Problem 60
Question
Use the given conditions to determine in which quadrant of a rectangular coordinate system each point \((x, y)\) is located. \(x>0\) and \(y>0\)
Step-by-Step Solution
Verified Answer
The point
(x, y)
with
x>0
and
y>0
is located in Quadrant I.
1Step 1: Understanding the Coordinate System
In a rectangular coordinate system, also known as the Cartesian coordinate plane, there are four quadrants that are formed by two perpendicular lines called axes: the x-axis (horizontal) and the y-axis (vertical). The quadrants are numbered counterclockwise starting from the upper right quadrant.
2Step 2: Identifying the Quadrants
The quadrants of the coordinate plane are designated as follows: Quadrant I is where both x and y are positive (
x>0, y>0
), Quadrant II is where x is negative and y is positive (
x<0, y>0
), Quadrant III is where both x and y are negative (
x<0, y<0
), and Quadrant IV is where x is positive and y is negative (
x>0, y<0
).
3Step 3: Applying the Given Condition
Using the given conditions, where
x>0
and
y>0
, we look at which quadrants x and y belong to based on the signs of their values. Both x being positive and y being positive occurs only in Quadrant I.
Key Concepts
Cartesian coordinate systemquadrant identificationpositive and negative values
Cartesian coordinate system
The Cartesian coordinate system is central to many areas of mathematics and science. It provides a grid-like framework, formed by two perpendicular axes. The horizontal axis is the x-axis, and the vertical axis is the y-axis. These axes intersect at a point known as the origin, denoted by
(0, 0).
Each point in this system is determined by a pair of numerical values, or coordinates, written as (x, y). The first number represents the position relative to the x-axis, while the second denotes the position relative to the y-axis.
For example, the point (3, 4) means moving 3 units along the x-axis and 4 units up the y-axis. This system allows for precise location of points within a two-dimensional plane.
Each point in this system is determined by a pair of numerical values, or coordinates, written as (x, y). The first number represents the position relative to the x-axis, while the second denotes the position relative to the y-axis.
For example, the point (3, 4) means moving 3 units along the x-axis and 4 units up the y-axis. This system allows for precise location of points within a two-dimensional plane.
quadrant identification
Knowing how to identify quadrants in the Cartesian coordinate system is crucial for understanding how points are located on a plane. The system divides the plane into four regions, called quadrants. They go counterclockwise starting from the upper right part of the plane.
Here's a simple way to remember them:
Here's a simple way to remember them:
- **Quadrant I**: Both x and y values are positive, (x > 0, y > 0).
- **Quadrant II**: x-values are negative, y-values are positive, (x < 0, y > 0).
- **Quadrant III**: Both x and y values are negative, (x < 0, y < 0).
- **Quadrant IV**: x-values are positive, y-values are negative, (x > 0, y < 0).
positive and negative values
Positive and negative values in the Cartesian coordinate system are essential in determining the position of points. These values indicate direction as well as distance from the origin.
**Positive Values**:
**Negative Values**:
**Positive Values**:
- For x-values, if x is positive, the point is to the right of the y-axis.
- For y-values, if y is positive, the point is above the x-axis.
**Negative Values**:
- For x-values, if x is negative, the point is to the left of the y-axis.
- For y-values, if y is negative, the point is below the x-axis.
Other exercises in this chapter
Problem 59
Solve each inequality. Graph the solution set and write it using interval notation. $$ 3(z-2) \leq 2(z+7) $$
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Solve each inequality. Graph the solution set and write it using interval notation. $$ 5(3+z)>-3(z+3) $$
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Solve each compound inequality, if possible. Graph the solution set (if one exists) and write it using interval notation. \(2(-2) \leq 3 x-1\) and \(3 x-1 \leq-
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