Problem 62
Question
(a) factor by grouping. Identify any prime polynomials. (b) check. $$ 8 c z+10 d z+12 a c+15 a d $$
Step-by-Step Solution
Verified Answer
The polynomial factorizes to \((2z + 3a)(4c + 5d)\). The factorization is correct upon verification.
1Step 1 - Group the terms
Group the terms in pairs to make factoring easier: \( (8cz + 10dz) + (12ac + 15ad) \).
2Step 2 - Factor out the greatest common factor (GCF) from each group
For the first group \(8cz + 10dz\), the GCF is \(2z\). For the second group \(12ac + 15ad\), the GCF is \(3a\). Factoring out these GCFs gives: \(2z(4c + 5d) + 3a(4c + 5d)\).
3Step 3 - Factor out the common binomial
Notice that \(4c + 5d\) is a common factor in both terms. Factor \(4c + 5d\) out: \((2z + 3a)(4c + 5d)\).
4Step 4 - Check the factorization
Expand \((2z + 3a)(4c + 5d)\) to check if it matches the original polynomial: \((2z + 3a)(4c + 5d) = 2z(4c + 5d) + 3a(4c + 5d) = 8cz + 10dz + 12ac + 15ad\). The original polynomial is correctly factorized.
Key Concepts
Grouping MethodGreatest Common FactorFactoring BinomialsChecking Factorization
Grouping Method
When factoring polynomials, one effective technique is the grouping method. This is especially useful if you cannot immediately spot a common factor for all terms. Here's how it works: First, look at the polynomial and split it into groups of terms. In our example, we have four terms: \(8cz + 10dz + 12ac + 15ad\). By grouping similar terms together, you get:
- (8cz + 10dz) - These terms have a 'z' in common.
- (12ac + 15ad) - These terms involve 'a' and 'd'.
Greatest Common Factor
Once you have grouped your terms, the next step is to factor out the greatest common factor (GCF) from each group. The GCF is the largest factor that divides each term. Consider the first group in our example:
- Group: (8cz + 10dz)
- The GCF is: 2z
- Group: (12ac + 15ad)
- The GCF is: 3a
Factoring Binomials
After factoring out the greatest common factors, you often end up with similar terms which can form a common binomial factor. In our example, after factoring out the GCFs, we have: \(2z(4c + 5d) + 3a(4c + 5d)\). Notice that both terms now contain the binomial \(4c + 5d\). You can factor this common binomial out, treating it as a common factor:
- Binomial: (2z + 3a)
- Common binomial factor: (4c + 5d)
Checking Factorization
To ensure the factorization is correct, always check by expanding the factors and confirming that you get the original polynomial. For our example, we factored the polynomial into \((2z + 3a)(4c + 5d)\). Expand this product:
- First, apply the distributive property: \(2z \cdot 4c + 2z \cdot 5d + 3a \cdot 4c + 3a \cdot 5d\)
- Simplify: \(8cz + 10dz + 12ac + 15ad\)
Other exercises in this chapter
Problem 62
Factor completely. Identify any prime polynomials. $$ 10 a c+15 a d+10 b c+15 b d $$
View solution Problem 62
Use any of the factoring methods to factor. Identify any prime polynomials. $$ 4 b^{2}+36 b+64 $$
View solution Problem 63
Factor completely. Identify any prime polynomials. $$ 3 a x^{2}-6 x^{2} $$
View solution Problem 63
Use any of the factoring methods to factor. Identify any prime polynomials. $$ 18 x^{2}+5 x-7 $$
View solution