Problem 60
Question
verify each identity. $$ \frac{\sin 2 x+(\sin 3 x+\sin x)}{\cos 2 x+(\cos 3 x+\cos x)}=\tan 2 x $$
Step-by-Step Solution
Verified Answer
After the simplification process, it is found that the left side becomes \( \tan 2x \), which confirms the given identity of \( \frac{\sin 2x + (\sin 3x + \sin x)}{\cos 2x + (\cos 3x + \cos x)} = \tan 2x \).
1Step 1: Simplify the numerator and denominator
The first step is to simplify the numerator (the top part) and the denominator of the left side of the equation. Using the double-angle formula of \( \sin(2x) \), it can be written as \( 2 \sin x \cos x \). Similarly, using the double-angle formula of \( \cos(2x) \), it can be written as \( 1- 2 \sin^{2} x \) or \( 2 \cos^{2} x - 1 \). However, observe that in the denominator, there are three cosine terms, so it is advisable to use the second formula \( 2 \cos^{2} x - 1 \) to keep the denominator in terms of cosine. Apply these substitutions to the original equation.
2Step 2: Group the terms
After applying the substitutions in previous step, the left side of the equation appears complex. So group the terms of \( \sin x \) together and \( \cos x \) together in the numerator as well as in the denominator.
3Step 3: Factor out common terms
In the numerator and the denominator, there are common terms which can be factored out. In particular, factor \( \sin x \) from the numerator and \( \cos x \) from the denominator.
4Step 4: Simplify the left side
Now you can simplify the left side of the expression by dividing the numerator and the denominator by the common terms factored out, which will simplify the expression greatly. After simplifying, you will find that the left side matches the right side of the original equation, confirming the given identity.
Key Concepts
Double-Angle FormulasSine and Cosine FunctionsAlgebraic Manipulations
Double-Angle Formulas
The double-angle formulas are key identities in trigonometry that express trigonometric functions of double angles (like \(2x\)) in terms of single angles (like \(x\)). They simplify complex trigonometric expressions and are essential for solving problems more efficiently.
- Double-Angle Formula for Sine: \( \sin(2x) = 2 \sin(x) \cos(x) \). This is quite helpful because it breaks down the function of a double angle, transforming it into a product of sine and cosine functions of a single angle.
- Double-Angle Formula for Cosine: There are multiple forms, but one useful version is \( \cos(2x) = 2 \cos^2(x) - 1 \). It shows how a double angle cosine can be expressed using square of the cosine function, which can be manipulated based on the need of the simplification.
Sine and Cosine Functions
Understanding sine and cosine functions is crucial for mastering trigonometry. They are the most fundamental trigonometric functions and are involved in defining other trigonometric identities.
- Sine Function: Denoted as \( \sin(x) \), it represents the y-coordinate of a point on the unit circle as the point moves along the circumference starting from the positive x-axis.
- Cosine Function: Denoted as \( \cos(x) \), it represents the x-coordinate of a point on the unit circle following a similar path as sine but focusing on the position along the x-axis.
Algebraic Manipulations
Algebraic manipulations are operations you perform to simplify expressions or equations. In trigonometry, these manipulations help in verifying identities by simplifying complex expressions. Here are a few common techniques used:
- Factoring: Looking at an expression and identifying common terms that can be factored out, like factoring \( \sin(x) \) out of several terms in a sum.
- Grouping: The strategy of organizing terms to simplify the expression. For example, grouping terms involving \( \sin(x) \) or \( \cos(x) \) together can make subsequent steps like factoring clearer.
- Simplifying: Combining like terms or reducing fractions by the greatest common divisor. This step often follows factoring and grouping.
Other exercises in this chapter
Problem 60
Find the exact value of the following under the given conditions: a. \(\cos (\alpha+\beta)\) b. \(\sin (\alpha+\beta)\) c. \(\tan (\alpha+\beta)\) \(\tan \alpha
View solution Problem 60
Solve each equation on the interval \([0,2 \pi)\) $$ \cos x-2 \sin x \cos x=0 $$
View solution Problem 60
Verify each identity. $$ \sin ^{2} \frac{\theta}{2}=\frac{\csc \theta-\cot \theta}{2 \csc \theta} $$
View solution Problem 60
Verify each identity. \(\frac{\sin x+\cos x}{\sin x}-\frac{\cos x-\sin x}{\cos x}=\sec x \csc x\)
View solution