Problem 61
Question
Solve each absolute value equation or indicate the equation has no solution. $$ |x-2|=7 $$
Step-by-Step Solution
Verified Answer
The solutions for the equation are \( x = 9 \) and \( x = -5 \).
1Step 1: Investigate the first scenario (x - 2 = 7)
Start solving the equation considering positive \( x \). Here, \( x - 2 \) is equal to 7. That being, an algebraic manipulation results in the value of \( x = 7 + 2 \), which gives \( x = 9 \).
2Step 2: Investigate the second case (x - 2 = -7)
Now, consider \( x - 2 \) is equal to -7. Manipulating the equation algebraically, the value of \( x = -7 + 2 \), which solves to \( x = -5 \).
3Step 3: Summarize the solutions
Having taken into account the two possible cases given the properties of absolute values, it's concluded that the solutions for the equation \( |x-2|=7 \) are \( x = 9 \) and \( x = -5 \).
Key Concepts
Algebraic ManipulationSolution of EquationsProperties of Absolute Values
Algebraic Manipulation
When solving absolute value equations like \( |x-2|=7 \), algebraic manipulation is a valuable tool. This process involves rearranging and simplifying parts of the equation to isolate the variable of interest—in our case, \( x \). To effectively apply algebraic manipulation, one must understand the order of operations and the balance between both sides of the equation.
- Consider \( |x-2| \) like any other algebraic expression. Initially, ignore the absolute value and solve the equation as though it were \( x-2=7 \). This gives us one possible value of \( x \) after moving the 2 to the other side of the equation.
- The second step is to acknowledge the unique principle of absolute values, which can also be negative and still satisfy the equation. So, we solve \( x-2=-7 \) as well, providing us with another valid solution for \( x \).
Solution of Equations
The process of finding the solution of equations, especially absolute value equations, requires a careful approach that deals with both the algebraic structure and the specific properties of the functions involved.
For an absolute value equation like \( |x-2|=7 \), the solution is not immediately apparent. Here’s how we approach it:
For an absolute value equation like \( |x-2|=7 \), the solution is not immediately apparent. Here’s how we approach it:
- Separate the equation into two scenarios based on the definition of absolute value. This yields the equations \( x-2=7 \) and \( x-2=-7 \).
- Solve each resulting equation. The solution to the first is \( x=9 \) and the second is \( x=-5 \).
- Verifying each solution by substituting it back into the original equation will confirm that both solutions are correct.
Properties of Absolute Values
Understanding the properties of absolute values is crucial in solving equations that include absolute value expressions. An absolute value measures the distance between a number and zero on the number line, regardless of direction. This property can lead to two different mathematical scenarios, hence why the solution to an absolute value equation can result in two numerical values.
Here's an illustration:
Here's an illustration:
- For the equation \( |x-2|=7 \), \( x-2 \) must be 7 units away from zero. It can be 7 units in the positive direction (\( x-2=7 \)) or 7 units in the negative direction (\( x-2=-7 \)).
- These two scenarios correspond to the two possible values of \( x \), demonstrating that \( x \) can exist at two different points on the number line that are equidistant from 2.
Other exercises in this chapter
Problem 60
The equations in Exercises \(59-70\) combine the types of equations we have discussed in this section. Solve each equation or state that it is true for all real
View solution Problem 61
Describe similarities and differences between the solutions of $$ (x-2)(x+5) \geq 0 \text { and } \frac{x-2}{x+5} \geq 0 $$
View solution Problem 61
Solve each equation in Exercises \(55-64\) using the quadratic formula. $$ 4 x^{2}=2 x+7 $$
View solution Problem 61
In Exercises \(57-76,\) solve each formula for the specified variable. Do you recognize the formula? If so, what does it describe? \(I=P r t\) for \(P\)
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