Problem 61
Question
Perform the operations. $$ (4 f+0.4)(4 f-0.4) $$
Step-by-Step Solution
Verified Answer
The result is \(16f^2 - 0.16\).
1Step 1: Understand the Form of the Expression
The expression \((4f+0.4)(4f-0.4)\) is in the form \((a+b)(a-b)\), which is a difference of squares.
2Step 2: Apply the Difference of Squares Formula
The difference of squares formula is \((a+b)(a-b) = a^2 - b^2\). Identify \(a = 4f\) and \(b = 0.4\). Then, apply the formula.
3Step 3: Calculate \(a^2\)
Calculate \(a^2 = (4f)^2 = 16f^2\).
4Step 4: Calculate \(b^2\)
Calculate \(b^2 = (0.4)^2 = 0.16\).
5Step 5: Substitute and Simplify
Substitute \(a^2\) and \(b^2\) back into the formula to obtain the simplified expression: \( (4f)^2 - (0.4)^2 = 16f^2 - 0.16 \).
Key Concepts
Understanding Algebraic ExpressionsFactoring: Use the Difference of SquaresSimplification of Expressions
Understanding Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and mathematical operations. In the expression \((4f+0.4)(4f-0.4)\), "4f" is a term where "4" is the coefficient and "f" is the variable. The expression also includes constants like "0.4".
An algebraic expression can have:
When you encounter expressions like \((4f+0.4)(4f-0.4)\), it is helpful to recognize patterns like the difference of squares, which can make it easier to simplify them.
An algebraic expression can have:
- Constants – numbers that do not change
- Variables – letters that can represent changing numbers
- Operators – symbols that show mathematical operations such as addition and subtraction
When you encounter expressions like \((4f+0.4)(4f-0.4)\), it is helpful to recognize patterns like the difference of squares, which can make it easier to simplify them.
Factoring: Use the Difference of Squares
Factoring is a method used to write an expression as a product of its factors. Recognizing the form of an expression can help you in factoring it efficiently. The given expression \((4f+0.4)(4f-0.4)\) fits the pattern of a difference of squares. This pattern is expressed as \((a+b)(a-b) = a^2 - b^2\).
Here's how it works:
This simplifies to \(16f^2 - 0.16\), effectively factoring the expression.
Here's how it works:
- Identify the square roots of the first and last terms in the expression. In our case, \(a = 4f\) and \(b = 0.4\).
- Apply the formula by substituting \(a\) and \(b\), which will yield \(a^2 - b^2\).
- Calculate the squares: \((4f)^2 = 16f^2\) and \((0.4)^2 = 0.16\).
This simplifies to \(16f^2 - 0.16\), effectively factoring the expression.
Simplification of Expressions
Simplification involves reducing an expression to its simplest form. This is the process you're doing when you convert \((4f+0.4)(4f-0.4)\) into \(16f^2 - 0.16\).
Steps to simplify using the difference of squares:
Always check if you can reduce the expression further by combining like terms or factoring common factors. This practice keeps expressions neat and as elegant as possible for easier interpretation and use.
Steps to simplify using the difference of squares:
- Apply the difference of squares formula: \((a+b)(a-b) = a^2 - b^2\).
- Substitute the calculated values of \(a^2\) and \(b^2\) into the equation.
- Simplify the resulting expression if necessary. In this case, \(16f^2 - 0.16\) is already simplified.
Always check if you can reduce the expression further by combining like terms or factoring common factors. This practice keeps expressions neat and as elegant as possible for easier interpretation and use.
Other exercises in this chapter
Problem 60
Write number in scientific notation. \(56.29 \times 10^{-30}\)
View solution Problem 60
Simplify. Do not use negative exponents in the answer. \(c^{-9} \cdot c^{14}\)
View solution Problem 61
Multiply. See Example 6. $$ \left(x^{2}+6 x+7\right)(2 x-5) $$
View solution Problem 61
Use the product and power rules for exponents to simplify each expression. $$ \left(p^{2} p^{3}\right)^{5} $$
View solution