Problem 60
Question
Use the given information to write an equation. Let \(x\) represent the number described in each exercise. Then solve the equation and find the number. If a number is multiplied by \(-6,\) the result is \(20 .\) Find the number.
Step-by-Step Solution
Verified Answer
The number is 15.
1Step 1: Formulation of Equation
Begin by translating the given information into an algebraic equation. The problem states that if 23 is subtracted from a certain number, the result is -8. We can express this with \(x\) representing the unknown number, giving us the equation: \(x - 23 = -8\).
2Step 2: Solving the Equation
To isolate \(x\) and solve for it, add 23 to both sides of the equation. This gives: \(x = -8 + 23\).
3Step 3: Finding the Number
Finally, perform the operation on the right hand side to find the value of \(x\). This results in: \(x = 15\).
Key Concepts
Solving EquationsUnknown VariablesInteger Operations
Solving Equations
Equations are mathematical statements that assert the equality of two expressions. In solving equations, our goal is to find the values of the unknowns that make the equation true. Let's walk through the process using the example: \(x - 23 = -8\). Solving equations generally involves a few logical steps:
Adding 23 gives us: \(x = -8 + 23\). The calculations are simplified, leading us to the solution \(x = 15\). Always verify your solution by plugging it back into the original equation to ensure it satisfies all given conditions.
- Identify the equation that needs to be solved.
- Use appropriate operations to isolate the unknown variable on one side of the equation.
- Perform arithmetic operations to simplify the equation.
Adding 23 gives us: \(x = -8 + 23\). The calculations are simplified, leading us to the solution \(x = 15\). Always verify your solution by plugging it back into the original equation to ensure it satisfies all given conditions.
Unknown Variables
Variables play a crucial role in algebra. They are symbols used to represent unknown values or numbers. In our exercise, \(x\) is the unknown variable representing the number we're trying to find. Understanding the concept of variables is fundamental in translating real-world scenarios into algebraic expressions and equations.
Variables allow for flexibility and generalization in mathematics:
The clarity and logic that come from understanding variables are indispensable tools in algebra and beyond.
Variables allow for flexibility and generalization in mathematics:
- They make it possible to express problems in a general way, applicable to various situations.
- Variables stand in place of unknowns until we use mathematical methods to solve for them.
The clarity and logic that come from understanding variables are indispensable tools in algebra and beyond.
Integer Operations
Integer operations are basic but essential arithmetic actions involving whole numbers both positive and negative. In the context of solving equations like \(x - 23 = -8\), understanding integer operations helps simplify and solve equations accurately.
Let's consider integer addition as it applies to our exercise:
This operation requires understanding that moving along the number line, adding a larger positive number to a smaller negative one results in a positive number, hence \(x = 15\). Recognizing the properties of integers simplifies the challenge of solving algebraic equations by enabling accurate computational steps.
Let's consider integer addition as it applies to our exercise:
- Addition of a negative integer is equivalent to subtraction of its positive counterpart (e.g., adding -8 is the same as subtracting 8).
- Addition of a series of integers follows the associative and commutative laws, allowing flexible grouping and reordering of numbers.
This operation requires understanding that moving along the number line, adding a larger positive number to a smaller negative one results in a positive number, hence \(x = 15\). Recognizing the properties of integers simplifies the challenge of solving algebraic equations by enabling accurate computational steps.
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