Problem 60
Question
The remainder and factor theorems are true for any complex value of \(c\). Therefore, for Problems \(56-58\), find \(f(c)\) by (a) using synthetic division and the remainder theorem, and (b) evaluating \(f(c)\) directly. $$ \text { Show that } x+3 i \text { is a factor of } f(x)=x^{4}+14 x^{2}+45 \text {. } $$
Step-by-Step Solution
Verified Answer
Yes, \( x+3i \) is a factor of \( f(x) \).
1Step 1: Identify function and divisor
First, identify the polynomial function \( f(x) = x^4 + 14x^2 + 45 \) and the divisor \( c = -3i \). We need to check if \( x + 3i \) is a factor of \( f(x) \), which is equivalent to checking if \( f(-3i) = 0 \).
2Step 2: Apply synthetic division
Perform synthetic division of \( f(x) \) by \( x + 3i \). Use \( c = -3i \) for the synthetic division setup. Start with the coefficients of \( f(x) \), which are \( 1, 0, 14, 0, 45 \), where the missing \( x^3 \) and \( x^1 \) terms are represented with zeroes.
3Step 3: Perform synthetic division computation
With \( -3i \) as the divisor:1. Bring down the leading coefficient: \( 1 \).2. Multiply \( 1 \) by \( -3i \), add to the next coefficient: result is \( 0 \).3. Multiply result by \( -3i \), add to the next coefficient: \( 14 \).4. Multiply result by \( -3i \), add to the next coefficient: \( 0 \).5. Multiply result by \( -3i \), add to the final coefficient \( 45 \).The remainder is computed to be \( 0 \).
4Step 4: Remainder theorem conclusion
According to the remainder theorem, if the remainder is zero, then \( x+3i \) is a factor of \( f(x) \). Since the remainder from synthetic division is \( 0 \), this confirms that \( x+3i \) is indeed a factor.
5Step 5: Evaluate \( f(c) \) directly
Substitute \( c = -3i \) into the polynomial:\[ f(-3i) = (-3i)^4 + 14(-3i)^2 + 45. \]Calculate each term:- \((-3i)^4 = 81\) because \((-3i)^4 = ((-3i)^2)^2 = (9)^2 = 81\).- \(14(-3i)^2 = 14(-9) = -126\).- So, \( f(-3i) = 81 - 126 + 45 = 0 \).
6Step 6: Direct evaluation conclusion
The direct evaluation confirms that \( f(-3i) = 0 \). This also implies that \( x+3i \) is a factor of \( f(x) \), consistent with our earlier synthetic division result.
Key Concepts
Synthetic Division ExplainedRemainder Theorem BasicsUnderstanding Complex Numbers
Synthetic Division Explained
Synthetic Division is a shortcut method for dividing a polynomial by a binomial of the form \( x - c \). It is a more efficient alternative to long division for this purpose, and it's particularly useful when dealing with polynomials of higher degrees.
To perform Synthetic Division, follow these steps:
To perform Synthetic Division, follow these steps:
- Identify the coefficients of the polynomial. It's crucial to include placeholders (zeroes) for any missing terms.
- Pick the value of \( c \) from the divisor \( x - c \) or \( x + 3i \) as in our problem.
- Write the coefficients in a row and bring the first coefficient down as is.
- Multiply the down number by \( c \) and add the result to the next coefficient.
- Repeat this multiplication and addition process for each coefficient.
- The final number obtained is the remainder from the division.
Remainder Theorem Basics
The Remainder Theorem is a straightforward yet powerful concept in polynomial mathematics. It states that for any polynomial \( f(x) \) divided by \( x - c \), the remainder of this division is \( f(c) \).
This tells us something crucial: To know if \( x - c \) is a factor of \( f(x) \), simply evaluate \( f(c) \). If \( f(c) = 0 \), then \( x - c \) is a factor of \( f(x) \); otherwise, it is not. Remember, a factor leaves no remainder!
In our problem, we evaluate \( f(c) \) for the value \( c = -3i \):
This tells us something crucial: To know if \( x - c \) is a factor of \( f(x) \), simply evaluate \( f(c) \). If \( f(c) = 0 \), then \( x - c \) is a factor of \( f(x) \); otherwise, it is not. Remember, a factor leaves no remainder!
In our problem, we evaluate \( f(c) \) for the value \( c = -3i \):
- Plug \( -3i \) into the polynomial and perform the necessary calculations.
- If the result is zero, \( x + 3i \) is confirmed to be a factor.
Understanding Complex Numbers
Complex Numbers are a type of number that includes the regular real number, as well as an imaginary unit \( i \), where \( i^2 = -1 \). They are typically expressed in the form \( a + bi \) where \( a \) and \( b \) are real numbers.
Complex Numbers allow us to solve polynomial equations that do not have solutions in the realm of Real numbers alone. This is essential for ensuring that every polynomial equation has a solution, known as the Fundamental Theorem of Algebra.
In our exercise, \( x + 3i \) is used to determine if it's a factor of the polynomial \( f(x) \). Complex arithmetic involves:
Complex Numbers allow us to solve polynomial equations that do not have solutions in the realm of Real numbers alone. This is essential for ensuring that every polynomial equation has a solution, known as the Fundamental Theorem of Algebra.
In our exercise, \( x + 3i \) is used to determine if it's a factor of the polynomial \( f(x) \). Complex arithmetic involves:
- Adding and subtracting complex numbers by combining their real and imaginary components separately.
- Multiplying involves using the distributive property, remembering \( i^2 = -1 \), and simplifying.
Other exercises in this chapter
Problem 57
The remainder and factor theorems are true for any complex value of \(c\). Therefore, for Problems \(56-58\), find \(f(c)\) by (a) using synthetic division and
View solution Problem 58
The remainder and factor theorems are true for any complex value of \(c\). Therefore, for Problems \(56-58\), find \(f(c)\) by (a) using synthetic division and
View solution Problem 56
The remainder and factor theorems are true for any complex value of \(c\). Therefore, for Problems \(56-58\), find \(f(c)\) by (a) using synthetic division and
View solution