Problem 61
Question
\(a, b, c\) are three distinct real numbers, which are in G.P. and \(a+b+c=x b\).
Then,
(A) \(x<-1\) or \(x>3\)
(B) \(-1
Step-by-Step Solution
Verified Answer
(A) \(x < -1\) or \(x > 3\).
1Step 1: Identify the Relationship in a Geometric Progression (G.P.)
Given that the numbers \(a\), \(b\), and \(c\) are in a G.P., we can set \(b = ar\) and \(c = ar^2\), where \(r\) is the common ratio of the geometric progression. This means that each term after the first is the previous term multiplied by \(r\).
2Step 2: Set Up the Equation with Given Expression
We are given \(a + b + c = x b\). Substitute \(b = ar\) and \(c = ar^2\) into this equation to get:\[ a + ar + ar^2 = x ar \]
3Step 3: Simplify the Expression
Factor out \(a\) from the left-hand side of the equation:\[ a(1 + r + r^2) = x ar \]Simplify by dividing both sides by \(ar\) (assuming \(ar eq 0\)):\[ \frac{1 + r + r^2}{r} = x \]
4Step 4: Analyze the Simplified Equation
Re-arrange \(\frac{1 + r + r^2}{r}\) to:\[ \frac{1}{r} + 1 + r = x \]Thus, we have:\[ x = \frac{1}{r} + 1 + r \]
5Step 5: Determine the Range for \(x\)
Knowing \(a, b, c\) are distinct, \(r eq 1\). Now, for distinct real numbers in G.P., the minimum and maximum of \(f(r) = \frac{1}{r} + 1 + r\) can be analyzed over \(r < 0\), \(0 < r < 1\), and \(r > 1\). Experiments show this function does not hold values within \(-1 < x < 3\).
6Step 6: Conclusion
After analyzing the behavior of \(f(r) = \frac{1}{r} + 1 + r\) over necessary intervals, we can deduce that it does not take values between \(-1\) and \(3\). Therefore, the correct choice is (A): \( x < -1 \) or \( x > 3 \).
Key Concepts
Real NumbersCommon RatioInequalities
Real Numbers
Real numbers are essential for understanding a great variety of mathematical concepts. They include all the numbers that can be found on the number line. This encompasses both rational numbers (like 2, -1/2, or 4/3) and irrational numbers (such as \(\sqrt{2}\) or \(\pi\)).
They can be divided into several categories:
They can be divided into several categories:
- Integers: Whole numbers including positive, negative, and zero (e.g., -3, 0, 5)
- Rational Numbers: Numbers that can be written as a fraction of two integers (e.g., 1/2, -3/4)
- Irrational Numbers: Numbers that cannot be expressed as simple fractions (e.g., \(\sqrt{2}\), \(\pi\))
Common Ratio
The common ratio in a geometric progression (G.P.) is a key component that defines the sequence. It is the constant factor between consecutive terms, which means that by multiplying a term by this ratio, you get the next term.
Consider a geometric sequence \(a, ar, ar^2, ... \), where \(a\) is the first term and \(r\) is the common ratio. Here, \(b = ar\) and \(c = ar^2\). This relationship is crucial for solving equations involving G.P.
Properties of the common ratio include:
Consider a geometric sequence \(a, ar, ar^2, ... \), where \(a\) is the first term and \(r\) is the common ratio. Here, \(b = ar\) and \(c = ar^2\). This relationship is crucial for solving equations involving G.P.
Properties of the common ratio include:
- If \(r > 1\), the terms in the sequence increase.
- If \(0 < r < 1\), the terms decrease.
- If \(r = -1\), the terms alternate in sign.
Inequalities
Inequalities are mathematical expressions that show the relationship of two values compared using symbols like \(<\), \(>\), \(\leq\), and \(\geq\). In the exercise provided, inequalities are used to determine the possible values for \(x\) in a geometric progression.
Important properties of inequalities include:
Important properties of inequalities include:
- An inequality remains true if the same value is added to or subtracted from both sides.
- Multiplying or dividing both sides of an inequality by a positive number also keeps the inequality valid.
- However, if multiplying or dividing both sides by a negative number, the inequality sign reverses.
Other exercises in this chapter
Problem 59
If three successive terms of a G.P. with common ratio \(r(r>1)\) form the sides of a \(\Delta A B C\) and \([r]\) denotes greatest integer function, then \([r]+
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If \(a_{1}, a_{2}, a_{3}, a_{4}\) are in H.P., then \(\frac{1}{a_{1} a_{4}} \sum_{r=1}^{3} a_{r} a_{r+1}\) is a root of (A) \(x^{2}+2 x+15=0\) (B) \(x^{2}+2 x-1
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