Problem 62
Question
A bicycle tire has an internal volume of \(1.52 \mathrm{L}\) and contains 0.406 mol of air. The tire will burst if its internal pressure reaches 7.25 atm. To what temperature, in degrees Celsius, does the air in the tire need to be heated to cause a blowout?
Step-by-Step Solution
Verified Answer
The tire will burst at approximately 55.6 °C.
1Step 1: Identify Known Quantities and Formula
We are given the internal volume of the tire as \(1.52 \text{ L}\), the amount of air as \(0.406 \text{ mol}\), and the pressure at which the tire bursts as \(7.25 \text{ atm}\). We need to find the temperature that would cause this pressure, using the Ideal Gas Law formula: \[PV = nRT\] where \(P\) is pressure, \(V\) is volume, \(n\) is the number of moles, \(R\) is the ideal gas constant \((0.0821 \text{ L atm/mol K})\), and \(T\) is temperature in Kelvin.
2Step 2: Rearrange the Ideal Gas Law
Rearrange the ideal gas law equation to solve for temperature \(T\): \[T = \frac{PV}{nR}\]
3Step 3: Substitute the Known Values
Substitute the known values into the equation: \[T = \frac{(7.25 \text{ atm})(1.52 \text{ L})}{(0.406 \text{ mol})(0.0821 \text{ L atm/mol K})}\].
4Step 4: Calculate the Temperature in Kelvin
Perform the calculations: \[T = \frac{(7.25)(1.52)}{(0.406)(0.0821)} \approx 328.745 \text{ K}\].
5Step 5: Convert Temperature from Kelvin to Celsius
Convert the temperature from Kelvin to Celsius using the formula \(T_\text{C} = T_\text{K} - 273.15\): \[T_\text{C} = 328.745 - 273.15 = 55.595\text{ °C}\]. This is the temperature at which the air in the tire will cause it to burst.
Key Concepts
Pressure and TemperatureGas Law CalculationsThermodynamics in Chemistry
Pressure and Temperature
Gas pressure and temperature are intimately related in the context of the Ideal Gas Law. When gas molecules are heated, they gain kinetic energy. This increased energy causes the molecules to move more rapidly and collide with the walls of their container more frequently, which leads to an increase in pressure if the volume remains constant. This relationship is directly proportional, meaning when temperature increases, pressure also increases, as long as volume and the amount of gas remain unchanged.
To understand how changes in temperature affect gas pressure, consider the bicycle tire example. If the temperature inside the tire rises, the internal pressure will increase. This increase occurs because the air molecules inside the tire are moving more vigorously, thus pushing harder against the tire walls. For safety measures, it is crucial to monitor both temperature and pressure to prevent a tire burst, especially when environmental conditions change, like during hot weather.
Gas Law Calculations
The Ideal Gas Law is a fundamental equation in chemistry for understanding how gases behave under different conditions. The equation is \[PV = nRT\]where:
- \(P\) is the pressure of the gas.
- \(V\) is the volume it occupies.
- \(n\) is the number of moles of gas particles.
- \(R\) is the ideal gas constant \((0.0821 \text{ L atm/mol K})\).
- \(T\) is the temperature in Kelvin.
Thermodynamics in Chemistry
Thermodynamics is the study of energy and its transformations, and it plays a key role in understanding gas behavior through temperature and pressure analysis. According to the first law of thermodynamics, energy can neither be created nor destroyed, only transferred or transformed from one form to another. In gases, heating them increases their internal energy, mainly in the form of kinetic energy.
The Ideal Gas Law provides us with a macroscopic view, linking thermodynamics principles with observable changes like pressure and volume alterations. For example, when calculating the temperature that leads a tire to burst, we're applying thermodynamics to determine how heat energy affects gas molecules and how this change translates into macroscopic parameters like pressure. By deeply grasping these principles, one learns to predict how gases will react under various conditions, which can help in designing safer and more efficient chemical processes and products.
Other exercises in this chapter
Problem 59
You have a sample of helium gas at \(-33^{\circ} \mathrm{C}\) and you want to increase the rms speed of helium atoms by \(10.0 \% .\) To what temperature should
View solution Problem 60
If \(12.0 \mathrm{g}\) of \(\mathrm{O}_{2}\) is required to inflate a balloon to a certain size at \(27^{\circ} \mathrm{C},\) what mass of \(\mathrm{O}_{2}\) is
View solution Problem 63
The temperature of the atmosphere on Mars can be as high as \(27^{\circ} \mathrm{C}\) at the equator at noon, and the atmospheric pressure is about \(8 \mathrm{
View solution Problem 64
If you place 2.25 g of solid silicon in a \(6.56-\mathrm{L}\) flask that contains \(\mathrm{CH}_{3} \mathrm{Cl}\) with a pressure of \(585 \mathrm{mm} \mathrm{H
View solution