Problem 61
Question
An organic compound is found to have the formula \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{ONCl}\). The percentage of nitrogen present in it is (a) \(23.36 \%\) (b) \(10.3 \%\) (c) \(41.05 \%\) (d) \(5.06 \%\)
Step-by-Step Solution
Verified Answer
The percentage of nitrogen present in the compound is (b) 10.3%.
1Step 1: Determine Atomic Masses
To solve this problem, first list the atomic masses of each element in the compound: Carbon (C) is approximately 12 g/mol, Hydrogen (H) is 1 g/mol, Oxygen (O) is 16 g/mol, Nitrogen (N) is 14 g/mol, and Chlorine (Cl) is 35.5 g/mol.
2Step 2: Calculate Molecular Mass
Calculate the compound's total molecular mass by multiplying each element's atomic mass by the number of its atoms in the formula, then summing them: \[ ext{Molecular mass} = (5 imes 12) + (10 imes 1) + (1 imes 16) + (1 imes 14) + (1 imes 35.5) \] Calculating gives: \[ 60 + 10 + 16 + 14 + 35.5 = 135.5 extrm{ g/mol} \]
3Step 3: Calculate Nitrogen's Mass Percentage
The mass of nitrogen in the compound is 14 g (1 N atom). The percentage mass of nitrogen is calculated as:\[ \text{Percentage of N} = \left( \frac{\text{mass of N}}{\text{total molecular mass}} \right) \times 100 = \left( \frac{14}{135.5} \right) \times 100 \] Calculating this gives approximately 10.33\%.
4Step 4: Select the Correct Answer
In the provided options, 10.3% is the closest value to our calculated percentage. Therefore, the correct answer is option (b) 10.3%.
Key Concepts
Molecular Mass CalculationOrganic CompoundsAtomic Mass Determination
Molecular Mass Calculation
Calculating the molecular mass of a compound helps us understand its composition on a quantitative level. This is essential for determining the mass percentage of each element in a compound. To calculate the molecular mass:
By calculating this, we gain insight into the quantitative relationships of all atoms in the compound.
- Identify the chemical formula of the compound, which indicates the number of each type of atom.
- Multiply the atomic mass of each element by the number of atoms of that element in the compound.
- Add these values together to obtain the total molecular mass.
By calculating this, we gain insight into the quantitative relationships of all atoms in the compound.
Organic Compounds
Organic compounds are primarily made of carbon and hydrogen atoms but may include other elements such as oxygen, nitrogen, halogens, etc. These compounds are fundamental to life and countless industrial applications. Organic molecules:
- Contain carbon-carbon bonds which form a variety of structures like chains, rings, and complex branches.
- Include functional groups that define their chemical properties and reactions.
- Have a vast array of configurations, making the study of their structural formulas crucial.
Atomic Mass Determination
Atomic mass is a key concept that defines the mass of an atom, usually expressed in atomic mass units (u). To determine the atomic mass, we rely on:
- Measurements relative to the carbon-12 isotope, setting it as the standard of exactly 12 u.
- The average mass of all isotopes for an element, since most elements have multiple isotopes.
- Referencing established values from periodic tables or scientific data sources.
Other exercises in this chapter
Problem 59
\(60 \mathrm{~g}\) of a compound on analysis produced \(24 \mathrm{~g}\) carbon, \(4 \mathrm{~g}\) hydrogen and \(32 \mathrm{~g}\) oxygen. The empirical formula
View solution Problem 60
Mark the incorrect statement in Kjeldahl's method of estimation of nitrogen (a) copper sulphate or mercury acts as a catalyst (b) nitrogen is quantitatively dec
View solution Problem 62
\(500 \mathrm{~mL}\) of a hydrocarbon gas burnt in excess of oxygen, gave \(2500 \mathrm{~mL}\) of \(\mathrm{CO}_{2}\) and \(3000 \mathrm{~mL}\) of water vapour
View solution Problem 63
The empirical formula of a compound is \(\mathrm{CH}_{2}\). One mole of the compound has a mass of \(42 \mathrm{~g}\), its molecular formula is (a) \(\mathrm{C}
View solution