Problem 61
Question
Simplify each radical. Assume that all variables represent positive real numbers. $$ \sqrt{25 a^{2} b^{20}} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \( 5ab^{10} \).
1Step 1: Understand the Square Root Function
The square root function is searching for a number that, when multiplied by itself, equals the given expression under the root. For example, the square root of 25 is 5 because 5 multiplied by 5 equals 25.
2Step 2: Simplify the Number under the Root
Identify any perfect square factors under the radical. In this case, within the expression \( \sqrt{25 a^2 b^{20}} \), the number 25 can be simplified as it is a perfect square, so \( \sqrt{25} = 5 \).
3Step 3: Simplify the Variables under the Root
Apply the square root to each variable separately:- \( a^2 \) is a perfect square: \( \sqrt{a^2} = a \).- \( b^{20} \) can be rewritten as \( (b^{10})^2 \), allowing us to write: \( \sqrt{b^{20}} = b^{10} \).
4Step 4: Combine Simplified Elements
Combine elements from Steps 2 and 3. The simplified expression is: \[ \sqrt{25 a^{2} b^{20}} = 5ab^{10} \].
Key Concepts
Understanding Square RootsThe Role of Perfect SquaresDealing with Variable Exponents
Understanding Square Roots
The square root is a fascinating mathematical operation. It asks "what number, multiplied by itself, gives this value?" For the number 25, its square root is 5 because multiplying 5 by itself gives 25. Think of it as the opposite of squaring a number. This operation is most often seen as the symbol \( \sqrt{} \).
Here are some things to remember about square roots:
Here are some things to remember about square roots:
- If the number inside the square root (known as the radicand) is a perfect square, the square root simplifies to a whole number.
- When working with variables, you apply the square root to each part separately.
- Understanding square roots helps simplify expressions in algebra.
The Role of Perfect Squares
Perfect squares are the numbers that gain importance when dealing with square roots. A perfect square is simply a number multiplied by itself. Examples include 1, 4, 9, 16, 25, etc. These numbers already have a nice neat square root.
When simplifying expressions under a radical, such as \( \sqrt{25} \), recognizing 25 as \( 5^2 \) tells us that its square root is simply 5. For variables in radical expressions, it’s the same principle. In our example, \( a^2 \) is a perfect square, so \( \sqrt{a^2} \) simplifies to \( a \).
The key benefits of identifying perfect squares include:
When simplifying expressions under a radical, such as \( \sqrt{25} \), recognizing 25 as \( 5^2 \) tells us that its square root is simply 5. For variables in radical expressions, it’s the same principle. In our example, \( a^2 \) is a perfect square, so \( \sqrt{a^2} \) simplifies to \( a \).
The key benefits of identifying perfect squares include:
- They help eliminate the radical in the expression entirely.
- They simplify your calculations by reducing complex terms into simple numerical forms.
Dealing with Variable Exponents
Variable exponents can seem tricky at first, but understanding them simplifies many algebraic expressions. When you see a variable with an exponent within a radical, remember that you're looking for manageable ways to reduce it.
Take \( b^{20} \), for example. Since we're taking the square root, we're looking for something squared that, when squared, gives us \( b^{20} \). This can be written as \( (b^{10})^2 \). Thus, \( \sqrt{b^{20}} = b^{10} \).
Here are some quick tips for working with variable exponents:
Take \( b^{20} \), for example. Since we're taking the square root, we're looking for something squared that, when squared, gives us \( b^{20} \). This can be written as \( (b^{10})^2 \). Thus, \( \sqrt{b^{20}} = b^{10} \).
Here are some quick tips for working with variable exponents:
- Split the exponent into two parts that are easy to manage, like squared terms.
- Ensure every part of the exponent has been simplified according to the root you're taking.
- Always simplify the expression fully by individually handling each variable.
Other exercises in this chapter
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