Problem 60
Question
While sitting in your car by the side of a country road, you see your friend, who happens to have an identical car with an identical horn, approaching you. You blow your horn, which has a frequency of \(260 \mathrm{Hz} ;\) your friend begins to blow his horn as well, and you hear a beat frequency of 6.0 \(\mathrm{Hz} .\) How fast is your friend approaching you?
Step-by-Step Solution
Verified Answer
Your friend is approaching at approximately 6.99 m/s.
1Step 1: Understand the Problem and Given Information
We know that the frequency of your horn is \(f_s = 260 \, \text{Hz}\). You hear the beat frequency, which is the difference in frequencies from two sources, as \(f_{beat} = 6.0 \, \text{Hz}\). The Doppler effect affects your friend's horn frequency as it approaches you.
2Step 2: Establish Relationship Due to Doppler Effect
Since your friend is approaching, the sound frequency of the approaching source increases. We'll denote your friend's observed frequency as \(f_o\). For beats against your horn, \(f_o\) can be either \(266 \, \text{Hz}\) or \(254 \, \text{Hz}\) (260 Hz ± beat frequency of 6 Hz). Given that your friend's car approaches, \(f_o\) should be greater than \(f_s\). Thus, \(f_o = 266 \, \text{Hz}\).
3Step 3: Apply the Doppler Effect Formula
The frequency of sound from a source approaching an observer is given by:\[ f_o = \frac{v + v_o}{v - v_s} \cdot f_s \]where \(v\) is the speed of sound in air (approximately 343 m/s), \(v_o\) is the observer's velocity (your velocity here is 0 m/s), \(v_s\) is the source's velocity (your friend's car), and \(f_s\) is the original frequency of 260 Hz. We need to solve for \(v_s\) when \(f_o = 266 \, \text{Hz}\).
4Step 4: Solve for Friend's Velocity
Since you are stationary (observer velocity \(v_o = 0\)), the formula simplifies to:\[ 266 = \frac{343}{343 - v_s} \cdot 260\]Rearrange and solve the equation:\[ 266(343 - v_s) = 343 \times 260 \ 91038 - 266v_s = 89180 \ 1858 = 266v_s \ v_s = \frac{1858}{266} \approx 6.99 \, \text{m/s} \]Your friend is approaching at approximately 6.99 m/s.
Key Concepts
Beat FrequencySound FrequencyObserver VelocitySpeed of Sound
Beat Frequency
The concept of beat frequency occurs when two sound waves of slightly different frequencies interfere with each other. This interference produces a fluctuating sound whose frequency is the difference between the two original frequencies. This is known as the beat frequency.
In practical terms, if you have two horns sounding, each with frequencies close to each other, but not identical, you would hear a variation in sound intensity as the waves continuously go in and out of phase. This is the beat you've noticed: it has a frequency equal to the absolute value of the difference between the two frequencies.
In practical terms, if you have two horns sounding, each with frequencies close to each other, but not identical, you would hear a variation in sound intensity as the waves continuously go in and out of phase. This is the beat you've noticed: it has a frequency equal to the absolute value of the difference between the two frequencies.
- If you're hearing a beat frequency of 6 Hz, this means the two frequencies could either add up to this difference above or below the stationary frequency. For example, if a horn has a frequency of 260 Hz, then possible heard frequencies could be 254 Hz or 266 Hz.
Sound Frequency
Sound frequency relates to the number of vibrations or cycles that occur per unit of time. It is often measured in Hertz (Hz), which corresponds to one cycle per second.
In the context of the problem, sound frequency directly ties into the idea of an object's motion. Our exercises demonstrate two horns with frequencies, where the motion of one horn affects its perceived frequency.
In the context of the problem, sound frequency directly ties into the idea of an object's motion. Our exercises demonstrate two horns with frequencies, where the motion of one horn affects its perceived frequency.
- Your horn, for example, has a stationary sound frequency of 260 Hz.
- Your friend's perceived horn frequency while moving is different due to the Doppler effect.
Observer Velocity
Observer velocity refers to the speed at which an observer is moving towards or away from a sound source. In Doppler effect phenomena, this velocity can significantly alter how the sound frequency is perceived.
- A stationary observer will hear the frequency as it is emitted from the source.
- An observer moving towards the source perceives a higher frequency due to compressed sound waves.
- In the exercise, you acted as a stationary observer, meaning your observer velocity was 0 m/s, whereas your friend's movement caused a change in frequency perception.
Speed of Sound
The speed of sound is the rate at which a sound wave travels through a medium. In air, at room temperature, it is typically around 343 meters per second.
This speed is a crucial factor in the Doppler effect formula and calculations.
This speed is a crucial factor in the Doppler effect formula and calculations.
- It determines how quickly sound waves reach an observer from a moving source, such as a vehicle horn.
- In the step-by-step exercise, the speed of sound acts as a reference that shifts frequencies based on relative motion between the observer and the source.
Other exercises in this chapter
Problem 58
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