Problem 61
Question
Suppose that \(f^{\prime}(x) \leq 1\) for \(1 \leq x \leq 4 .\) Show that \(f(4)-\) \(f(1) \leq 3 .\)
Step-by-Step Solution
Verified Answer
The inequality is shown by applying the Mean Value Theorem: \(f(4)-f(1) \leq 3\).
1Step 1: Understand the Given Information
We are given that the derivative of the function, \(f'(x)\), is less than or equal to 1 for all \(x\) in the interval \([1, 4]\). This implies that the rate of change of the function \(f(x)\) does not exceed 1 at any point within this interval.
2Step 2: Interpret the Derivative Information
The derivative \(f'(x)\) being \(\leq 1\) means that the function \(f(x)\) is non-decreasing at a rate not faster than 1 unit change in \(f\) for 1 unit change in \(x\). This forms the fundamental basis for the Mean Value Theorem application.
3Step 3: Apply the Mean Value Theorem
The Mean Value Theorem states that there exists at least one \(c\) in \((1, 4)\) such that:\[f'(c) = \frac{f(4) - f(1)}{4 - 1}\]Given \(f'(c) \leq 1\), substitute to get:\[\frac{f(4) - f(1)}{3} \leq 1\]
4Step 4: Solve the Inequality
Multiply both sides of the inequality \(\frac{f(4) - f(1)}{3} \leq 1\) by 3 to isolate the expression for \(f(4) - f(1)\):\[f(4) - f(1) \leq 3\]This proves that the change in the function values over the interval \([1, 4]\) is at most 3.
Key Concepts
DerivativeRate of ChangeInequalityNon-decreasing Function
Derivative
The concept of a derivative is fundamental in calculus and represents the idea of instantaneous rate of change. In the context of the function provided, the derivative is expressed as \( f'(x) \), which tells us how the function \( f(x) \) changes at any point \( x \). When we say \( f'(x) \leq 1 \) within an interval, it implies that for every unit increase in \( x \), the change in \( f(x) \) is at most 1 unit. This is crucial for understanding the function's behavior over any segment.
- The derivative essentially measures the slope of the tangent line to the function at any given point.
- It provides insights into whether the function is increasing or decreasing within a particular range.
- If the derivative remains constant over an interval, the graph of the function is a straight line within that interval.
Rate of Change
The rate of change is closely related to the derivative and is a measure of how one quantity changes with respect to another. In this exercise, the rate of change is defined by the derivative \( f'(x) \), which is not greater than 1.This means:
- For every 1 unit increase in \( x \), \( f(x) \) will increase by no more than 1 unit.
- The function changes smoothly without sudden spikes or drops.
- It allows us to predict and understand the behavior of the function over an interval by knowing that the change is bounded.
Inequality
Inequalities are mathematical expressions used to compare two values. In the context of this problem, we worked with the inequality \( \frac{f(4) - f(1)}{3} \leq 1 \).Inequalities help in setting up constraints:
- They tell us the range within which a particular expression or function's value lies.
- For \( f(x) \), the inequality ensures that \( f(4) - f(1) \leq 3 \).
- This gives us a ceiling for the function's growth over the specified interval, allowing bounded estimation of the function values from start to end of the interval.
Non-decreasing Function
A non-decreasing function is a function where, as \( x \) increases, \( f(x) \) does not decrease. In the provided interval \([1, 4]\), knowing the derivative \( f'(x) \leq 1 \) doesn't just imply it is non-decreasing but also gives the rate of non-decrease.This characteristic of the function is significant because:
- It assures us that as \( x \) moves from 1 to 4, \( f(x) \) will not fall, ensuring at least a constant or increasing trend.
- Combined with the derivative information, it informs us about the maximum possible increase over the interval.
- Non-decreasing functions are typically used in real-world applications where a consistent or growing rate is expected, such as in population growth, cumulative data patterns, etc.
Other exercises in this chapter
Problem 61
You are to construct an open rectangular box with a square base and a volume of 48 \(\mathrm{ft}^{3} .\) If material for the bottom costs \(\ 6 / \mathrm{ft}^{2
View solution Problem 61
In Exercises \(61-62,\) show that the function has neither an absolute minimum nor an absolute maximum on its natural domain. $$ y=x^{11}+x^{3}+x-5 $$
View solution Problem 62
In Exercises \(61-62,\) show that the function has neither an absolute minimum nor an absolute maximum on its natural domain. $$ y=3 x+\tan x $$
View solution Problem 62
The graph of \(f^{\prime}\) is given. Assume that \(f\) is continuous and determine the \(x\) -values corresponding to local minima and local maxima.
View solution