Problem 61
Question
Make an input-output table for the function \(A=8+2.5 t\) when \(t=2,3,4,5,\) and \(6 .\) Describe the domain and the range of the function whose values are shown in the table.
Step-by-Step Solution
Verified Answer
The input-output table of the function will be: for \(t=2\), \(A=13\); \(t=3\), \(A=15.5\); for \(t=4\), \(A=18\); for \(t=5\), \(A=20.5\); for \(t=6\), \(A=23\). The domain of the function is \(t = 2, 3, 4, 5, 6\) and the range is \(A = 13, 15.5, 18, 20.5, 23\).
1Step 1: Create an Input-Output Table
Substitute the given values for \(t\) into the function \(A=8+2.5 t\) to find the corresponding value of \(A\).For \(t=2\), compute \(A\) as: \(A=8+2.5*2=13\)For \(t=3\), compute \(A\) as: \(A=8+2.5*3=15.5\)For \(t=4\), compute \(A\) as: \(A=8+2.5*4=18\)For \(t=5\), compute \(A\) as: \(A=8+2.5*5=20.5\)For \(t=6\), compute \(A\) as: \(A=8+2.5*6=23\)
2Step 2: Determine the Domain
The domain of a function is the set of all possible input values (here, \(t\) values). In this case, the domain is \(t = 2, 3, 4, 5, 6\)
3Step 3: Identify the Range of the Function
The range is the set of all possible outputs of the function, in this case, corresponding \(A\) values. For the given values of \(t = 2, 3, 4, 5, 6\), the calculated range is \(A = 13, 15.5, 18, 20.5, 23\)
Key Concepts
Input-Output TablesDomain and RangeLinear Functions
Input-Output Tables
An input-output table is a simple yet powerful tool used in algebra to show how a function links input values with their corresponding output values. It's like a translator between numbers, helping you visualize the relationship between variables.When you have a function such as \(A = 8 + 2.5t\), the input-output table can be created by substituting specific values into the formula. Imagine you've chosen the values \(t = 2, 3, 4, 5,\) and \(6\). Plug these inputs into the function to find the outputs.
- For \(t = 2\), substitute into the function: \(A = 8 + 2.5 \times 2 = 13\).
- For \(t = 3\), substitute into the function: \(A = 8 + 2.5 \times 3 = 15.5\).
- This continues for each of your selected inputs.
Domain and Range
When discussing functions, the terms "domain" and "range" quickly come into play. They describe the limits of the function in terms of inputs and outputs.The domain is all the possible values you can choose for the input. In our earlier example, the domain consists of the values where \[ t = \{2, 3, 4, 5, 6\}\]. These are the chosen numbers allowed within the function for \(t\).On the flip side, the range refers to all the possible outputs that the function can produce. In this scenario, when you plug the domain values into the function \(A = 8 + 2.5t\), you get the range: \[ A = \{13, 15.5, 18, 20.5, 23\}\].By clearly defining the domain and range, you not only determine the scope of your function but also allow for a deeper understanding of its behaviour. Knowing these terms helps in visualizing the function on a graph and can simplify solving more complex algebra problems.
Linear Functions
Linear functions, a fundamental concept in algebra, are those whose graph forms a straight line. They have the basic form \(y = mx + b\), where \(m\) is the slope, and \(b\) is the y-intercept.In our case, the function \(A = 8 + 2.5t\) fits this definition with \(A\) as the output, \(t\) as the input variable, \(2.5\) as the slope, and \(8\) as the y-intercept. Here, you can visualize it as moving up the y-axis by \(2.5\) units for each 1 unit increase along the x-axis (or in this case, the \(t\)-axis).A linear function translates neatly into a clear pattern:
- Slope of the line \(= 2.5\)
- Y-intercept \(= 8\)
- Pattern of change is constant
Other exercises in this chapter
Problem 61
Simplify the expression. $$\frac{1}{8} y \cdot 8$$
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Simplify the expression. $$-\frac{3}{5}\left(-\frac{5}{3} x\right)$$
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