Problem 61
Question
Sketch the curve given by parametric equations \(x=\cosh (t)\) \(y=\sinh (t)\) where \(-2 \leq t \leq 2\).
Step-by-Step Solution
Verified Answer
The curve is one branch of a hyperbola to the right, symmetric about the x-axis.
1Step 1: Recall Definitions of Hyperbolic Functions
Recall that hyperbolic cosine and sine functions are given by the expressions \(\cosh(t) = \frac{e^t + e^{-t}}{2}\) and \(\sinh(t) = \frac{e^t - e^{-t}}{2}\) respectively. These functions are related through the identity \(\cosh^2(t) - \sinh^2(t) = 1\), which resembles the Pythagorean identity in trigonometry.
2Step 2: Compute Points for Key Values of t
Calculate specific values for \(t\) in the range \([-2, 2]\) to help in sketching the curve. Consider the values: \(-2, -1, 0, 1, 2\). For each \(t\), calculate \(x = \cosh(t)\) and \(y = \sinh(t)\):- \(t = -2\): \(x = \cosh(-2) = \cosh(2)\), \(y = \sinh(-2) = -\sinh(2)\)- \(t = -1\): \(x = \cosh(-1) = \cosh(1)\), \(y = \sinh(-1) = -\sinh(1)\)- \(t = 0\): \(x = \cosh(0) = 1\), \(y = \sinh(0) = 0\)- \(t = 1\): \(x = \cosh(1)\), \(y = \sinh(1)\)- \(t = 2\): \(x = \cosh(2)\), \(y = \sinh(2)\)
3Step 3: Identify Symmetrical Properties of the Curve
Notice that the curve is symmetrical about the \(x\)-axis. This is because \(x = \cosh(t)\) is an even function and \(y = \sinh(t)\) is an odd function, resulting in symmetry. This symmetry helps in visualizing the curve's shape.
4Step 4: Plot the Calculated Points
Plot the computed pairs \((x, y)\) from Step 2 on the Cartesian plane. Each point represents a solution to the parametric equations for a specific parameter \(t\). Ensure to reflect the graphical symmetry identified in Step 3.
5Step 5: Sketch the Smooth Curve
Connect the plotted points smoothly, respecting the behavior of hyperbolic functions. The curve will resemble the right arm of a hyperbola, opening to the right due to \(\cosh(t)\)'s growth as \(t\) increases. Such a sketch confirms it looks like half of a hyperbola.
Key Concepts
Hyperbolic FunctionsCartesian PlaneSymmetrical PropertiesParametric Curve Sketching
Hyperbolic Functions
Hyperbolic functions, like trigonometric functions, are defined using exponential functions. They are important in many areas such as calculus and mathematical modeling. The two primary hyperbolic functions are \( \cosh(t) \) (hyperbolic cosine) and \( \sinh(t) \) (hyperbolic sine).
- \( \cosh(t) = \frac{e^t + e^{-t}}{2} \)
- \( \sinh(t) = \frac{e^t - e^{-t}}{2} \)
Cartesian Plane
The Cartesian plane is a two-dimensional coordinate plane defined by the x-axis and y-axis. It is used to represent and analyze geometric shapes or relationships between two variables. In this setup, each point has coordinates \((x, y)\).
- The horizontal axis is the x-axis.
- The vertical axis is the y-axis.
- A point on the plane is represented by the pair \((x, y)\).
Symmetrical Properties
Symmetrical properties of functions offer insight into the nature of curves and their transformations. For these parametric equations, symmetry can simplify the process of graphing. Here, the symmetry is found in the relationship of the functions:
- \( \cosh(t) \) is an even function, meaning \( \cosh(-t) = \cosh(t) \).
- \( \sinh(t) \) is an odd function, meaning \( \sinh(-t) = -\sinh(t) \).
Parametric Curve Sketching
Parametric curve sketching involves plotting curves defined not just by \(x\) or \(y\), but as functions of a third variable, often \(t\), a parameter. This can make graphs more flexible and expressive.
- Identify key points by calculating the values of \(x\) and \(y\) for select values of \(t\).
- Consider the symmetrical and behavior properties of the functions, such as growth rate.
- Connect the points smoothly while honoring identified symmetries and function characteristics.
Other exercises in this chapter
Problem 59
Use technology to sketch the spiral curve given by \(x=t \cos (t), y=t \sin (t)\) from \(-2 \pi \leq t \leq 2 \pi .\)
View solution Problem 60
Use technology to graph the curve given by the \(\begin{array}{l}\text { parametric } & \text { equations } \\ x=2 \cot (t), y=1-\cos (2 t),-\pi / 2 \leq t \leq
View solution Problem 62
Each set of parametric equations represents a line. Without eliminating the parameter, find the slope of each line. $$ x=3+t, \quad y=1-t $$
View solution Problem 64
Each set of parametric equations represents a line. Without eliminating the parameter, find the slope of each line. $$ x=4-3 t, \quad y=-2+6 t $$
View solution