Problem 61
Question
Use the determinant to find the inverse of \(A\) $$ A=\left[\begin{array}{rr} -1 & 4 \\ 5 & 1 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The inverse of matrix \( A \) is \( \begin{bmatrix} -\frac{1}{21} & \frac{4}{21} \\ \frac{5}{21} & \frac{1}{21} \end{bmatrix} \).
1Step 1: Calculate the Determinant of Matrix A
The determinant of a 2x2 matrix \( A = \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is calculated using the formula \( \text{det}(A) = ad - bc \). For our matrix \( A = \begin{bmatrix} -1 & 4 \ 5 & 1 \end{bmatrix} \), we have \( a = -1 \), \( b = 4 \), \( c = 5 \), \( d = 1 \). Substituting these values into the formula, we get \( \text{det}(A) = (-1)(1) - (4)(5) = -1 - 20 = -21 \).
2Step 2: Check if the Matrix is Invertible
A square matrix is invertible if and only if its determinant is non-zero. Since the determinant of matrix \( A \) is \( -21 \), which is non-zero, the matrix is invertible.
3Step 3: Find the Adjugate of Matrix A
The adjugate of a 2x2 matrix \( A = \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is given by \( \text{adj}(A) = \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \). Substituting the values from matrix \( A = \begin{bmatrix} -1 & 4 \ 5 & 1 \end{bmatrix} \), we find \( \text{adj}(A) = \begin{bmatrix} 1 & -4 \ -5 & -1 \end{bmatrix} \).
4Step 4: Calculate the Inverse of Matrix A
The inverse of a matrix \( A \) is given by \( A^{-1} = \frac{1}{\text{det}(A)} \times \text{adj}(A) \). From Step 1, we found that \( \text{det}(A) = -21 \) and from Step 3, \( \text{adj}(A) = \begin{bmatrix} 1 & -4 \ -5 & -1 \end{bmatrix} \). Therefore, \( A^{-1} = \frac{1}{-21} \times \begin{bmatrix} 1 & -4 \ -5 & -1 \end{bmatrix} = \begin{bmatrix} \frac{1}{-21} & \frac{-4}{-21} \ \frac{-5}{-21} & \frac{-1}{-21} \end{bmatrix} \). Simplifying, \( A^{-1} = \begin{bmatrix} -\frac{1}{21} & \frac{4}{21} \ \frac{5}{21} & \frac{1}{21} \end{bmatrix} \).
Key Concepts
Determinant CalculationAdjugate MatrixInvertible Matrix Criteria
Determinant Calculation
The determinant of a matrix plays a crucial role in various aspects of linear algebra, including determining whether a matrix is invertible. For a 2x2 matrix like \[ A = \begin{bmatrix} a & b \ c & d \end{bmatrix}, \]the determinant is calculated using the formula:\[ \text{det}(A) = ad - bc. \]In the example matrix \(A = \begin{bmatrix} -1 & 4 \ 5 & 1 \end{bmatrix},\)substitute the values where \(a = -1\), \(b = 4\), \(c = 5\), and \(d = 1\).
This gives us:\[ \text{det}(A) = (-1)(1) - (4)(5) = -1 - 20 = -21. \]The determinant not only helps find the inverse but also checks if a matrix is invertible. A non-zero determinant indicates the matrix can indeed be inverted, as shown here.
This gives us:\[ \text{det}(A) = (-1)(1) - (4)(5) = -1 - 20 = -21. \]The determinant not only helps find the inverse but also checks if a matrix is invertible. A non-zero determinant indicates the matrix can indeed be inverted, as shown here.
Adjugate Matrix
The adjugate of a 2x2 matrix is used when finding the matrix inverse, especially in manual calculations. It's derived by swapping the diagonal elements and changing the signs of the off-diagonal elements. For a general 2x2 matrix:\[ A = \begin{bmatrix} a & b \ c & d \end{bmatrix}, \]the adjugate is:\[ \text{adj}(A) = \begin{bmatrix} d & -b \ -c & a \end{bmatrix}. \]Applying this to our specific example matrix \(A = \begin{bmatrix} -1 & 4 \ 5 & 1 \end{bmatrix}\),we find the adjugate matrix:\[ \text{adj}(A) = \begin{bmatrix} 1 & -4 \ -5 & -1 \end{bmatrix}. \]Using the adjugate is a key step in ultimately determining the inverse of a matrix.
Invertible Matrix Criteria
Understanding when a matrix is invertible is fundamental in linear algebra. A square matrix is said to be invertible—or non-singular—if its determinant is not equal to zero. This criterion ensures that a unique inverse matrix exists. The inverse is utilized in solving linear equations and transforming systems.
For our example matrix \(A = \begin{bmatrix} -1 & 4 \ 5 & 1 \end{bmatrix}\),we calculated that \(\text{det}(A) = -21\),which is non-zero. This confirms that matrix \(A\) is indeed invertible.
An invertible matrix allows for meaningful computations such as finding solutions to linear systems, which is often represented as\[ A \mathbf{x} = \mathbf{b}. \]Knowing your matrix is invertible gives the green light for calculating other important characteristics in linear transformations.
For our example matrix \(A = \begin{bmatrix} -1 & 4 \ 5 & 1 \end{bmatrix}\),we calculated that \(\text{det}(A) = -21\),which is non-zero. This confirms that matrix \(A\) is indeed invertible.
An invertible matrix allows for meaningful computations such as finding solutions to linear systems, which is often represented as\[ A \mathbf{x} = \mathbf{b}. \]Knowing your matrix is invertible gives the green light for calculating other important characteristics in linear transformations.
Other exercises in this chapter
Problem 60
Find the parametric equation of the line in \(x-\) \(y-z\) space that goes through the given points. \((2,0,-3)\) and \((4,1,0)\)
View solution Problem 60
$$ \begin{array}{l} \text { In Problems , find the eigenvalues } \lambda_{1} \text { and } \lambda_{2} \text { for each matrix }\\\ A \end{array} $$ $$ \text {
View solution Problem 61
Find the parametric equation of the line in \(x-\) \(y-z\) space that goes through the given points. \((2,-3,1)\) and \((-5,2,1)\)
View solution Problem 61
Find the eigenvalues \(\lambda_{1}\) and \(\lambda_{2}\) for $$ A=\left[\begin{array}{ll} a & 0 \\ c & b \end{array}\right] $$
View solution