Problem 61
Question
Verify the property. \(\bar{z}=z\) if and only if \(z\) is real.
Step-by-Step Solution
Verified Answer
\(\bar{z}=z\) means \(z\) is real because the imaginary part must be zero.
1Step 1: Define the Property
The property states that the complex conjugate of a complex number equals the complex number itself if and only if the number is real.
2Step 2: Express the Complex Number
A complex number \( z \) can be expressed as \( z = a + bi \), where \( a \) is the real part and \( b \) is the imaginary part.
3Step 3: Write the Complex Conjugate
The complex conjugate of \( z \), denoted by \( \bar{z} \), is \( a - bi \).
4Step 4: Set the Equality
Set the given equality \( \bar{z} = z \). This implies \( a - bi = a + bi \).
5Step 5: Compare Real and Imaginary Parts
For the equality \( a - bi = a + bi \) to hold, the imaginary parts must be equal: \(-bi = bi\). This simplifies to \(-b = b\).
6Step 6: Solve for the Imaginary Part
The equation \(-b = b\) implies that \( b = 0 \).
7Step 7: Conclude on the Nature of \(z\)
Since \( b = 0 \), the complex number \( z = a + bi\) reduces to \( z = a \). Therefore, \( z \) is real.
Key Concepts
Complex ConjugateReal NumbersImaginary Part
Complex Conjugate
The complex conjugate of a complex number is a core concept in mathematics, particularly useful in various fields like engineering and physics. If you have a complex number, say \( z = a + bi \), where \( a \) and \( b \) are real numbers, the complex conjugate of \( z \) is denoted as \( \bar{z} \) and is equal to \( a - bi \). This operation essentially "flips" the sign of the imaginary component while keeping the real part unchanged.
The significance of this operation lies in its properties:
The significance of this operation lies in its properties:
- If you multiply a complex number by its complex conjugate, you get a non-negative real number: \( z\bar{z} = a^2 + b^2 \).
- This can help in simplifying division of complex numbers by eliminating the imaginary part in the denominator.
- It is also used in determining whether results are consistent when dealing with complex numbers subject to various operations, as was demonstrated in the original exercise.
Real Numbers
Real numbers are foundational in mathematics and are defined as any number that can be located on the number line. These include both positive and negative integers, fractions, and irrational numbers. In relation to complex numbers, if the imaginary part is zero, a complex number reduces to just its real part, making it a real number.
Consider the equation \( z = a + bi \). If \( b = 0 \), then \( z = a \), where \( a \) belongs to the set of real numbers. This is significant when understanding when a complex number equals its complex conjugate: it happens when the number is purely real with no imaginary part.
Consider the equation \( z = a + bi \). If \( b = 0 \), then \( z = a \), where \( a \) belongs to the set of real numbers. This is significant when understanding when a complex number equals its complex conjugate: it happens when the number is purely real with no imaginary part.
- This property is crucial because it indicates that if a complex conjugate \( \bar{z} = z \), \( z \) must be entirely real.
- Real numbers are fundamental in both everyday math and advanced calculations, underpinning countless mathematical concepts.
Imaginary Part
In complex numbers, the imaginary part is the component that involves the imaginary unit \( i \), where \( i \) is defined as \( \sqrt{-1} \). This is what distinguishes complex numbers from real numbers. For a complex number \( z = a + bi \), \( b \) is the coefficient of the imaginary part.
Managing the imaginary part is crucial when analyzing complex numbers:
Managing the imaginary part is crucial when analyzing complex numbers:
- When you have an expression of the form \( a + bi \), \( b \) must be zero for \( z \) to equal its complex conjugate.
- In the provided exercise, setting \( \bar{z} = z \) led to the realization that the imaginary part must cancel out, requiring \( b = 0 \).
- This cancellation results in a number that is purely real, as the imaginary component disappears.
Other exercises in this chapter
Problem 61
Solve for the specified variable. $$P+N=\frac{C+2}{C} \text { for } C$$
View solution Problem 61
Rationalize the denominator. $$\frac{\sqrt{t}+5}{\sqrt{t}-5}$$
View solution Problem 62
Simplify the expression, and rationalize the denominator when appropriate. $$\sqrt{\frac{1}{7}}$$
View solution Problem 62
The formula occurs in the indicated application. Solve for the specified variable. \(s=\frac{1}{2} g t^{2}+v_{0} t\) for \(t \quad\) (distance an object falls)
View solution