Problem 62
Question
A \(60.0-\mathrm{kg}\) skier starts from rest at the top of a ski slope 65.0 \(\mathrm{m}\) high. (a) If frictional forces do \(-10.5 \mathbf{k J}\) of work on her as she descends, how fast is she going at the bottom of the slope? (b) Now moving horizontally, the skier crosses a patch of soft snow, where \(\mu_{\mathrm{k}}=0.20\) If the patch is 82.0 \(\mathrm{m}\) wide and the average force of air resistance on the skier is 160 \(\mathrm{N}\) , how fast is she going after crossing the patch? (c) The skier hits a snowdrift and Penetrates 2.5 \(\mathrm{m}\) into it before coming to a stop. What is the average force exerted on her by the snowdrift as it stops her?
Step-by-Step Solution
Verified Answer
(a) 30.38 m/s; (b) 12.75 m/s; (c) 1950.25 N.
1Step 1: Determine Potential Energy at the Top
To find the skier's potential energy at the top of the slope, calculate using the formula for gravitational potential energy: \[ PE = m \cdot g \cdot h \]where \( m = 60.0 \, \text{kg} \), \( g = 9.81 \, \text{m/s}^2 \), and \( h = 65.0 \, \text{m} \). Substituting these values, we get:\[ PE = 60.0 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times 65.0 \, \text{m} = 38223 \, \text{J} \] or \( 38.2 \, \text{kJ} \).
2Step 2: Calculate Work Done by Friction
The frictional force does \(-10.5 \, \text{kJ}\) of work, which converts into a reduction in mechanical energy as the skier descends.
3Step 3: Apply Conservation of Energy to Find Speed at Bottom
The energy conversion can be calculated as follows:\[ KE_{bottom} = PE_{top} + W_{frictional} \]Where \( KE_{bottom} \) is the kinetic energy at the bottom of the slope and is given by:\[ KE_{bottom} = \frac{1}{2} m v^2 \]Thus:\[ \frac{1}{2} \times 60.0 \, \text{kg} \times v^2 = 38.2 \, \text{kJ} - 10.5 \, \text{kJ} \]\[ 30 v^2 = 27.7 \, \text{kJ} \]\[ v^2 = \frac{27700 \, \text{J}}{30} \approx 923.33 \]\[ v = \sqrt{923.33} \approx 30.38 \, \text{m/s} \]
4Step 4: Calculate Work Done Across the Snow Patch
Here, calculate the forces acting on the skier as she crosses the patch:- Friction force \( F_{fric} = \mu_k \times m \times g = 0.20 \times 60.0 \times 9.81 = 117.72 \, \text{N} \).- Air resistance \( F_{air} = 160 \, \text{N} \).The total work done against these forces is:\[ W = (F_{fric} + F_{air}) \times d = (117.72 + 160) \times 82.0 = 22842.64 \, \text{J} \].
5Step 5: Determine Final Velocity after Snow Patch
The work-energy principle tells us:\[ \Delta KE = W \]Thus:\[ \frac{1}{2} \times 60.0 \times (v_{after}^2 - v_{before}^2) = -22842.64 \]\[ 30 \times (v_{after}^2 - 923.33) = -22842.64 \]\[ v_{after}^2 = 923.33 - \frac{22842.64}{30} = 162.57 \]\[ v_{after} = \sqrt{162.57} \approx 12.75 \, \text{m/s} \]
6Step 6: Determine Force Exerted by the Snowdrift
Since the skier comes to a stop after penetrating the snowdrift, the kinetic energy is completely converted into work done by the snowdrift:\[ \Delta KE = -W \]\[ \frac{1}{2} \times 60.0 \times 12.75^2 = F_{snow} \times 2.5 \]\[ 4875.625 = F_{snow} \times 2.5 \]\[ F_{snow} = \frac{4875.625}{2.5} \approx 1950.25 \, \text{N} \]
Key Concepts
Work-Energy PrincipleKinetic EnergyPotential Energy
Work-Energy Principle
The Work-Energy Principle is like a bridge connecting the concepts of work and energy. It explains how the work done on an object affects its energy. In mechanics, this principle is incredibly useful to calculate changes in kinetic energy and potential energy. Work done on an object can change its energy, and this principle can be mathematically expressed as:
\[ \Delta KE = W \]
This means that the change in kinetic energy \( \Delta KE \) of a system is equal to the work \( W \) done on that system. This principle helps us understand various scenarios, such as when a skier moves down a ski slope. As the skier descends, both gravitational work and frictional work act upon the skier, affecting the total mechanical energy of the system.
\[ \Delta KE = W \]
This means that the change in kinetic energy \( \Delta KE \) of a system is equal to the work \( W \) done on that system. This principle helps us understand various scenarios, such as when a skier moves down a ski slope. As the skier descends, both gravitational work and frictional work act upon the skier, affecting the total mechanical energy of the system.
- If work is done on the system, like friction that does negative work, it reduces the system's energy.
- Conversely, positive work adds energy to the system.
Kinetic Energy
Kinetic Energy is the energy that an object possesses due to its motion. When discussing kinetic energy in mechanics, it is usually represented by the formula:
\[ KE = \frac{1}{2} mv^2 \]
Here, \( KE \) stands for Kinetic Energy, \( m \) is the mass of the object, and \( v \) is its velocity. Kinetic energy depends on both the mass and the velocity of the object, meaning that more massive objects or those moving quicker have greater kinetic energy.
Consider the scenario of a skier descending a slope. Initially, the skier starts from rest and has zero kinetic energy. As she moves downhill, her velocity increases due to gravity, and consequently, her kinetic energy also increases. However, factors such as friction can reduce this energy by doing work against the skier, slowing her down.
\[ KE = \frac{1}{2} mv^2 \]
Here, \( KE \) stands for Kinetic Energy, \( m \) is the mass of the object, and \( v \) is its velocity. Kinetic energy depends on both the mass and the velocity of the object, meaning that more massive objects or those moving quicker have greater kinetic energy.
Consider the scenario of a skier descending a slope. Initially, the skier starts from rest and has zero kinetic energy. As she moves downhill, her velocity increases due to gravity, and consequently, her kinetic energy also increases. However, factors such as friction can reduce this energy by doing work against the skier, slowing her down.
- At the bottom of the slope, her kinetic energy is influenced by the initial potential energy and the work done by friction.
- Kinetic energy variations allow us to calculate her speed, using the Work-Energy Principle.
Potential Energy
Potential Energy is the stored energy in an object due to its position or state. In the context of mechanics, gravitational potential energy is one of the most common forms, given by the expression:
\[ PE = mgh \]
where \( m \) is mass, \( g \) is the acceleration due to gravity, and \( h \) is height. This formula calculates the energy stored in an object raised above ground level. This type of energy is stored due to gravitational forces acting on the object.
In our skier example, the skier begins with a certain amount of gravitational potential energy at the top of the slope. This potential energy depends on her mass, the height of the slope, and gravity. As she descends, this stored energy converts into kinetic energy, causing her to accelerate.
\[ PE = mgh \]
where \( m \) is mass, \( g \) is the acceleration due to gravity, and \( h \) is height. This formula calculates the energy stored in an object raised above ground level. This type of energy is stored due to gravitational forces acting on the object.
In our skier example, the skier begins with a certain amount of gravitational potential energy at the top of the slope. This potential energy depends on her mass, the height of the slope, and gravity. As she descends, this stored energy converts into kinetic energy, causing her to accelerate.
- At the top of the slope, potential energy is at its maximum because of the great height.
- As she moves down, potential energy decreases, converting into kinetic energy.
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