Problem 61
Question
Find the dot product \langle-3,2\rangle\(\cdot\langle 2,5\rangle\) Solution: Multiply component by component. \(\langle-3,2\rangle \cdot\langle 2,5\rangle=\langle(-3)(2),(2)\rangle\) Simplify. \(\langle-3,2\rangle \cdot\langle 2,5\rangle=\langle-6,10\rangle\) This is incorrect. What mistake was made?
Step-by-Step Solution
Verified Answer
The mistake was in calculation of the dot product components. The correct dot product is 4.
1Step 1: Understand the Dot Product
The dot product (also known as the scalar product) of two vectors \(\langle a, b \rangle\) and \(\langle c, d \rangle\) is calculated as follows:\[ a \cdot c + b \cdot d \]
2Step 2: Apply the Dot Product Formula
Apply the dot product formula to the vectors \(-3, 2\) and \(2, 5\) as follows:\[-3 \cdot 2 + 2 \cdot 5 \]
3Step 3: Calculate Each Multiplication
Calculate each multiplication individually:- \(-3 \times 2 = -6\)- \(2 \times 5 = 10\)
4Step 4: Add the Results
Add the two results from Step 3:\[-6 + 10\]
5Step 5: Final Calculation
Calculate the sum:\[-6 + 10 = 4\]
Key Concepts
Dot ProductScalar ProductVectorsPrecalculus Concepts
Dot Product
The Dot Product, also known as the Scalar Product, is a fundamental operation in vector calculus. It combines two vectors to return a single number, or scalar. This operation is useful in many fields, including physics and computer graphics. The formula for the dot product of two vectors \(\langle a, b \rangle\) and \(\langle c, d \rangle\) is given by:
For example, given vectors \(\langle -3, 2 \rangle\) and \(\langle 2, 5 \rangle\), the dot product is calculated by multiplying corresponding components and summing the results. This leads to the scalar value \(-6 + 10 = 4\). The dot product can help determine whether two vectors are perpendicular. If the result is zero, the vectors are orthogonal.
- \(a \cdot c + b \cdot d\)
For example, given vectors \(\langle -3, 2 \rangle\) and \(\langle 2, 5 \rangle\), the dot product is calculated by multiplying corresponding components and summing the results. This leads to the scalar value \(-6 + 10 = 4\). The dot product can help determine whether two vectors are perpendicular. If the result is zero, the vectors are orthogonal.
Scalar Product
The Scalar Product is another name for the Dot Product. It results in a scalar rather than a vector, which means it only has magnitude and no direction. The scalar product is essential in understanding the relationship between two vectors.
This property makes the scalar product very handy in simplifying vector equations and computations in mathematical physics and engineering contexts.
- Think "dot" in terms of multiplication, as it combines elements multiplicatively.
- A scalar result simplifies complex vector interactions to a single value.
This property makes the scalar product very handy in simplifying vector equations and computations in mathematical physics and engineering contexts.
Vectors
Vectors are mathematical objects used to represent quantities that have both magnitude and direction. They are often depicted as arrows in a coordinate system. In a 2D coordinate plane, vectors are represented as \(\langle x, y \rangle\). Vectors are useful in a wide range of applications, from physics to engineering to computer graphics.
- The algebra of vectors involves operations such as addition, subtraction, and scalar multiplication.
- Vectors can be decomposed into components to simplify analysis in complex systems.
Precalculus Concepts
Precalculus is an essential building block for advanced mathematics. It introduces concepts that prepare students for calculus, such as functions, series, and importantly, vectors and their operations.
These concepts are not only fundamental in mathematics but also applicable in computing, physics, and engineering scenarios daily. Mastery of these ideas will ensure students are well-prepared for the challenges of calculus and beyond.
- Fundamental understanding of different types of numbers and operations sets the stage for calculus.
- Mastery of vector operations, like the dot product, is crucial for solving real-world problems.
These concepts are not only fundamental in mathematics but also applicable in computing, physics, and engineering scenarios daily. Mastery of these ideas will ensure students are well-prepared for the challenges of calculus and beyond.
Other exercises in this chapter
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