Problem 61
Question
Simplify. $$ \frac{2-i}{3-4 i} $$
Step-by-Step Solution
Verified Answer
The simplified form is \(\frac{2}{5} + \frac{i}{5}\).
1Step 1: Identify the complex fractions
The given fraction is \( \frac{2-i}{3-4i} \). In order to simplify a fraction with complex numbers, we need to eliminate the imaginary part from the denominator by multiplying both numerator and denominator by the conjugate of the denominator.
2Step 2: Conjugate of the denominator
The denominator is \(3 - 4i\). The conjugate of \(3 - 4i\) is \(3 + 4i\). We will multiply both the numerator and the denominator of the fraction by this conjugate.
3Step 3: Multiply by the conjugate
Multiply the numerator and the denominator by \(3 + 4i\): \[\frac{(2 - i)(3 + 4i)}{(3 - 4i)(3 + 4i)}\]
4Step 4: Simplify the denominator
The denominator becomes \((3 - 4i)(3 + 4i) = 3^2 - (4i)^2 = 9 - 16(-1) = 9 + 16 = 25\). Now, the denominator is 25.
5Step 5: Expand the numerator
Expand the numerator using distributive property:\((2 - i)(3 + 4i) = 2(3) + 2(4i) - i(3) - i(4i)\). Simplifying this gives:\[6 + 8i - 3i - 4i^2\]. Note that \(i^2 = -1\), so \(-4i^2 = 4\).
6Step 6: Combine like terms
Now, combine like terms in the expanded form:\[6 + 4 + 5i = 10 + 5i\].
7Step 7: Write the simplified fraction
Substitute back the simplified parts into the fraction:\[\frac{10 + 5i}{25}\]
8Step 8: Simplify the fraction further
Divide both real and imaginary components by 25:\[\frac{10}{25} + \frac{5i}{25} = \frac{2}{5} + \frac{i}{5}\]
9Step 9: Final Simplified Form
The simplified form of the original complex fraction is:\[\frac{2}{5} + \frac{i}{5}\]
Key Concepts
Imaginary NumbersComplex ConjugateAlgebraic SimplificationComplex Numbers
Imaginary Numbers
Imaginary numbers might seem mysterious at first, but they are simply numbers that give a negative product when squared. To understand them, let's start with a typical number line, which includes zero as its midpoint and stretches infinitely in both positive and negative directions. Imaginary numbers extend this idea by providing a perpendicular number line.
At the heart of imaginary numbers is the symbol \( i \), defined as the square root of \(-1\). This means that \( i^2 = -1 \). When you multiply \( i \) by any real number, the result is purely imaginary. For example:
In our original problem, the imaginary unit \( i \) appears, which is addressed by using algebraic techniques to make calculations with complex numbers feasible.
At the heart of imaginary numbers is the symbol \( i \), defined as the square root of \(-1\). This means that \( i^2 = -1 \). When you multiply \( i \) by any real number, the result is purely imaginary. For example:
- \( 3i \) means 3 times \( i \)
- \( -2i \) means -2 times \( i \)
In our original problem, the imaginary unit \( i \) appears, which is addressed by using algebraic techniques to make calculations with complex numbers feasible.
Complex Conjugate
A complex conjugate is a significant concept when working with complex numbers. By definition, the complex conjugate of a complex number is obtained by changing the sign of the imaginary component. For instance, the conjugate of \( a + bi \) is \( a - bi \).
This operation is particularly useful for simplifying complex fractions. The multiplication of a complex number by its conjugate results in a real number because the imaginary parts cancel each other out. For example:
This operation is particularly useful for simplifying complex fractions. The multiplication of a complex number by its conjugate results in a real number because the imaginary parts cancel each other out. For example:
- \((a + bi)(a - bi) = a^2 - (bi)^2\)
- Since \( i^2 = -1 \), this simplifies to: \( a^2 + b^2 \)
Algebraic Simplification
Algebraic simplification is a crucial step when working with complex fractions. It involves breaking down expressions into simpler forms for more manageable calculations.
In complex fractions, both the numerator and denominator can be complex expressions. Simplifying them requires a good grasp of basic algebraic operations such as expansion, combination of like terms, and the use of properties of imaginary numbers, particularly noting that \( i^2 = -1 \):
In complex fractions, both the numerator and denominator can be complex expressions. Simplifying them requires a good grasp of basic algebraic operations such as expansion, combination of like terms, and the use of properties of imaginary numbers, particularly noting that \( i^2 = -1 \):
- Expand expressions using distributive property
- Combine like terms, both real and imaginary
Complex Numbers
Complex numbers are extensions of the real number line into a plane system, involving both real and imaginary parts. Any complex number can be expressed in the form \(a + bi\), where \(a\) is the real part and \(bi\) is the imaginary part.
These numbers are incredibly versatile and are used in various fields, including engineering, physics, and applied mathematics. They allow for the solution of equations that have no real solutions, such as those involving roots of negative numbers.
In the exercise presented, we deal with the expression \( \frac{2-i}{3-4i} \), which involves both real and imaginary components. Simplifying such fractions means manipulating both components correctly to derive a fully simplified form. The final simplified form, \( \frac{2}{5} + \frac{i}{5} \), exemplifies how real and imaginary numbers can be combined and simplified in useful ways, encapsulating how complex numbers make calculations involving imaginary units feasible.
These numbers are incredibly versatile and are used in various fields, including engineering, physics, and applied mathematics. They allow for the solution of equations that have no real solutions, such as those involving roots of negative numbers.
In the exercise presented, we deal with the expression \( \frac{2-i}{3-4i} \), which involves both real and imaginary components. Simplifying such fractions means manipulating both components correctly to derive a fully simplified form. The final simplified form, \( \frac{2}{5} + \frac{i}{5} \), exemplifies how real and imaginary numbers can be combined and simplified in useful ways, encapsulating how complex numbers make calculations involving imaginary units feasible.
Other exercises in this chapter
Problem 61
Solve each matrix equation or system of equations by using inverse matrices. $$ \begin{array}{l}{5 y+2 z=11} \\ {10 y-4 z=-2}\end{array} $$
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Find the value of the discriminant for each quadratic equation. Then describe the number and type of roots for the equation. $$ 3 x^{2}-6 x+2=0 $$
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Factor completely. $$ x^{2}-100 $$
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Write a perfect square trinomial equation in which the linear coefficient is negative and the constant term is a fraction. Then solve the equation.
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