Problem 61
Question
The value of the determinant \(\left|\begin{array}{ccc}-b c & b^{2}+b c & c^{2}+b c \\ a^{2}+a c & -a c & c^{2}+a c \\ a^{2}+a b & b^{2}+a b & -a b\end{array}\right|\) (A) \(\left(a^{2}+b^{2}+c^{2}\right)^{3}\) (B) \((a b+b c+c a)^{3}\) (C) \(\left(a^{2}+b^{2}+c^{2}\right)(a b+b c+c a)^{2}\) (D) None of these
Step-by-Step Solution
Verified Answer
The determinant of the matrix is zero.
1Step 1: Analyze the Matrix Structure
The matrix is a 3x3 square matrix, where each element is a combination of terms involving the variables \(a\), \(b\), and \(c\). We will use properties of determinants to simplify this expression and identify patterns or symmetries.
2Step 2: Use Properties of Determinants
One property we can exploit is that if two rows (or columns) of a determinant are identical or proportional, the determinant is zero. Notice the symmetry and shared terms across rows of the matrix.
3Step 3: Apply Transformations to Simplify
Let's try adding columns as an attempt to find zero-column combinations or constant multiples of columns, such as adding the first column to the others. Also, consider simplifying the expression by partial factoring.
4Step 4: Check for Common Factor or Matrix Row Zeros
Perform calculations or factorizations to see if repeated terms cancel out or help recognize a zero-determinant due to linear dependence. Verifying linear dependence can immediately show that the determinant is zero.
5Step 5: Confirm the Determinant Calculation
Through applying the property of linear dependence of rows, where row sums and others indicate linear dependence, confirm again the determinant value. Recalculate any direct expressions felt necessary and be sure linear dependence implies determinant zero.
Key Concepts
Properties of DeterminantsLinear DependenceMatrix Transformations
Properties of Determinants
Determinants have several interesting properties that can greatly simplify calculations. Understanding these properties helps to quickly evaluate or even eliminate potential values in determinant problems, especially with larger matrices. A key property is that if any two rows (or columns) of the matrix are identical or proportional, the determinant of that matrix is zero. This property is useful in the exercise above. By looking for identical or proportional elements across rows or columns, we can simplify our work.
Another property is that certain operations on rows and columns, such as adding a multiple of one row to another, do not change the value of the determinant. This can help to simplify the matrix into a form that is easier to work with. Taking advantage of these properties not only saves time but makes solving complicated determinant problems much more manageable.
Moreover, the swapping of two rows or columns results in changing the sign of the determinant. Understanding these basic concepts provides insight into managing complex determinants, ensuring a more efficient and strategic approach to problem solving.
Another property is that certain operations on rows and columns, such as adding a multiple of one row to another, do not change the value of the determinant. This can help to simplify the matrix into a form that is easier to work with. Taking advantage of these properties not only saves time but makes solving complicated determinant problems much more manageable.
Moreover, the swapping of two rows or columns results in changing the sign of the determinant. Understanding these basic concepts provides insight into managing complex determinants, ensuring a more efficient and strategic approach to problem solving.
Linear Dependence
Linear dependence is a fundamental concept in linear algebra. It helps determine whether a set of vectors are related or independent in a matrix context. In the context of determinants, if the rows or columns of a matrix are linearly dependent, then the determinant of that matrix is zero. This is because linear dependence implies there is no unique solution or meaningful volume associated with the matrix.
When analyzing a matrix for linear dependence, one looks to see if one row is a linear combination of others. For example, in a 3x3 matrix like the one in the original exercise, if the sums of any two rows or columns create the third, it suggests linear dependence.
Utilizing this concept can make matrix manipulation much easier and is particularly useful in proving that a determinant is zero without having to go through exhaustive calculations. Recognizing linear patterns means identifying inherent redundancies and eliminating unnecessary complexity in matrix evaluations.
When analyzing a matrix for linear dependence, one looks to see if one row is a linear combination of others. For example, in a 3x3 matrix like the one in the original exercise, if the sums of any two rows or columns create the third, it suggests linear dependence.
Utilizing this concept can make matrix manipulation much easier and is particularly useful in proving that a determinant is zero without having to go through exhaustive calculations. Recognizing linear patterns means identifying inherent redundancies and eliminating unnecessary complexity in matrix evaluations.
Matrix Transformations
Matrix transformations involve operations like rotation, scaling, and translation applied to matrices. These operations are crucial for simplifying matrices to more workable forms. Understanding how these transformations affect determinants is essential.
In the context of determinant calculations, transformations such as row reduction through row addition or factoring out common elements can simplify evaluating the determinant. For instance, adding multiples of one column to another does not change the determinant's value, but it can make working with it much easier.
In transformation terms, reducing a matrix can help reveal symmetric structures or zero out elements that contribute to simpler determinant calculations. By employing techniques to streamline the matrix, it can often uncover linear dependencies or other properties that indicate a determinant might be zero, as shown in the exercise solution. This approach reflects a strategic maneuver in determining the determinant's value efficiently.
In the context of determinant calculations, transformations such as row reduction through row addition or factoring out common elements can simplify evaluating the determinant. For instance, adding multiples of one column to another does not change the determinant's value, but it can make working with it much easier.
In transformation terms, reducing a matrix can help reveal symmetric structures or zero out elements that contribute to simpler determinant calculations. By employing techniques to streamline the matrix, it can often uncover linear dependencies or other properties that indicate a determinant might be zero, as shown in the exercise solution. This approach reflects a strategic maneuver in determining the determinant's value efficiently.
Other exercises in this chapter
Problem 59
The value of the determinant is \(\left|\begin{array}{ccc}\beta \gamma & \beta \gamma^{\prime}+\beta^{\prime} \gamma & \beta^{\prime} \gamma^{\prime} \\\ \gamma
View solution Problem 60
If \(a \neq 0, a \neq 1\) and \(\left|\begin{array}{ccc}x+1 & x & x \\ x & x+a & x \\ x & x & x+a^{2}\end{array}\right|=a^{3}+f(x) \cdot a\left(a^{2}+a+1\right)
View solution Problem 62
If \(\left|\begin{array}{ccc}x+a^{2} & a b & a c \\ a b & x+b^{2} & b c \\ a c & b c & x+c^{2}\end{array}\right|=0\) and \(x(\neq 0) \in R\) then \(x\) is equal
View solution Problem 63
The values of \(m\) for which the system of equations \(3 x+m y=m\) and \(2 x-5 y=20\) has a solution satisfying the condition \(x>0, y>0\), are (A) \(m \in\lef
View solution