Problem 61
Question
The profit function, in thousands of dollars, for a company that makes graphing calculators is \(\mathrm{P}(x)=-5 x^{2}+5,400 x-106,000\) where \(x\) is the number of calculators sold in the millions. a. Graph the profit function \(\mathrm{P}(x)\) b. How many calculators must the company sell in order to make a profit?
Step-by-Step Solution
Verified Answer
The company must sell more than 20.633 million calculators to make a profit.
1Step 1: Understanding the Profit Function
The profit function is given as \( P(x) = -5x^2 + 5400x - 106000 \). This is a quadratic function of the form \( ax^2 + bx + c \), where \( a = -5 \), \( b = 5400 \), and \( c = -106000 \). It represents the profit, in thousands of dollars, based on the number of calculators sold, where \(x\) is in millions.
2Step 2: Graphing the Profit Function
To graph this function, identify the vertex and intercepts. Since this is a downward-opening parabola (\( a < 0 \)), the vertex will be the maximum point. The vertex \((h, k)\) is found using \( h = -\frac{b}{2a} \), which gives \( h = -\frac{5400}{2 \times -5} = 540 \). Substitute \( x = 0 \) to find the y-intercept, \( P(0) = -106000 \), indicating when no calculators are sold, there is a loss of $106,000. Plot the function by calculating additional points or using a graphing tool.
3Step 3: Finding the Break-Even Point
The company makes a profit when \( P(x) > 0 \), so set \( -5x^2 + 5400x - 106000 > 0 \). Solve \( -5x^2 + 5400x - 106000 = 0 \) using the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Substitute \( a = -5 \), \( b = 5400 \), and \( c = -106000 \) to find the roots, which are the break-even points.
4Step 4: Solving for Break-Even Points
Calculate the discriminant: \( \Delta = b^2 - 4ac = 5400^2 - 4 \times (-5) \times (-106000) = 29160000 - 2120000 = 27040000 \). Use the quadratic formula to find \( x = \frac{-5400 \pm \sqrt{27040000}}{-10} \), which simplifies to \( x \approx 20.633 \) and \( x \approx 1029.367 \). This means the company must sell between approximately 20.633 million and 1029.367 million calculators to make a profit.
Key Concepts
Profit FunctionGraphing Quadratic EquationsBreak-Even AnalysisVertex of a Parabola
Profit Function
The profit function is a mathematical equation that calculates the profit a company earns based on various factors. For the company producing graphing calculators, the profit function is given as \( P(x) = -5x^2 + 5400x - 106000 \). This specific equation tells us:
- The term \( -5x^2 \) indicates a downward-opening parabola, representing a reduction in profit with every additional increase in the sales number.
- The linear term \( 5400x \) shows the increase in profit per calculator sold, while the constant \( -106000 \) depicts an initial loss when no calculators are sold. This is because of fixed costs or initial investments before any calculators are sold.
Graphing Quadratic Equations
Graphing quadratic equations involves plotting the curve that the equation represents on a coordinate plane. In our case, we are dealing with a quadratic function \( P(x) = -5x^2 + 5400x - 106000 \), which forms a parabola.To graph this equation properly:
- Identify key features like intercepts. The y-intercept is where the graph meets the y-axis, found by setting \( x = 0 \), giving us \( P(0) = -106000 \).
- The parabola's vertex is another critical point. It is found using the formula \( h = -\frac{b}{2a} \). For our equation, \( h = 540 \). This indicates the point of maximum profit as the parabola opens downwards.
- Using a graphing tool, plot this vertex to visualize how the profit changes over different sales volumes. Use additional points to define the shape of the parabola if necessary.
Break-Even Analysis
Break-even analysis is a method used to determine when an investment will start generating profit. For the graphing calculator company, the break-even point is the sales volume where profit starts happening, represented by \( P(x) > 0 \).Expanding on our function:
- Set the profit equation to zero: \( -5x^2 + 5400x - 106000 = 0 \).
- Apply the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) to find the values of \( x \), which are the solutions to when the profit is zero. These solutions are the break-even points.
- The discriminant was calculated as \( \Delta = 27040000 \), and solved \( x \) values are approximately 20.633 million and 1029.367 million calculators sold.
Vertex of a Parabola
The vertex of a parabola is a pivotal point that gives the maximum or minimum value of the quadratic function, depending on the function's orientation. In our downward-opening parabola \( P(x) = -5x^2 + 5400x - 106000 \), the vertex represents the point of maximum profit.How to find the vertex:
- Utilize the formula \( h = -\frac{b}{2a} \) to find the x-coordinate of the vertex. For this profit function, \( h = 540 \), meaning it occurs when 540 million calculators are sold.
- Substitute \( x = 540 \) back into the profit equation to find the maximum profit value, \( k = P(540) \). This gives the highest profit point.
Other exercises in this chapter
Problem 59
In \(46-60,\) write each quotient in \(a+b i\) form. $$ \frac{3 i}{\pi+\frac{1}{2} i} $$
View solution Problem 60
In \(46-60,\) write each quotient in \(a+b i\) form. $$ \frac{\frac{1}{7}+i}{\frac{5}{i}} $$
View solution Problem 61
Impedance is the resistance to the flow of current in an electric circuit measured in ohms. The impedance, \(Z,\) in a circuit is found by using the formula \(Z
View solution Problem 62
Find the current that will flow when \(V=1.6-0.3 i\) volts and \(Z=1.5+8 i\) ohms using the formula \(Z=\frac{V}{I} .\)
View solution