Problem 62
Question
A scientist begins with 100 milligrams of a radioactive substance that decays exponentially. After 35 hours, \(50 \mathrm{mg}\) of the substance remains. How many milligrams will remain after 54 hours?
Step-by-Step Solution
Verified Answer
Approximately 37.61 mg will remain after 54 hours.
1Step 1: Understanding Exponential Decay Formula
In problems involving exponential decay, the formula used is \( N(t) = N_0 e^{-kt} \), where \( N(t) \) is the quantity remaining after time \( t \), \( N_0 \) is the initial quantity, and \( k \) is the decay constant. We need to find \( k \) using the given information.
2Step 2: Calculating the Decay Constant \( k \)
Given that \( N_0 = 100 \) mg and \( N(35) = 50 \) mg after 35 hours, we substitute these values into the exponential decay formula: \[ 50 = 100 e^{-35k} \]. Solving for \( k \), we get \[ e^{-35k} = \frac{1}{2} \], which simplifies to \[ -35k = \ln\left(\frac{1}{2}\right) \]. Thus, \[ k = -\frac{\ln\left(\frac{1}{2}\right)}{35} \].
3Step 3: Substitute \( k \) to Find Remaining Substance After 54 Hours
With \( k \) calculated, use the formula \( N(t) = 100 e^{-kt} \), where \( t = 54 \). Substitute \( k \) and \( t \) into the equation: \[ N(54) = 100 e^{-\frac{\ln\left(\frac{1}{2}\right)}{35} \cdot 54} \]. This can be simplified using properties of exponents as \[ N(54) = 100 \left( \frac{1}{2} \right)^{\frac{54}{35}} \].
4Step 4: Calculate the Remaining Milligrams
Using a calculator, evaluate \[ 100 \times \left( \frac{1}{2} \right)^{\frac{54}{35}} \] and find that \( N(54) \approx 37.61 \) mg. Thus, after 54 hours, approximately 37.61 milligrams of the substance will remain.
Key Concepts
Decay ConstantRadioactive SubstanceHalf-life Calculation
Decay Constant
The decay constant, represented as \( k \), is a key component in the exponential decay formula. It helps determine the rate at which a radioactive substance diminishes over time. Generally, decay constant is unique to each substance, allowing us to quantify how quickly or slowly a substance breaks down.
For example, the process to find the decay constant involves using known values of the substance. When you know how much substance remains after a specific period, you can apply the exponential decay formula:
For example, the process to find the decay constant involves using known values of the substance. When you know how much substance remains after a specific period, you can apply the exponential decay formula:
- \( N(t) = N_0 e^{-kt} \), where:
- \( N(t) \) is the amount remaining after time \( t \)
- \( N_0 \) is the initial quantity
- \( k \) is the decay constant
Radioactive Substance
A radioactive substance is a material that naturally breaks down over time, emitting radiation through a process called radioactive decay. This spontaneous decay changes the composition of the substance, reducing its original mass.
When dealing with radioactive substances, understanding their behavior is crucial for applications like medical treatments, carbon dating, and nuclear power. Characteristics that define radioactive substances include:
When dealing with radioactive substances, understanding their behavior is crucial for applications like medical treatments, carbon dating, and nuclear power. Characteristics that define radioactive substances include:
- Decay over time, changing to different elements or isotopes
- Emissions of alpha, beta, or gamma radiation
- Unpredictable decay times for individual atoms but predictable for large groups
Half-life Calculation
Half-life is a crucial concept when dealing with radioactive decay, referring to the time taken for half of a radioactive substance to decay. This allows scientists to predict how long a substance will remain active or effective. Calculating half-life involves understanding that the substance's mass reduces by half over each half-life period.
To calculate half-life, you can use the decay constant \( k \):
To calculate half-life, you can use the decay constant \( k \):
- The relationship is given by \( t_{1/2} = \frac{\ln(2)}{k} \)
Other exercises in this chapter
Problem 62
For the following exercises, solve the equation for \(x\), if there is a solution. Then graph both sides of the equation, and observe the point of intersection
View solution Problem 62
Is the following true: \(\frac{\log _{3}(27)}{\log _{4}\left(\frac{1}{64}\right)}=-1 ?\) Verify the result.
View solution Problem 63
For the following exercises, solve the equation for \(x\), if there is a solution. Then graph both sides of the equation, and observe the point of intersection
View solution Problem 63
In the year \(1985,\) a house was valued at \(\$ 110,000\). By the year 2005, the value had appreciated to \(\$ 145,000 .\) What was the annual growth rate betw
View solution