Problem 61
Question
Perform the indicated operations Indicate the degree of the resulting polynomial. $$ \left(4 x^{2} y+8 x y+11\right)+\left(-2 x^{2} y+5 x y+2\right) $$
Step-by-Step Solution
Verified Answer
The resulting polynomial from adding the given polynomials is \(2x^{2}y + 13xy + 13\). The degree of this polynomial is 3.
1Step 1: Add the Polynomials
Combine the like terms from both polynomials. Like terms are those which have the same variables raised to the same power. That is, add \(4x^{2}y\) and \(-2x^{2}y\) together, and add \(8xy\) and \(5xy\) together. Leave \(11 + 2\) as they have no variables.
2Step 2: Resultant Polynomial
Adding the terms from Step 1 will give the resulting polynomial: \( (4x^{2}y - 2x^{2}y) + (8xy + 5xy) + (11 + 2) = 2x^{2}y + 13xy + 13 \)
3Step 3: Degree of the Polynomial
The degree of the polynomial is the highest power of x or y in the polynomial. For the resulting polynomial \(2x^{2}y + 13xy + 13\), the terms are of degree 3, 2, and 0, respectively. Therefore, the degree of the resulting polynomial is 3.
Key Concepts
Degree of a PolynomialLike TermsCombining Polynomials
Degree of a Polynomial
The degree of a polynomial is an important concept to grasp, as it helps determine the behavior and properties of the polynomial. The degree is defined as the highest power of the variable in the polynomial expression. In our given example of the resulting polynomial, \(2x^{2}y + 13xy + 13\), each term has its own degree.
- The term \(2x^{2}y\) is a product of \(x^2\) and \(y\), giving it a degree of 3 (as we add the exponents: 2 from \(x^2\) and 1 from \(y\)).
- The term \(13xy\) has a degree of 2 (1 for \(x\) and 1 for \(y\)).
- The constant term \(13\) holds a degree of 0 since it has no variable attached.
Like Terms
Understanding like terms is fundamental in simplifying polynomials. Like terms are terms in an expression that have the same variables and corresponding powers. They can be combined through addition or subtraction to simplify the expression.
In our expression \((4x^{2}y + 8xy + 11) + (-2x^{2}y + 5xy + 2)\), we identify the following like terms:
In our expression \((4x^{2}y + 8xy + 11) + (-2x^{2}y + 5xy + 2)\), we identify the following like terms:
- \(4x^{2}y\) and \(-2x^{2}y\): Both terms have the same variables \(x^2y\).
- \(8xy\) and \(5xy\): These terms share the variables \(xy\) with the same power.
- Constants \(11\) and \(2\) can be added together without any variables being involved.
Combining Polynomials
Combining polynomials involves carrying out addition or subtraction, which means merging their corresponding terms to get a simplified result. This process often requires dealing with like terms. There is also a systematic approach to ensure accuracy.
In the given exercise, we have two polynomials: \((4x^{2}y + 8xy + 11)\) and \((-2x^{2}y + 5xy + 2)\). To combine these polynomials, follow these steps:
In the given exercise, we have two polynomials: \((4x^{2}y + 8xy + 11)\) and \((-2x^{2}y + 5xy + 2)\). To combine these polynomials, follow these steps:
- Arrange terms over each other, so like terms line up vertically.
- Add or subtract the coefficients of like terms.
- Write the resulting polynomial, ensuring every term is accounted for.
Other exercises in this chapter
Problem 61
Factor using the formula for the sum or difference of tho cubes. $$ 8 x^{3}-1 $$
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Evaluate each expression or indicate that the root is not a real number. $$\sqrt[4]{(-3)^{4}}$$
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Simplify each complex rational expression. $$\frac{1+\frac{1}{x}}{3-\frac{1}{x}}$$
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Simplify each exponential expression in Exercises 23–64. $$\left(\frac{-15 a^{4} b^{2}}{5 a^{10} b^{-3}}\right)^{3}$$
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