Problem 61
Question
Find the exact value of the following under the given conditions: a. \(\cos (\alpha+\beta)\) b. \(\sin (\alpha+\beta)\) c. \(\tan (\alpha+\beta)\) \(\cos \alpha=\frac{8}{17}, \alpha\) lies in quadrant IV, and \(\sin \beta=-\frac{1}{2}, \beta\) lies in quadrant III.
Step-by-Step Solution
Verified Answer
The exact values of the trigonometric expressions are: a. \( \cos(\alpha + \beta) = \frac{-8\sqrt{3} + 15}{34} \), b. \( \sin(\alpha + \beta) = \frac{30\sqrt{3} - 8}{34} \), c. \( \tan(\alpha + \beta) = -(\frac{30\sqrt{3} - 8}{8\sqrt{3} - 15}) \).
1Step 1: Determination of \(\sin \alpha\) and \(\cos \beta\)
Based on the known relation \( \sin^2\alpha + \cos^2\alpha = 1 \), solve for \( \sin\alpha \) and get \( \sin\alpha = -\sqrt{1 - \cos^2\alpha} = -\sqrt{1 - (\frac{8}{17})^2} = -\frac{15}{17} \). Similarly solve for \( \cos\beta \) using \( \sin^2\beta + \cos^2\beta = 1 \) to get \( \cos\beta = -\sqrt{1 - \sin^2\beta} = -\sqrt{1 - (-\frac{1}{2})^2} = -\frac{\sqrt{3}}{2} \). \nRemember: In Quadrant IV, sine is negative. In Quadrant III, cosine is negative.
2Step 2: Calculation of \( \cos(\alpha + \beta) \)
Substitute the values into the formula \( \cos(\alpha + \beta) = \cos\alpha\cos\beta - \sin\alpha\sin\beta \). This gives \( \cos(\alpha + \beta) = \frac{8}{17}*\frac{-\sqrt{3}}{2} - \frac{-15}{17}*\frac{-1}{2} = -\frac{4\sqrt{3}}{17} - \frac{15}{34} = -\frac{8\sqrt{3} + 15}{34} \).
3Step 3: Calculation of \( \sin(\alpha + \beta) \)
Substitute the values into the formula \( \sin(\alpha + \beta) = \sin\alpha\cos\beta + \cos\alpha\sin\beta \). This gives \( \sin(\alpha + \beta) = \frac{-15}{17}*\frac{-\sqrt{3}}{2} + \frac{8}{17}*\frac{-1}{2} = \frac{15\sqrt{3}}{34} - \frac{8}{34} = \frac{30\sqrt{3} - 8}{34} \).
4Step 4: Calculation of \( \tan(\alpha + \beta) \)
Substitute the values into the formula \( \tan(\alpha + \beta) = \frac{\sin(\alpha + \beta)}{\cos(\alpha + \beta)} \). This gives \( \tan(\alpha + \beta) = \frac{\frac{30\sqrt{3} - 8}{34}}{\frac{-8\sqrt{3} + 15}{34}} = -(\frac{30\sqrt{3} - 8}{8\sqrt{3} - 15}) \).
Key Concepts
Cosine Sum FormulaSine Sum FormulaTangent Sum FormulaPythagorean Trigonometric Identity
Cosine Sum Formula
Understanding the cosine sum formula is crucial for solving trigonometry problems involving the addition of angles. It states that for any two angles \(\alpha\) and \(\beta\), the cosine of their sum is given by the equation:
\[\cos(\alpha + \beta) = \cos\alpha\cos\beta - \sin\alpha\sin\beta.\]
This identity is derived from the geometric definition of cosine in terms of the unit circle.
When calculating \(\cos(\alpha + \beta)\) given certain trigonometric values, we first need to find the missing sine and cosine values for each angle. In the example provided, we knew that \(\cos \alpha = \frac{8}{17}\) and \(\sin \beta = -\frac{1}{2}\). Given these, we could compute \(\sin \alpha\) and \(\cos \beta\) using the Pythagorean trigonometric identity, tailored to the specific quadrants where the angles lie. After obtaining these values, we substituted them into the cosine sum formula. The result is an exact value for \(\cos(\alpha + \beta)\), essential for further trigonometry calculations or proofs.
\[\cos(\alpha + \beta) = \cos\alpha\cos\beta - \sin\alpha\sin\beta.\]
This identity is derived from the geometric definition of cosine in terms of the unit circle.
When calculating \(\cos(\alpha + \beta)\) given certain trigonometric values, we first need to find the missing sine and cosine values for each angle. In the example provided, we knew that \(\cos \alpha = \frac{8}{17}\) and \(\sin \beta = -\frac{1}{2}\). Given these, we could compute \(\sin \alpha\) and \(\cos \beta\) using the Pythagorean trigonometric identity, tailored to the specific quadrants where the angles lie. After obtaining these values, we substituted them into the cosine sum formula. The result is an exact value for \(\cos(\alpha + \beta)\), essential for further trigonometry calculations or proofs.
Sine Sum Formula
The sine sum formula provides a method of finding the sine of the sum of two angles. It is expressed as:
\[\sin(\alpha + \beta) = \sin\alpha\cos\beta + \cos\alpha\sin\beta.\]
This identity, like the cosine sum formula, originates from the properties of sine and cosine on the unit circle.
When faced with an exercise to find \(\sin(\alpha + \beta)\), as in our example, we determine the sine of the individual angles if not already known. In our case, we calculated \(\cos \beta\) based on the given \(\sin \beta\) and used the angle's quadrant to determine its sign. After computing all necessary trigonometric values, we applied them to the sine sum formula, yielding the precise value of \(\sin(\alpha + \beta)\) required for the computation.
\[\sin(\alpha + \beta) = \sin\alpha\cos\beta + \cos\alpha\sin\beta.\]
This identity, like the cosine sum formula, originates from the properties of sine and cosine on the unit circle.
When faced with an exercise to find \(\sin(\alpha + \beta)\), as in our example, we determine the sine of the individual angles if not already known. In our case, we calculated \(\cos \beta\) based on the given \(\sin \beta\) and used the angle's quadrant to determine its sign. After computing all necessary trigonometric values, we applied them to the sine sum formula, yielding the precise value of \(\sin(\alpha + \beta)\) required for the computation.
Tangent Sum Formula
If you're working with angles and their tangent values, the tangent sum formula is indispensable. It's given by:
\[\tan(\alpha + \beta) = \frac{\sin(\alpha + \beta)}{\cos(\alpha + \beta)}.\]
Alternatively, it can be stated as:
\[\tan(\alpha + \beta) = \frac{\tan\alpha + \tan\beta}{1 - \tan\alpha\tan\beta},\]
assuming that neither \(\tan\alpha\) nor \(\tan\beta\) is undefined.
In the specific problem we've been examining, once we computed the sine and cosine of the sum of the angles using the respective sum formulas, we were able to use these results to find the tangent of the sum using the first version of the tangent sum formula. This approach allowed us to avoid direct computation using the alternative version, which requires the tangent values of the individual angles. The process exemplifies how trigonometric identities can be cleverly employed to simplify calculation steps.
\[\tan(\alpha + \beta) = \frac{\sin(\alpha + \beta)}{\cos(\alpha + \beta)}.\]
Alternatively, it can be stated as:
\[\tan(\alpha + \beta) = \frac{\tan\alpha + \tan\beta}{1 - \tan\alpha\tan\beta},\]
assuming that neither \(\tan\alpha\) nor \(\tan\beta\) is undefined.
In the specific problem we've been examining, once we computed the sine and cosine of the sum of the angles using the respective sum formulas, we were able to use these results to find the tangent of the sum using the first version of the tangent sum formula. This approach allowed us to avoid direct computation using the alternative version, which requires the tangent values of the individual angles. The process exemplifies how trigonometric identities can be cleverly employed to simplify calculation steps.
Pythagorean Trigonometric Identity
A cornerstone of trigonometry is the Pythagorean trigonometric identity, which is the foundation for many trigonometric calculations:
\[\sin^2\alpha + \cos^2\alpha = 1.\]
This identity reveals the intrinsic relationship between the sine and cosine functions and is derived from the Pythagorean theorem applied to the unit circle. It is universally true for any angle \(\alpha\).
When solving trigonometry problems, we often encounter a situation where we know one trigonometric value and need to find another. As in our example exercise, knowing \(\cos\alpha\) allowed us to find \(\sin\alpha\) using this identity. Similarly, we could determine \(\cos\beta\) given \(\sin\beta\). The identity is also critical in verifying the correctness of other trigonometric identities and in transforming trigonometric expressions into equivalent forms.
\[\sin^2\alpha + \cos^2\alpha = 1.\]
This identity reveals the intrinsic relationship between the sine and cosine functions and is derived from the Pythagorean theorem applied to the unit circle. It is universally true for any angle \(\alpha\).
When solving trigonometry problems, we often encounter a situation where we know one trigonometric value and need to find another. As in our example exercise, knowing \(\cos\alpha\) allowed us to find \(\sin\alpha\) using this identity. Similarly, we could determine \(\cos\beta\) given \(\sin\beta\). The identity is also critical in verifying the correctness of other trigonometric identities and in transforming trigonometric expressions into equivalent forms.
Other exercises in this chapter
Problem 60
Verify each identity. $$ \sin ^{2} \frac{\theta}{2}=\frac{\csc \theta-\cot \theta}{2 \csc \theta} $$
View solution Problem 60
Verify each identity. \(\frac{\sin x+\cos x}{\sin x}-\frac{\cos x-\sin x}{\cos x}=\sec x \csc x\)
View solution Problem 61
Solve each equation on the interval \([0,2 \pi)\) $$ \tan ^{2} x \cos x=\tan ^{2} x $$
View solution Problem 61
verify each identity. $$ 4 \cos x \cos 2 x \sin 3 x=\sin 2 x+\sin 4 x+\sin 6 x $$
View solution