Problem 61
Question
Multiply. Write all answers in the form a \(+b i.\) $$ (4+\sqrt{-1})(3-\sqrt{-1}) $$
Step-by-Step Solution
Verified Answer
The product is \( 13 - i \).
1Step 1: Recognize the Imaginary Unit
Identify that \( \sqrt{-1} \) is \( i \), the imaginary unit. Rewrite each complex number using \( i \): \( (4 + i) \) and \( (3 - i) \).
2Step 2: Distribute the Terms
Apply the distributive property, also known as the FOIL method, to multiply the expressions: \( (4+i)(3-i) = 4(3) + 4(-i) + i(3) + i(-i) \).
3Step 3: Calculate Each Term
Calculate each component of the expanded expression: - \( 4 \times 3 = 12 \)- \( 4 \times (-i) = -4i \)- \( i \times 3 = 3i \)- \( i \times (-i) = -i^2 \).
4Step 4: Substitute \( i^2 = -1 \) and Simplify
Since \( i^2 = -1 \), replace \( -i^2 \) with \(-(-1) = 1 \). Combine real and imaginary parts:- Real parts: \( 12 + 1 = 13 \)- Imaginary parts: \(-4i + 3i = -i \).
5Step 5: Write the Final Answer
Combine the simplified real and imaginary parts into the final answer in the form \( a + bi \): \( 13 - i \).
Key Concepts
Imaginary UnitFOIL MethodDistributive PropertySimplifying Expressions
Imaginary Unit
In the world of complex numbers, the imaginary unit plays a crucial role. Often represented by the symbol \( i \), it is defined as the square root of negative one.
This means that \( i^2 = -1 \). Without \( i \), it would be impossible to deal with the square roots of negative numbers in mathematics, as they do not fit within the real number system. This clever concept allows us to expand beyond what is possible with just real numbers and solve equations that would otherwise have no solution.
By considering \( \ \sqrt{-1} \) as \( i \), we can rewrite expressions like \( 4 + \ \sqrt{-1} \) as \( 4 + i \), making calculations more manageable when dealing with complex numbers.
This means that \( i^2 = -1 \). Without \( i \), it would be impossible to deal with the square roots of negative numbers in mathematics, as they do not fit within the real number system. This clever concept allows us to expand beyond what is possible with just real numbers and solve equations that would otherwise have no solution.
By considering \( \ \sqrt{-1} \) as \( i \), we can rewrite expressions like \( 4 + \ \sqrt{-1} \) as \( 4 + i \), making calculations more manageable when dealing with complex numbers.
FOIL Method
The FOIL method is a specific technique used to multiply two binomials. The acronym FOIL stands for First, Outer, Inner, Last, referring to the order in which you multiply the terms.
To apply this method to our problem, which is to multiply \( (4 + i)(3 - i) \), we break it down as follows:
Using the FOIL method ensures a systematic approach to multiplying binomials so that no term is overlooked.
To apply this method to our problem, which is to multiply \( (4 + i)(3 - i) \), we break it down as follows:
- First: Multiply the first terms: \( 4 \times 3 = 12 \)
- Outer: Multiply the outer terms: \( 4 \times (-i) = -4i \)
- Inner: Multiply the inner terms: \( i \times 3 = 3i \)
- Last: Multiply the last terms: \( i \times (-i) = -i^2 \)
Using the FOIL method ensures a systematic approach to multiplying binomials so that no term is overlooked.
Distributive Property
The distributive property is fundamental in algebra and underlies the FOIL method. It states that multiplying a number by a sum is the same as doing each multiplication separately and then adding the results.
In mathematical terms, if \( a, b, \) and \( c \) are any numbers, the distributive property says \( a(b + c) = ab + ac \).
Applying this to complex numbers, when we distribute \( (4 + i) \) with \( (3 - i) \), we individually multiply each term:
This is key to properly expanding and simplifying expressions involving complex numbers.
In mathematical terms, if \( a, b, \) and \( c \) are any numbers, the distributive property says \( a(b + c) = ab + ac \).
Applying this to complex numbers, when we distribute \( (4 + i) \) with \( (3 - i) \), we individually multiply each term:
- \( 4(3 - i) = 12 - 4i \)
- \( i(3 - i) = 3i - i^2 \)
This is key to properly expanding and simplifying expressions involving complex numbers.
Simplifying Expressions
Simplifying expressions, especially with complex numbers, requires combining like terms and understanding the properties of \( i \).
Each term produced from the multiplication step can be categorized into real or imaginary components:
For the example \( (4+i)(3-i) \), simplifying means ensuring all real numbers and imaginary numbers are combined correctly to arrive at the equation:
The equation \( 13 - i \) illustrates the form \( a + bi \), which is the standard way to present a complex number, showing the real part \( a \) and the imaginary part \( bi \).
This systematic approach ensures clarity and correctness when handling complex numbers in expressions.
Each term produced from the multiplication step can be categorized into real or imaginary components:
- The real component is obtained from multiplying numbers without \( i \), and involves computation with \( i^2 \) since \( i^2 = -1 \), transforming it into a real number.
- The imaginary component involves terms with \( i \), and once multiplied or added, these terms are kept separate but alongside real parts to finalize the complex number form.
For the example \( (4+i)(3-i) \), simplifying means ensuring all real numbers and imaginary numbers are combined correctly to arrive at the equation:
The equation \( 13 - i \) illustrates the form \( a + bi \), which is the standard way to present a complex number, showing the real part \( a \) and the imaginary part \( bi \).
This systematic approach ensures clarity and correctness when handling complex numbers in expressions.
Other exercises in this chapter
Problem 61
The sides of a regular hexagonal nut are 10 millimeters long. Find the height \(h\) of the nut. Give the exact answer and an approximation to two decimal places
View solution Problem 61
Solve each equation. Write all proposed solutions. Cross out those that are extraneous. See Example 8. $$ 2=\sqrt{2 u+7}-\sqrt{u} $$
View solution Problem 61
Rationalize each denominator. $$ \frac{1}{\sqrt[3]{2}} $$
View solution Problem 61
Simplify by combining like radicals. $$ 8+\sqrt[3]{32}-\sqrt[3]{108}-7 $$
View solution