Problem 61
Question
Solve for the specified variable or expression. $$ S n=(n-2) 180 \text { for } n $$
Step-by-Step Solution
Verified Answer
The solution for \( n \) is \( n = \frac{S_n + 360}{180} \).
1Step 1: Isolate the terms with the variable n
The given equation is \( S_n = (n-2) \times 180 \). Begin by expanding and simplifying to make it easier to solve for \( n \). Isolate the term involving \( n \), so write it as \( S_n = 180n - 360 \).
2Step 2: Move constants to the other side
Add 360 to both sides of the equation to get rid of the constant on the right. This results in \( S_n + 360 = 180n \).
3Step 3: Solve for n
Finally, to solve for \( n \), divide both sides of the equation by 180: \[ n = \frac{S_n + 360}{180}. \] This gives the expression for \( n \) in terms of \( S_n \).
Key Concepts
Equation SolvingVariables in AlgebraIsolation of Variables
Equation Solving
Equation solving is like unlocking a mystery. It's the process of finding the value of a variable that makes a mathematical sentence true. In algebra, this often means getting the variable on one side of the equation by itself. For example, when faced with an equation like \( S_n = (n-2) \times 180 \), the goal is to figure out what \( n \) is. To solve it:
- Start by identifying the equation you need to work with.
- Next, perform operations that simplify the equation step by step.
- Finally, isolate the variable and solve for it.
Variables in Algebra
Variables are like placeholders in algebra. They stand for unknown values and are usually represented by letters such as \( n, x, y \) or any other letter. A major part of understanding algebra is knowing how these variables interact with numbers and operations.In the equation \( S_n = (n-2) \times 180 \):
- \( S_n \) is a placeholder for a specific number that depends on \( n \).
- The \( n \) in the equation represents the number we are trying to solve.
Isolation of Variables
The isolation of variables is a key technique in algebra. It involves rearranging an equation to get a variable by itself on one side of the equation, making it simpler to find its value. This technique is crucial for solving equations efficiently.In our example, \( S_n = 180n - 360 \):
- The term \( 180n \) is separated from \( -360 \) by adding 360 to both sides, keeping the equation balanced.
- Once constants are moved, we isolate \( n \) by dividing the whole equation by 180.
Other exercises in this chapter
Problem 60
Solve each inequality. Write the solution set in interval notation and then graph it. $$ -2 x+6 \geq 16 $$
View solution Problem 61
Find \(h(5)\) and \(h(-2) .\) See Example 4. $$ h(x)=\frac{1}{x+3} $$
View solution Problem 61
Factor. \((a-b)^{3}+27\)
View solution Problem 61
Solve each compound inequality, if possible. Graph the solution set (if one exists) and write it using interval notation. $$ \frac{4.5 x-12}{2}-3(x-1.4) $$
View solution