61
Digestion Disaccharides and polysaccharides cannot be broken down in the absence of water. Why do you think this is so? Include an equation in your answer.
View solution Problem 63
Sugars Compare and contrast the molecular formula, molecular weight, and functional groups found in glucose and fructose.
View solution Problem 64
Historical Perspective Carbohydrates are not hydrates of carbon as the name suggests. Explain how this misconception occurred.
View solution