Problem 61
Question
Two beakers each contain 1 L of water. Then \(0.1\) mole of HCl gas is dissolved in one beaker, and \(0.1\) mole of HF gas is dissolved in the other beaker. The HCl solution causes a light bulb to glow intensely, and the HF solution causes the same bulb to glow dimly. Explain these observations.
Step-by-Step Solution
Verified Answer
The difference in the light bulb's glow intensity can be explained by the difference in the dissociation characteristics of strong and weak acids. HCl (a strong acid) completely dissociates in water, resulting in a higher concentration of H+ ions and a more conductive solution, causing the light bulb to glow intensely. In contrast, HF (a weak acid) only partially dissociates, producing fewer H+ ions and a less conductive solution, causing the light bulb to glow dimly.
1Step 1: The problem statement involves two acids, HCl and HF, dissolved in water. HCl is a strong acid while HF is a weak acid. The difference between a strong and a weak acid lies in how they dissociate (break down) into ions when they dissolve in water. This will be important to understand the behavior of the two solutions and the subsequent impact on the light bulb.
#Step 2: Understand the concept of strong acids and their dissociation#
2Step 2: Strong acids like HCl completely dissociate in water into their constituent ions. For example, when HCl is dissolved in water, it releases hydrogen ions (H+) and chloride ions (Cl-): \[ HCl_{(aq)} \rightarrow H^+_{(aq)} + Cl^-_{(aq)} \] The increase in the concentration of H+ ions causes the solution to be highly conductive, as the ions can move freely and carry an electric charge. This conductivity allows the solution to transmit electricity and causes the light bulb to glow intensely.
#Step 3: Understand the concept of weak acids and their dissociation#
3Step 3: Weak acids, like HF, do not fully dissociate in water. Instead, they partially dissociate: \[ HF_{(aq)} \rightleftharpoons H^+_{(aq)} + F^-_{(aq)} \] In this equilibrium, there are fewer H+ ions produced than in the case of a strong acid like HCl. This means that the solution is less conductive as there are fewer ions to carry the electric charge. This results in the light bulb glowing dimly when brought into contact with the HF solution.
#Step 4: Relate the conductivity to the light bulb intensity#
4Step 4: Both the HCl and HF solutions have the ability to conduct electricity due to the presence of ions, which is the reason why the light bulb glows in both cases. However, the difference in the glow's intensity can be attributed to the higher concentration of H+ ions in the HCl solution compared to the HF solution. The higher concentration of ions in the HCl solution results in higher conductivity and therefore a more intense glow from the light bulb. On the other hand, the lower concentration of ions in the HF solution leads to lower conductivity, causing the light bulb to glow dimly.
In conclusion, the difference in the intensity of the light bulb's glow in HCl and HF solutions can be explained by the difference in the dissociation characteristics of strong and weak acids. The higher conductivity of the HCl solution due to its greater H+ ion concentration leads to a more intense glow, while the lower conductivity of the HF solution causes the light bulb to glow dimly.
Key Concepts
Strong AcidsWeak AcidsConductivity
Strong Acids
When we talk about strong acids, we refer to their powerful ability to dissociate in water. For instance, hydrochloric acid (HCl) is a perfect example. It completely breaks down into its individual ions, hydrogen ions (H⁺) and chloride ions (Cl⁻), when it dissolves in water.
This means that in a solution of HCl, you'll find a high concentration of H⁺ ions floating freely.
This means that in a solution of HCl, you'll find a high concentration of H⁺ ions floating freely.
- These ions are crucial as they can move around easily and carry a charge, which is why such solutions conduct electricity very well.
- In a typical experiment, like dissolving HCl in water and connecting it with a circuit, the high conductivity will make a light bulb glow brightly.
- This phenomenon occurs because the freely moving ions facilitate the flow of electric current efficiently.
Weak Acids
Weak acids, in contrast, do not fully dissociate in water. Hydrofluoric acid (HF) is a classic example of a weak acid. Instead of breaking all its molecules into ions, only a fraction of HF molecules release hydrogen ions (H⁺) when dissolved in water.
- This partial dissociation creates an equilibrium between the non-dissociated HF molecules and the ions produced.
- Compared to strong acids, weak acids produce fewer H⁺ ions.
- As a result, the lower concentration of ions leads to a solution with reduced conductivity.
Conductivity
Conductivity in a solution essentially describes how well it can transmit electric signals. The presence and concentration of charged particles, like ions, dictate this behavior. Strong acids such as HCl lead to high conductivity due to their complete ionization that releases more ions.
On the other hand, weak acids like HF result in lower conductivity because fewer ions are released upon partial ionization.
On the other hand, weak acids like HF result in lower conductivity because fewer ions are released upon partial ionization.
- High concentration of ions means higher conductivity, leading to strong reactions observable through devices like glowing bulbs or meters.
- Conversely, lower ion concentration corresponds with weaker conductivity, showing milder reactions.
Other exercises in this chapter
Problem 58
Write a balanced equation to show what happens when \(\mathrm{CaBr}_{2}\) dissolves in water. Use the \((a q)\) symbol when necessary.
View solution Problem 60
What do we mean by saying that some molecular compounds dissolve in water and also dissociate? Give an example of such a compound.
View solution Problem 63
To which side does the dissociation equilibrium lie for a strong electrolyte? For a weak electrolyte?
View solution Problem 65
Consider the three molecular compounds \(\mathrm{HCl}\), \(\mathrm{CH}_{3} \mathrm{COOH}\), and \(\mathrm{H}_{2} \mathrm{SO}_{4} \cdot\) (a) When they dissolve
View solution