Problem 61
Question
Multiply the algebraic expressions using a Special Product Formula, and simplify. \((3 x-4)(3 x+4)\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(9x^2 - 16\).
1Step 1: Identify the Formula to Use
The given algebraic expressions \((3x - 4)(3x + 4)\) suggest the use of the difference of squares formula, which states \((a-b)(a+b) = a^2 - b^2\).
2Step 2: Apply the Difference of Squares Formula
Here, let \(a = 3x\) and \(b = 4\). Plug these values into the formula to get \((3x)^2 - 4^2\).
3Step 3: Calculate Each Square in the Formula
First, calculate \((3x)^2\), which is \((3x)(3x) = 9x^2\). Next, calculate \(4^2\), which is \(16\).
4Step 4: Simplify the Expression
Substitute the calculated values back into the formula: \(9x^2 - 16\), which is already simplified.
Key Concepts
Algebraic ExpressionsSpecial Product FormulaSimplifying Expressions
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations that describe a mathematical idea or problem. In the exercise, we have two algebraic expressions in the form \(3x - 4\) and \(3x + 4\). These expressions can be thought of as instructions to calculate a value given a specific \(x\).
Understanding the structure of these expressions:
Understanding the structure of these expressions:
- Coefficient: In \(3x\), the number 3 is a coefficient, showing how many units of \(x\) there are.
- Variable: \(x\) is the variable that can change or be given a specific value.
- Constant: The numbers -4 and +4 are constants, values that don't change.
Special Product Formula
Special product formulas in algebra are pre-established rules that help solve certain types of multiplication problems quickly. One specific formula we often use is the difference of squares: \(a^2 - b^2 = (a - b)(a + b)\).
This formula is especially useful because:
You identify the terms: \(a = 3x\) and \(b = 4\), then apply the formula to get \[a^2 - b^2 = (3x)^2 - 4^2\]. This matches the formula perfectly, making calculations almost immediate without needing each term to be multiplied individually.
This formula is especially useful because:
- It turns a multiplication of two binomials into a simple subtraction problem.
- By recognizing the pattern, complex calculations can be avoided.
You identify the terms: \(a = 3x\) and \(b = 4\), then apply the formula to get \[a^2 - b^2 = (3x)^2 - 4^2\]. This matches the formula perfectly, making calculations almost immediate without needing each term to be multiplied individually.
Simplifying Expressions
Simplifying expressions involves reducing them to their simplest form, making them easier to understand or use. This often means performing arithmetic with known numbers and combining like terms.
In the exercise, after recognizing and using the difference of squares formula, we end up with \(9x^2 - 16\).
Steps to simplify this include:
In the exercise, after recognizing and using the difference of squares formula, we end up with \(9x^2 - 16\).
Steps to simplify this include:
- Calculating individual squares: \(3x \, squared gives \, 9x^2\) and \(4^2 = 16\).
- Substituting these into the formula: We thus have \(9x^2 - 16\).
Other exercises in this chapter
Problem 61
Factor the expression completely. $$ t^{3}+1 $$
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Find the distance between the given numbers. $$ \begin{array}{llll}{\text { (a) } 2 \text { and } 17} & {\text { (b) }-3 \text { and } 21} & {\text { (c) } \fra
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Perform the addition or subtraction and simplify. $$ \frac{x}{x^{2}-x-6}-\frac{1}{x+2}-\frac{2}{x-3} $$
View solution Problem 62
\(47-72\) . Simplify the expression, and eliminate any negative exponent(s). $$ \left(\frac{x^{4} z^{2}}{4 y^{5}}\right)\left(\frac{2 x^{3} y^{2}}{z^{3}}\right)
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