Problem 61
Question
Write the sum without using sigma notation. $$\sum_{k=1}^{4} k^{3}$$
Step-by-Step Solution
Verified Answer
1 + 8 + 27 + 64
1Step 1: Understand the Sigma Notation
The expression \( \sum_{k=1}^{4} k^{3} \) means that we need to calculate the sum of \( k^3 \) for each integer value of \( k \) from 1 to 4.
2Step 2: Compute Individual Terms
We will work out each term in the sequence separately:- When \( k = 1 \), \( k^3 = 1^3 = 1 \).- When \( k = 2 \), \( k^3 = 2^3 = 8 \).- When \( k = 3 \), \( k^3 = 3^3 = 27 \).- When \( k = 4 \), \( k^3 = 4^3 = 64 \).
3Step 3: Write Without Sigma
Replacing the sigma notation with its expanded form, we write the sum without the sigma notation: \(1 + 8 + 27 + 64\).
4Step 4: Calculate the Sum
We add the individual terms together: \(1 + 8 + 27 + 64 = 100\).
Key Concepts
Sum of CubesSeries ExpansionMathematical Notation
Sum of Cubes
The concept of the sum of cubes is intriguing and presents a powerful mathematical pattern. The expression you often encounter, like \( \sum_{k=1}^{n} k^3 \), represents the sum of cubes of integers starting from 1 to \( n \). Each term, \( k^3 \), is the cube of an integer value \( k \). In simple terms, it tells you to take a number, multiply it by itself twice (like squaring but with an extra step), and you have the cube. For example, if you cube 2, you get \( 2 \times 2 \times 2 = 8 \). So, to find \( \sum_{k=1}^{4} k^3 \), you compute \( 1^3 + 2^3 + 3^3 + 4^3 \), which gives you 100.
- 1 cubed is 1
- 2 cubed is 8
- 3 cubed is 27
- 4 cubed is 64
Series Expansion
Series expansion is a natural mathematical tool used to express functions or sequences in a form that reveals the sums of individual terms. When dealing with a series, like the sum of cubes, the process involves breaking down the sigma (\( \Sigma \)) notation into a sequence that involves the explicit addition of each term.
This concept is key when working with sigma notation to uncover what each element or stage of the sequence equates to. Consider this exercise: you start with the sigma notation \( \sum_{k=1}^{4} k^3 \). By expanding it, you display it as \( 1 + 8 + 27 + 64 \).
This concept is key when working with sigma notation to uncover what each element or stage of the sequence equates to. Consider this exercise: you start with the sigma notation \( \sum_{k=1}^{4} k^3 \). By expanding it, you display it as \( 1 + 8 + 27 + 64 \).
- The process moves from a compact sigma notation to a detailed and expanded view of the series.
- Each number represents a term generated from cubing integers sequentially.
- These integers span from the lower to the upper bounds specified in the notation, here from 1 to 4.
Mathematical Notation
Mathematical notation is the universal language of mathematics, encapsulating complex ideas succinctly and accurately. The use of symbols, like summation notation (\( \Sigma \)), turns lengthy processes into concise statements. Such notations are pivotal in simplifying and communicating intricate mathematical operations.
In this context, the notation \( \sum_{k=1}^{4} k^3 \) stands for the sum of cubes from 1 to 4. Breaking down the notation:
In this context, the notation \( \sum_{k=1}^{4} k^3 \) stands for the sum of cubes from 1 to 4. Breaking down the notation:
- The symbol \( \Sigma \) signifies summation.
- \( k \) is our index of summation, essentially a placeholder that takes on each integer value from 1 to 4.
- \( k^3 \) is the expression we evaluate for each \( k \).
Other exercises in this chapter
Problem 60
Use a graphing calculator to evaluate the sum. $$\sum_{n=1}^{100} \frac{(-1)^{n}}{n}$$
View solution Problem 61
Find the sum. $$\sum_{k=1}^{6} 5(-2)^{k-1}$$
View solution Problem 62
A partial sum of an arithmetic sequence is given. Find the sum. $$-10-9.9-9.8-\dots-0.1$$
View solution Problem 62
Find the sum. $$\sum_{k=1}^{6} 10(5)^{k-1}$$
View solution