Problem 61
Question
Evaluate each sum. $$\sum_{j=1}^{10}(2 j+3)$$
Step-by-Step Solution
Verified Answer
The sum is 140.
1Step 1: Understand the Problem
We are asked to evaluate the sum \( \sum_{j=1}^{10}(2j+3) \). This means we need to find the total by adding up the values of \(2j+3\) for each integer \(j\) from 1 to 10.
2Step 2: Write the First Few Terms
Let's identify the first few terms of the sequence by substituting \(j = 1, 2, 3, \dots, 10\) into \(2j + 3\). For example, when \(j=1\), the term is \(2(1) + 3 = 5\). When \(j=2\), the term is \(2(2) + 3 = 7\). Continue this for \(j=3, 4, \ldots, 10\).
3Step 3: Calculate Each Term
Evaluate each term in the sequence:- When \(j=1\), he term is \(5\).- When \(j=2\), the term is \(7\).- When \(j=3\), the term is \(9\).- When \(j=4\), the term is \(11\).- When \(j=5\), the term is \(13\).- When \(j=6\), the term is \(15\).- When \(j=7\), the term is \(17\).- When \(j=8\), the term is \(19\).- When \(j=9\), the term is \(21\).- When \(j=10\), the term is \(23\).
4Step 4: Add the Terms
Sum all the terms together: \(5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23\).
5Step 5: Simplify the Sum
Perform the addition step-by-step:- First pair and add: \(5+23=28\), \(7+21=28\), \(9+19=28\), \(11+17=28\), \(13+15=28\).- Sum these results: \(28\times5 = 140\).
6Step 6: Write the Final Answer
The sum \(\sum_{j=1}^{10}(2j+3)\) is \(140\).
Key Concepts
Summation NotationSequence CalculationSeries Evaluation
Summation Notation
Summation notation is a concise way of expressing the sum of a sequence of numbers. In mathematics, it is represented by the Greek letter sigma (\(\Sigma\)). This symbol is followed by an expression of the terms you want to sum. For example, \(\sum_{j=1}^{10}(2j+3)\) is asking us to calculate the sum of the formula \(2j+3\) where \(j\) takes on all integer values from 1 to 10.
Summation notation has three parts:
Summation notation has three parts:
- The lower limit of summation: This is the value where your sequence starts, such as \(j=1\).
- The upper limit of summation: This is where your sequence stops, like \(j=10\).
- The expression: What you are calculating for each successive value of \(j\), here it's \(2j+3\).
Sequence Calculation
The core task in evaluating a sum using summation notation involves calculating terms in a sequence. A sequence is simply a list of numbers in a particular order. In our example, each term in the sequence is given by the formula \(2j+3\), where \(j\) takes values from 1 to 10.
To calculate a sequence:
Each term results from plugging the values between 1 and 10 into the expression. Recognizing these individual terms helps in understanding how the sequence progresses and prepares us for finding the sum of the sequence.
To calculate a sequence:
- Substitute each successive value of \(j\) into the expression \(2j+3\).
- For example, when \(j=1\), the term is \(2(1)+3=5\), and when \(j=2\), the term equals \(2(2)+3=7\).
Each term results from plugging the values between 1 and 10 into the expression. Recognizing these individual terms helps in understanding how the sequence progresses and prepares us for finding the sum of the sequence.
Series Evaluation
Evaluating a series means finding the sum of its sequence. A series is essentially an expression for the sum of a sequence of numbers. In our example, the series is written through summation notation: \(\sum_{j=1}^{10}(2j+3)\).
For series evaluation:
For instance, pair 5 with 23, 7 with 21, and continue like that, each pair summing to 28 in this problem. Then multiplying the number of pairs (5) by the common pair sum (28) gives us the final answer, 140. This step-by-step formulation allows an organized and straightforward addition, leading us to the evaluated series sum.
For series evaluation:
- Calculate each term in the sequence first, as we've done previously, noting them down.
- Example terms are: 5, 7, 9, ..., 23.
- Proceed to add these numbers together to find the total sum.
For instance, pair 5 with 23, 7 with 21, and continue like that, each pair summing to 28 in this problem. Then multiplying the number of pairs (5) by the common pair sum (28) gives us the final answer, 140. This step-by-step formulation allows an organized and straightforward addition, leading us to the evaluated series sum.
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