Problem 61
Question
(a) In the Nernst equation, what is the numerical value of the reaction quotient, \(Q\), under standard conditions? (b) Can the Nernst equation be used at temperatures other than room temperature?
Step-by-Step Solution
Verified Answer
(a) The reaction quotient \( Q = 1 \) under standard conditions.
(b) Yes, the Nernst equation can be used at different temperatures.
1Step 1: Interpret the Problem
Understand what is being asked. Part (a) asks for the numerical value of the reaction quotient, \( Q \), under standard conditions. Part (b) is about the applicability of the Nernst equation at different temperatures.
2Step 2: Determine the Reaction Quotient Q Under Standard Conditions
Under standard conditions, the reaction quotient \( Q \) is defined such that each reactant and product concentration/activity is at its standard state. Therefore, \( Q = 1 \) under these conditions.
3Step 3: Review the Nernst Equation
The Nernst equation is given by: \[ E = E^0 - \frac{RT}{nF} \ln Q \]where \( E \) is the cell potential, \( E^0 \) is the standard cell potential, \( R \) is the ideal gas constant, \( T \) is the temperature in Kelvin, \( n \) is the number of moles of electrons exchanged, and \( F \) is Faraday's constant.
4Step 4: Evaluate the Temperature Dependency
The Nernst equation has a temperature term \( T \), which means it can be used at any temperature, not just room temperature. The equation accounts for different temperatures by including temperature in Kelvin in its formulation.
Key Concepts
Standard ConditionsReaction QuotientTemperature DependencyCell Potential
Standard Conditions
Under standard conditions, the state of the reactants and products is fixed to a standard state where each has a concentration of 1 M for solutions or a pressure of 1 atm for gases.
This simplifies calculations and provides a common reference point.When it comes to the Nernst equation, standard conditions offer significant scientific utility because:
This simplifies calculations and provides a common reference point.When it comes to the Nernst equation, standard conditions offer significant scientific utility because:
- The reaction quotient, denoted as \( Q \), equals 1. This is because each component in the reaction has its activity set to 1 in its standard state.
- By setting \( Q = 1 \), the Nernst equation reduces to \( E = E^0 \), where \( E^0 \) is the standard cell potential.
Reaction Quotient
The reaction quotient, or \( Q \), is a vital concept in electrochemistry. It quantitatively describes the relative amount of products and reactants in a chemical reaction at any given point.
- Mathematically, it's expressed as the ratio of the concentrations (or activities) of products to reactants, each raised to the power of their stoichiometric coefficients.
- In a balanced chemical reaction \( aA + bB \rightleftharpoons cC + dD \), the reaction quotient \( Q \) is written as: \[ Q = \frac{[C]^c [D]^d}{[A]^a [B]^b} \]
Temperature Dependency
The Nernst equation wonderfully incorporates temperature, highlighting its flexibility across a range of conditions:
- The equation includes a term \( T \), representing temperature in Kelvin, clearly indicating its significant role. At different temperatures, chemical reactions may speed up or slow down, altering the cell potential.
- Practically, the inclusion of temperature means that the Nernst equation can predict the potential of electrochemical cells even when the temperature is not at the standard 298 K (25°C or room temperature).
Cell Potential
Cell potential, often referred to as electromotive force (EMF), measures the potential difference between two electrodes in an electrochemical cell.Key aspects include:
- The cell potential \( E \) derived from the Nernst equation can help predict the direction and extent of a chemical reaction.
- Standard cell potential \( E^0 \) is obtained under standard conditions, providing a benchmark for comparison.
- The Nernst equation, \( E = E^0 - \frac{RT}{nF} \ln Q \), emphasizes how \( Q \) and temperature \( T \) influence \( E \). As reactions deviate from equilibrium, \( Q \) changes, thereby adjusting \( E \).
Other exercises in this chapter
Problem 58
At \(298 \mathrm{~K}\) a cell reaction has a standard cell potential of \(+0.63 \mathrm{~V}\). The equilibrium constant for the reaction is \(3.8 \times 10^{10}
View solution Problem 60
Consider the voltaic cell illustrated in Figure \(20.5,\) which is based on the cell reaction $$ \mathrm{Zn}(s)+\mathrm{Cu}^{2+}(a q) \longrightarrow \mathrm{Zn
View solution Problem 64
A voltaic cell utilizes the following reaction: $$ \mathrm{Al}(s)+3 \mathrm{Ag}^{+}(a q) \longrightarrow \mathrm{Al}^{3+}(a q)+3 \mathrm{Ag}(s) $$ What is the e
View solution Problem 67
A voltaic cell utilizes the following reaction: \(4 \mathrm{Fe}^{2+}(a q)+\mathrm{O}_{2}(g)+4 \mathrm{H}^{+}(a q) \longrightarrow 4 \mathrm{Fe}^{3+}(a q)+2 \mat
View solution