Problem 61
Question
Determine whether the statement is true or false. Justify your answer. The domain of a logistic growth function cannot be the set of real numbers.
Step-by-Step Solution
Verified Answer
The statement is false. The domain of a logistic growth function can be the set of all real numbers because there are no real numbers that you can substitute into the function to make it undefined.
1Step 1: Understand a Logistic Function
Logistic functions are used in a variety of fields, including statistics, ecology, and economics, to express growth under constraints. When the x represents time, the logistic function yields a graph which starts with a phase of exponential growth before slowing and flattening out - ideal for representing situations where growth is initially rapid but then becomes constrained. It is typically expressed in the form \(y = \frac{c}{1 + ae^{-bx}}\), where c, a, and b are constants.
2Step 2: Reflect on the Domain and Real Numbers
The domain of a function includes all the possible values that the variable x can be, such that a y-value (output) can be determined by the function. The set of all real numbers includes all rational and irrational numbers, which essentially means any number on the number line.
3Step 3: Evaluate if the Domain of a Logistic Function can be the set of all Real Numbers
We need to determine whether there's any real number we can put in for x in the logistic growth function \(y = \frac{c}{1 + ae^{-bx}}\) that would make this function undefined. Looking closely, we see that the denominator of the fraction can never be zero because there's a '+1' added to \(ae^{-bx}\). Since dividing by zero is the only operation that would make the function undefined, we can safely say that logistic growth functions are defined for all real numbers.
Other exercises in this chapter
Problem 60
Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing utility to verify your answer. $$100 e^{0.005 x}=125,000
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Use a graphing utility to find the point(s) of intersection, if any, of the graphs of the functions. Round your result to three decimal places. $$\begin{aligned
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Use the properties of logarithms to expand the expression as a sum, difference, and/or constant multiple of logarithms. (Assume all variables are positive.) $$\
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Write the logarithmic equation in exponential form. For example, the exponential form of \(\ln 5=1.6094\). . . is \(e^{1.6094 \cdots}=5.\) $$\ln 6=1.7917 . . .$
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