Problem 61
Question
Figure \(31-36\) shows an ac generator connected to a "black box" through a pair of terminals. The box contains an \(R L C\) circuit, possibly even a multiloop circuit, whose elements and connections we do not know. Measurements outside the box reveal that \(\mathscr{E}(t)=(75.0 \mathrm{~V}) \sin \omega_{d} t\) and \(i(t)=(1.20 \mathrm{~A}) \sin \left(\omega_{d} t+42.0^{\circ}\right)\) (a) What is the power factor? (b) Does the current lead or lag the emf? (c) Is the circuit in the box largely inductive or largely capacitive? (d) Is the circuit in the box in resonance? (e) Must there be a capacitor in the box? (f) An inductor? (g) A resistor? (h) At what average rate is energy delivered to the box by the generator? (i) Why don't you need to know \(\omega_{d}\) to answer all these questions?
Step-by-Step Solution
VerifiedKey Concepts
Power Factor
- Power factor formula: \( \cos(\phi) \)
- Indicates efficiency of power usage
- Important for reducing energy waste in electrical systems
Electrical Phase Angle
- Positive phase angle: current leads the voltage
- Negative phase angle: current lags the voltage
Average Power Calculation
\[ P_{avg} = V_{rms} \times I_{rms} \times \cos(\phi) \]
- \( V_{rms} \) and \( I_{rms} \) are obtained by dividing the peak values by \( \sqrt{2} \).
- The power factor \( \cos(\phi) \), calculated earlier, is crucial in determining the true power drawn by the circuit.
For the given values, \( V_{rms} = \frac{75.0}{\sqrt{2}} \) and \( I_{rms} = \frac{1.20}{\sqrt{2}} \). Substituting these into the formula gives \( P_{avg} \approx 31.5 \, \text{W} \). This quantifies the power being transferred in the circuit from the generator.
Inductive and Capacitive Reactance
- Inductive Reactance \( X_L \): Reactance that opposes changes in current, usually found in inductors.
- Formula: \( X_L = \omega L \) where \( \omega \) is the angular frequency and \( L \) is inductance.
- Capacitive Reactance \( X_C \): Reactance that opposes changes in voltage, usually found in capacitors.
- Formula: \( X_C = \frac{1}{\omega C} \) where \( C \) is capacitance.