Problem 60
Question
The angle of elevation from the top of a house to a jet flying 2 miles above
the house is \(x\) radians. If \(d\) represents the horizontal distance, in miles,
of the jet from the house, express \(d\) in terms of a trigonometric function of
\(x .\) Then graph the function for \(0
Step-by-Step Solution
Verified Answer
The horizontal distance, \(d\), of the jet from the house can be expressed in terms of a trigonometric function of the angle of elevation, \(x\), as \(d =\frac{2}{\tan(x)}\). This function can be graphed in the interval \(0 < x < \pi\).
1Step 1: Understand and visualize the problem
This step involves understanding the problem and visualizing it. Visualize a right triangle, where the house and the jet form the two non-right angles of the triangle. The height of the jet above the house is the side opposite the angle of elevation and the horizontal distance between the jet and the house is the side adjacent to the angle.
2Step 2: Formulate the equation
With the concept of trigonometry, it is known that the tangent of any angle is the ratio of the length of the side opposite the angle to the length of the adjacent side. Therefore, in the right triangle that represents the scenario in the problem, the tangent of the angle of elevation (\(x\)) is equal to the ratio of the height of the jet from the house (2 miles) to the horizontal distance of the jet from the house (\(d\)). Therefore, \(\tan(x) =\frac{2}{d}\).
3Step 3: Express \(d\) in terms of \(x\)
By rearranging the equation obtained in the previous step, it can be expressed \(d\) in terms of \(x\). That is \(d =\frac{2}{\tan(x)}\).
4Step 4: Graph the function
A the function \(d(x) =\frac{2}{\tan(x)}\) is a reciprocal trigonometric function, which need to be graphed in the interval \(0 < x < \pi\). This interval excludes the values of \(x\) that make the denominator zero. The graph of the function will show how the horizontal distance of the jet from the house changes as the angle of elevation changes within the specified interval.
Key Concepts
Angle of ElevationRight TriangleTangent Function
Angle of Elevation
When you look up at an object from a lower point, the angle you tilt your head is known as the angle of elevation. It's an angle formed between the line of sight from your eyes to the object and the horizontal line from your eyes. The angle of elevation is crucial in problems involving measurements from a lower point to a higher point.
For example:
For example:
- You are standing outside, looking up at a plane. The angle your line of sight makes with the horizontal is the angle of elevation.
- You need to note that the angle of elevation is measured from the horizontal line upward to the object.
Right Triangle
Right triangles are a critical component in understanding geometry and trigonometry. A right triangle is a triangle that has one angle equal to 90 degrees. This feature allows us to use the Pythagorean theorem and basic trigonometric functions.
- The legs of a right triangle are the two sides that form the right angle.
- The hypotenuse is the longest side opposite the right angle.
- Problems involving right triangles frequently involve calculating the lengths of sides or the measures of angles using trigonometric functions.
- The vertical side, which is the height of the jet above the house (2 miles).
- The horizontal side, which is the distance we aim to calculate, represented as "d" in the equation.
- This arrangement nicely fits into using trigonometric functions to solve for unknown distances.
Tangent Function
Trigonometric functions help relate the angles and sides of a triangle. The tangent function, often abbreviated as "tan," is particularly useful in right triangles. The tangent of an angle in a right triangle is the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle.
- If you know the angle and one side, you can use the tangent function to find the other side.
- Mathematically, it is expressed as: \( \tan(x) = \frac{\text{opposite}}{\text{adjacent}} \).
- \( \tan(x) = \frac{2}{d} \), where 2 is the height from the house to the jet.
- To find the horizontal distance \( d \), we can rearrange this equation: \( d = \frac{2}{\tan(x)} \).
Other exercises in this chapter
Problem 60
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find the reference angle for each angle. $$ -\frac{13 \pi}{3} $$
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