Problem 62
Question
Convert the rectangular equation to polar form. Assume \(a<0\) $$x^{2}+y^{2}-2 a y=0$$
Step-by-Step Solution
Verified Answer
Therefore, the polar form of the rectangular equation \(x^{2}+y^{2}-2 a y=0\) is \(r = 2a\sin(\theta)\).
1Step 1: Write Down the Polar Form
The polar form can be illustrated as: \(r = \sqrt{x^{2}+y^{2}}\), \(x = r\cos(\theta)\), \(y = r\sin(\theta)\).
2Step 2: Substitute x and y in terms of r and theta
Replace \(x\) and \(y\) in our given equation \(x^{2}+y^{2}-2 a y=0\) by their polar counterparts. This yields: \((r\cos(\theta))^{2}+(r\sin(\theta))^{2}-2a(r\sin(\theta))=0\).
3Step 3: Simplify the Equation
Now, simplify the equation obtained in Step 2. The left term simplifies via the pythagorean identity into \( r^{2} = 2ar\sin(\theta)\). This simplifies further to \( r = 2a\sin(\theta)\).
4Step 4: Express Final Equation in Polar Form
Finally, the polar form of the equation \(x^{2}+y^{2}-2 a y=0\) is \(r = 2a\sin(\theta)\).
Key Concepts
Rectangular to Polar ConversionPythagorean IdentityTrigonometric Substitution
Rectangular to Polar Conversion
The process of converting a rectangular equation to a polar form involves changing the coordinate system from a Cartesian (rectangular) coordinate system to a polar coordinate system. In the rectangular coordinate system, points are located using the coordinates \(x\) and \(y\). These represent horizontal and vertical distances respectively from a fixed reference point called the origin.
The polar coordinate system, however, uses a different approach. Instead of horizontal and vertical distances, it uses a distance \(r\) (radius) from the origin and an angle \(\theta\) from the positive x-axis. This is particularly useful in equations involving circles and other curves, where relationships between distances and angles are more intuitive.
To convert a rectangular equation to polar form:
The polar coordinate system, however, uses a different approach. Instead of horizontal and vertical distances, it uses a distance \(r\) (radius) from the origin and an angle \(\theta\) from the positive x-axis. This is particularly useful in equations involving circles and other curves, where relationships between distances and angles are more intuitive.
To convert a rectangular equation to polar form:
- Use the formulas \(x = r\cos(\theta)\) and \(y = r\sin(\theta)\).
- Replace every \(x\) and \(y\) in the equation with these expressions.
- Simplify the equation, using known trigonometric identities when possible, to express it in terms of \(r\) and \(\theta\).
Pythagorean Identity
The Pythagorean identity is a cornerstone of trigonometry, rooted in the Pythagorean theorem. It states that for any angle \(\theta\), the square of the sine function plus the square of the cosine function equals one:
\[\sin^2(\theta) + \cos^2(\theta) = 1\]
This identity is universal for all angles and plays a crucial role in simplifying and converting trigonometric equations.
In the context of polar and rectangular conversions, the Pythagorean identity helps to simplify expressions involving \(r\). For a point \( (x, y) \) in rectangular coordinates, the equivalent polar expression is \( r = \sqrt{x^2 + y^2} \), derived directly from the Pythagorean identity.
When manipulating an equation, this identity can also help to eliminate terms and simplify the relationship between variables, making it easier to isolate \(r\) or \(\theta\), as we simplified the step \( r^2 = x^2 + y^2 \) to simply \( r = 2a \sin(\theta) \) in our example.
This simplification demonstrates how powerful the Pythagorean identity can be, providing an elegant way to clean up complex expressions.
\[\sin^2(\theta) + \cos^2(\theta) = 1\]
This identity is universal for all angles and plays a crucial role in simplifying and converting trigonometric equations.
In the context of polar and rectangular conversions, the Pythagorean identity helps to simplify expressions involving \(r\). For a point \( (x, y) \) in rectangular coordinates, the equivalent polar expression is \( r = \sqrt{x^2 + y^2} \), derived directly from the Pythagorean identity.
When manipulating an equation, this identity can also help to eliminate terms and simplify the relationship between variables, making it easier to isolate \(r\) or \(\theta\), as we simplified the step \( r^2 = x^2 + y^2 \) to simply \( r = 2a \sin(\theta) \) in our example.
This simplification demonstrates how powerful the Pythagorean identity can be, providing an elegant way to clean up complex expressions.
Trigonometric Substitution
Trigonometric substitution is a method used to replace algebraic expressions with trigonometric functions, facilitating easier manipulation of the equation. This is especially handy in calculus and when dealing with polar coordinates.
This technique is applied by replacing one or more parts of an equation with a trigonometric entity. For example, in converting rectangular to polar forms, \(x\) and \(y\) are replaced by \(r \cos(\theta)\) and \(r \sin(\theta)\) respectively.
By doing this, complex algebraic equations are transformed into simpler trigonometric forms. This simplification becomes apparent in equations that revolve around circles, spirals, and waves.
Some other common substitutions include:
This technique is applied by replacing one or more parts of an equation with a trigonometric entity. For example, in converting rectangular to polar forms, \(x\) and \(y\) are replaced by \(r \cos(\theta)\) and \(r \sin(\theta)\) respectively.
By doing this, complex algebraic equations are transformed into simpler trigonometric forms. This simplification becomes apparent in equations that revolve around circles, spirals, and waves.
Some other common substitutions include:
- Substituting \(\tan(\theta)\) for expressions involving \(\frac{y}{x}\) when dealing with slope or angles.
- Using \(\sec(\theta)\) and \(\csc(\theta)\) for reciprocal identities.
Other exercises in this chapter
Problem 61
Find the vertex, focus, and directrix of the parabola and sketch its graph. Use a graphing utility to verify your graph. $$y=\frac{1}{2} x^{2}$$
View solution Problem 61
Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. \(y^{2}+12 x+4 y+28=0\)
View solution Problem 62
The area of the lemniscate \(r^{2}=a^{2} \cos 2 \theta\) is \(a^{2} .\) Sketch the graph of \(r^{2}=16 \cos 2 \theta .\) Then find the area of one loop of the g
View solution Problem 62
Find the vertex, focus, and directrix of the parabola and sketch its graph. Use a graphing utility to verify your graph. $$y=-2 x^{2}$$
View solution