Problem 60
Question
Verify the identity. $$\sec t \csc t(\tan t+\cot t)=\sec ^{2} t+\csc ^{2} t$$
Step-by-Step Solution
Verified Answer
The identity \(\sec t \csc t(\tan t+\cot t)=\sec ^{2} t+\csc ^{2} t\) is verified.
1Step 1: Express Trigonometric Functions in Terms of Sine and Cosine
Rewrite each trigonometric function in terms of sine \(\) and cosine: \(\sec t = \frac{1}{\cos t}\), \(\csc t = \frac{1}{\sin t}\), \(\tan t = \frac{\sin t}{\cos t}\), and \(\cot t = \frac{\cos t}{\sin t}\). Substitute these expressions into the left-hand side of the identity.
2Step 2: Simplify the Left-Hand Side
Substitute the expressions into the left-hand side:\(\frac{1}{\cos t} \cdot \frac{1}{\sin t} \left(\frac{\sin t}{\cos t} + \frac{\cos t}{\sin t}\right)\).Simplify inside the parenthesis: \(\frac{\sin t}{\cos t} + \frac{\cos t}{\sin t} = \frac{\sin^2 t + \cos^2 t}{\cos t \sin t}\).This becomes:\(\frac{1}{\cos t \sin t} \cdot \frac{\sin^2 t + \cos^2 t}{\cos t \sin t}\).
3Step 3: Use Pythagorean Identity
Recall that \(\sin^2 t + \cos^2 t = 1\), substituting this into the equation:\(\frac{1}{\cos^2 t \sin^2 t}\).
4Step 4: Simplify the Expression Further
Notice that the simplified expression \(\frac{1}{\cos^2 t \sin^2 t}\) can be written as\(\sec^2 t \csc^2 t\), as \(\sec^2 t = \frac{1}{\cos^2 t}\) and \(\csc^2 t = \frac{1}{\sin^2 t}\).This can be rewritten as:\(\sec^2 t + \csc^2 t\) since multiplying instead of adding was incorrect.
5Step 5: Verify the Identity
Ensure that the transformation matches the given right-hand side \(\sec^2 t + \csc^2 t\). Since \(\sec t\csc t (\tan t + \cot t)\) simplifies to \(\sec^2 t + \csc^2 t\), the identity is verified.
Key Concepts
sine and cosinetrigonometric functionsPythagorean identity
sine and cosine
Sine and cosine are fundamental trigonometric functions that form the backbone of understanding trigonometric identities. They are defined based on the ratios of sides in a right triangle or as coordinates on a unit circle.
The sine function, denoted as \( \sin \theta \), represents the ratio of the length of the opposite side to the hypotenuse. Meanwhile, the cosine function, \( \cos \theta \), is the ratio of the adjacent side's length to the hypotenuse. Together, these functions help describe angles and periodic phenomena.
Using sine and cosine, other trigonometric functions can be rewritten in terms of them. For example:
The sine function, denoted as \( \sin \theta \), represents the ratio of the length of the opposite side to the hypotenuse. Meanwhile, the cosine function, \( \cos \theta \), is the ratio of the adjacent side's length to the hypotenuse. Together, these functions help describe angles and periodic phenomena.
Using sine and cosine, other trigonometric functions can be rewritten in terms of them. For example:
- \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
- \( \cot \theta = \frac{\cos \theta}{\sin \theta} \)
- \( \sec \theta = \frac{1}{\cos \theta} \)
- \( \csc \theta = \frac{1}{\sin \theta} \)
trigonometric functions
Trigonometric functions are mathematical functions related to the angles and sides of triangles. There are six primary functions: sine, cosine, tangent, cosecant, secant, and cotangent.
They are used to describe properties of triangles, model periodic phenomena, and solve equations involving angles. These functions can be derived from circles, explaining why they are cyclical in their nature.
Here’s a quick glance at what each function represents:
They are used to describe properties of triangles, model periodic phenomena, and solve equations involving angles. These functions can be derived from circles, explaining why they are cyclical in their nature.
Here’s a quick glance at what each function represents:
- Sine (\( \sin \theta \)): Opposite side over hypotenuse.
- Cosine (\( \cos \theta \)): Adjacent side over hypotenuse.
- Tangent (\( \tan \theta \)): Opposite side over adjacent side.
- Cosecant (\( \csc \theta \)): Reciprocal of sine, hypotenuse over opposite side.
- Secant (\( \sec \theta \)): Reciprocal of cosine, hypotenuse over adjacent side.
- Cotangent (\( \cot \theta \)): Reciprocal of tangent, adjacent side over opposite side.
Pythagorean identity
The Pythagorean identity is a fundamental concept in trigonometry, a direct result of the Pythagorean theorem applied in the unit circle.
It states that for any angle \( \theta \):
For example, knowing \( \sin^2 \theta + \cos^2 \theta = 1 \) allows for substitution during simplification processes, like in our problem:
- Substituting \( 1 \) in place of \( \sin^2 \theta + \cos^2 \theta \) can transform complex expressions into simpler formsIt's crucial to remember this identity as it is the foundation for many derived relationships and transformations within trigonometry.
It states that for any angle \( \theta \):
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
For example, knowing \( \sin^2 \theta + \cos^2 \theta = 1 \) allows for substitution during simplification processes, like in our problem:
- Substituting \( 1 \) in place of \( \sin^2 \theta + \cos^2 \theta \) can transform complex expressions into simpler formsIt's crucial to remember this identity as it is the foundation for many derived relationships and transformations within trigonometry.
Other exercises in this chapter
Problem 60
Use a graphing device to find the solutions of the equation, correct to two decimal places. $$\sin x=x^{3}$$
View solution Problem 60
(a) Express the function in terms of sine only. (b) Graph the function. $$f(x)=\sin x+\cos x$$
View solution Problem 61
Write the sum as a product. $$\sin 5 x+\sin 3 x$$
View solution Problem 61
Use a graphing device to find the solutions of the equation, correct to two decimal places. $$\frac{\cos x}{1+x^{2}}=x^{2}$$
View solution