Problem 62
Question
\(61-66\) Write the sum as a product. $$ \sin x-\sin 4 x $$
Step-by-Step Solution
Verified Answer
\( \sin x - \sin 4x = -2 \cos \left( \frac{5x}{2} \right) \sin \left( \frac{3x}{2} \right) \)
1Step 1: Identify the Trigonometric Identity
To transform a difference of sines into a product, we need to use a trigonometric identity. The identity is: \[ \sin A - \sin B = 2 \cos \left( \frac{A+B}{2} \right) \sin \left( \frac{A-B}{2} \right) \]
2Step 2: Assign Values for A and B
In the given expression \( \sin x - \sin 4x \), assign \( A = x \) and \( B = 4x \).
3Step 3: Calculate \(A+B\) and \(A-B\)
Find \( A+B \) and \( A-B \):\[ A + B = x + 4x = 5x \]\[ A - B = x - 4x = -3x \]
4Step 4: Plug Values into the Identity
Substitute \( A+B \) and \( A-B \) into the identity. This gives:\[ \sin x - \sin 4x = 2 \cos \left( \frac{5x}{2} \right) \sin \left( \frac{-3x}{2} \right) \]
5Step 5: Use Sin(-θ) = -Sin(θ) Property
Since the sine function is an odd function, \( \sin(-\theta) = -\sin(\theta) \). Apply this to simplify:\[ \sin x - \sin 4x = -2 \cos \left( \frac{5x}{2} \right) \sin \left( \frac{3x}{2} \right) \]
Key Concepts
Difference of SinesCosine FunctionSine Function
Difference of Sines
When dealing with the difference of sines, such as \(\sin x - \sin 4x\), a useful approach involves a trigonometric identity designed for this very scenario. The identity is
- \( \sin A - \sin B = 2 \cos \left( \frac{A+B}{2} \right) \sin \left( \frac{A-B}{2} \right) \)
- First, consider the terms \(A\) and \(B\) as the angles in the sine functions.
- In our example, \(A = x\) and \(B = 4x\).
- Next, calculate \(A + B\) and \(A - B\) to use in the identity.
- For \(\sin x - \sin 4x\), these would be \(5x\) and \(-3x\), respectively.
Cosine Function
The cosine function is a fundamental part of many trigonometric identities and calculations. In our identity for the difference of sines, the cosine function plays a crucial role:
- The identity uses \( \cos \left( \frac{A+B}{2} \right) \).
- In the expression \(\sin x - \sin 4x\), this translates to \( \cos \left( \frac{5x}{2} \right) \).
- It is an even function, meaning \( \cos(-\theta) = \cos(\theta) \).
- The cosine function represents the horizontal coordinate of a point on the unit circle.
Sine Function
The sine function often appears in identities such as the difference of sines, being an essential part of these trigonometric transformations. It is important to understand a few key properties:
- The sine function is an odd function, meaning \( \sin(-\theta) = -\sin(\theta) \).
- It relates to the vertical component of a point on the unit circle.
- When we calculated \( \sin \left( \frac{-3x}{2} \right) \), the result is transformed to \(-\sin \left( \frac{3x}{2} \right)\).
- This transforms the expression into \(-2 \cos \left( \frac{5x}{2} \right) \sin \left( \frac{3x}{2} \right) \).
Other exercises in this chapter
Problem 61
Let \(g(x)=\cos x .\) Show that \(\frac{g(x+h)-g(x)}{h}=-\cos x\left(\frac{1-\cos h}{h}\right)-\sin x\left(\frac{\sin h}{h}\right)\)
View solution Problem 62
\(57-62\) . Use a graphing device to find the solutions of the equation, correct to two decimal places. $$ \cos x=\frac{1}{2}\left(e^{x}+e^{-x}\right) $$
View solution Problem 62
Show that if \(\beta-\alpha=\pi / 2\) , then $$ \sin (x+\alpha)+\cos (x+\beta)=0 $$
View solution Problem 62
Verify the identity. $$ \frac{1+\sec ^{2} x}{1+\tan ^{2} x}=1+\cos ^{2} x $$
View solution