Problem 61
Question
Multiply as indicated. Write each product in standard form. $$(3+i)(-3-i)$$
Step-by-Step Solution
Verified Answer
The product is \(-8 - 6i\).
1Step 1: Use the Distributive Property
Apply the distributive property (FOIL method) to the expression \((a+b)(c+d) = ac + ad + bc + bd\). For the given expression \((3+i)(-3-i)\), distribute each term:- First: \(3 \times -3 = -9\)- Outer: \(3 \times -i = -3i\)- Inner: \(i \times -3 = -3i\)- Last: \(i \times -i = -i^2\)
2Step 2: Simplify the Expression
Combine like terms:- Combine \(-3i\) and \(-3i\) to get \(-6i\).- Recognize that \(-i^2\) is equal to \(-(-1)\) or \(1\) because \(i^2 = -1\).So, we have:\(-9 - 6i + 1\).
3Step 3: Write in Standard Form
Combine the real parts:\(-9 + 1 = -8\).The standard form for the expression is \(-8 - 6i\).
Key Concepts
Distributive PropertyFOIL MethodSimplifying ExpressionsStandard Form
Distributive Property
The distributive property is a key algebraic rule that allows us to multiply a single term by two or more terms inside a parenthesis. It establishes how each element in one bracket multiplies with each element in the other.
For example, in \(a + b\)(c + d) = ac + ad + bc + bd\, each term is distributed across the others. This ensures each term in the first bracket multiplies with every term in the second. When applying this to complex numbers such as \(3+i\)(-3-i)\, this technique helps to systematically simplify the expression.
The distributive property's ability to handle complex numbers allows us to transform a product of sums into simpler terms, making calculations easier and more manageable.
For example, in \(a + b\)(c + d) = ac + ad + bc + bd\, each term is distributed across the others. This ensures each term in the first bracket multiplies with every term in the second. When applying this to complex numbers such as \(3+i\)(-3-i)\, this technique helps to systematically simplify the expression.
The distributive property's ability to handle complex numbers allows us to transform a product of sums into simpler terms, making calculations easier and more manageable.
FOIL Method
The FOIL method is a specific use of the distributive property commonly applied to multiply binomials. FOIL stands for First, Outer, Inner, Last, describing the order in which you multiply the terms:
- First: Multiplying the first terms in each binomial.
- Outer: Multiplying the outer terms.
- Inner: Multiplying the inner terms.
- Last: Multiplying the last terms.
- exttt{-9}: the product of the first terms (3 and -3).
- exttt{-3i} and exttt{-3i}: the products of the outer (3 and -i) and inner (i and -3) terms respectively.
- exttt{-i^2}: the product of the last terms (i and -i).
Simplifying Expressions
Simplifying expressions means reducing them to their simplest form by combining like terms and applying mathematical rules.
In our expression \(-9 - 6i + 1\), simplifying involves:
In our expression \(-9 - 6i + 1\), simplifying involves:
- Combining the constants \-9\ and \+1\, which results in \-8\.
- Recognizing that \-i^2\ equals \+1\ because \i^2 = -1\.
- Adding the like terms \-3i\ and \-3i\ to obtain \-6i\.
Standard Form
The standard form for complex numbers is expressed as \a + bi\, where \a\ and \b\ are real numbers. Here, \a\ represents the real part and \bi\ the imaginary part.
To write \(-9 - 6i + 1\) in standard form, you first combine the real components \-9\ and \+1\ to form \-8\. This leads to a final expression of \-8 - 6i\.
Using standard form is important for clarity and consistency, especially when dealing with complex expressions. It ensures that the expression is easily understandable and can be used correctly in further calculations.
To write \(-9 - 6i + 1\) in standard form, you first combine the real components \-9\ and \+1\ to form \-8\. This leads to a final expression of \-8 - 6i\.
Using standard form is important for clarity and consistency, especially when dealing with complex expressions. It ensures that the expression is easily understandable and can be used correctly in further calculations.
Other exercises in this chapter
Problem 61
For each polynomial, at least one zero is given. Find all others analytically. $$P(x)=x^{3}-2 x^{2}-5 x+6 ; \quad 3$$
View solution Problem 61
Solve each problem. Heart Rate An athlete's heart rate \(R\) in beats per minute after \(x\) minutes is given by $$R(x)=2(x-4)^{2}+90$$ where \(0 \leq x \leq 8\
View solution Problem 61
Find all \(n\) complex solutions of each equation of the form \(x^{n}=k\) $$x^{4}=16$$
View solution Problem 61
For the functions in Exercises \(59-66,\) use your graphing calculator to find a comprehensive graph and answer each of the following. (a) Determine the domain.
View solution