Problem 60
Question
Statement 1 : The variance of first \(n\) odd natural numbers is \(\frac{n^{2}-1}{3}\) Statement 2: The sum of first \(\mathrm{n}\) odd natural number is \(n^{2}\) and the sum of square of first \(n\) odd natural numbers is \(\frac{n\left(4 n^{2}+1\right)}{3}\). Online May 26, 2012] (a) Statement 1 is true, Statement 2 is false. (b) Statement 1 is true, Statement 2 is true; Statement 2 is not a correct explanation for Statement \(1 .\) (c) Statement 1 is false, Statement 2 is true. (d) Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1 .
Step-by-Step Solution
Verified Answer
(b) Statement 1 is true, Statement 2 is true; Statement 2 is not a correct explanation for Statement 1.
1Step 1: Understanding Statement 1
Statement 1 claims that the variance of the first \(n\) odd natural numbers is \(\frac{n^2 - 1}{3}\). We'll first derive the formula for variance.
2Step 2: Calculate Mean of Odd Numbers
The first \(n\) odd natural numbers are \(1, 3, 5, \ldots, (2n-1)\). Their sum is \(n^2\) from the formula in Statement 2, so the mean \(\mu\) is \(\frac{n^2}{n} = n\).
3Step 3: Calculate Sum of Squares
The sum of the squares of the first \(n\) odd natural numbers is given by Statement 2 as \(\frac{n(4n^2 + 1)}{3}\).
4Step 4: Find the Variance
Variance is calculated as \(\text{Variance} = \frac{1}{n} \left( \sum x_i^2 - n\mu^2 \right)\), where \(\mu = n\) from earlier. Substitute the sum of squares to get:\[\text{Variance} = \frac{1}{n} \left( \frac{n(4n^2 + 1)}{3} - n \times n^2 \right) = \frac{n(4n^2 + 1) - 3n^3}{3n} = \frac{n(4n^2+1) - 3n^3}{3n} = \frac{n^4 + n}{3n} = \frac{4n^3 + n - 3n^3}{3n} = \frac{n^2 - 1}{3}.\]
5Step 5: Verify Statement 2
Statement 2 states the sum of the first \(n\) odd numbers is \(n^2\) and sum of squares is \(\frac{n(4n^2 + 1)}{3}\). These are both standard formulas and correct, thus Statement 2 is true.
6Step 6: Determine the Relation Between Statements
Even though Statement 2 is true and correct, it simply provides the formulas. The relationship that variance calculation requires these formulas does not imply Statement 2 is an explanation for Statement 1. Therefore, if both statements are true, Statement 2 is not a correct explanation for Statement 1.
Key Concepts
Odd NumbersSum of SquaresMathematical ProofMean Calculation
Odd Numbers
Odd numbers are fascinating numbers that cannot be evenly divided by 2. When talking about odd numbers, we are referring to the sequence that begins with
This sequence is foundational in computing sums, variances, and other properties in mathematics. Knowing how to work with odd numbers can significantly simplify mathematical proofs and calculations.
- 1
- 3
- 5
- 7
- ... up to \(2n-1\)
This sequence is foundational in computing sums, variances, and other properties in mathematics. Knowing how to work with odd numbers can significantly simplify mathematical proofs and calculations.
Sum of Squares
The sum of squares of a series of numbers is a critical concept often encountered in mathematics. When calculating the sum of squares for odd numbers, particularly the first n odd numbers, we use the following formula: \[\frac{n(4n^2 + 1)}{3} \]This formula helps us sum the squares of the first few odd numbers like this:
- 1^2
- 3^2
- 5^2
- ... up to (2n-1)^2
Mathematical Proof
A mathematical proof is a logical argument that demonstrates the truth of a given statement. Proofs are essential in mathematics because they provide a validated framework for understanding why something is true.
When working on problems involving variance and sequences like odd numbers, a proof helps to break down why solutions are correct. For example, showing that the variance of the first n odd numbers is \[\frac{n^2 - 1}{3}\]relies on using known formulas and arithmetic steps. The process involves:
When working on problems involving variance and sequences like odd numbers, a proof helps to break down why solutions are correct. For example, showing that the variance of the first n odd numbers is \[\frac{n^2 - 1}{3}\]relies on using known formulas and arithmetic steps. The process involves:
- Calculating the mean of the sequence
- Finding the sum of squares
- Substituting into the variance formula
Mean Calculation
Calculating the mean of a set of numbers determines the average value of that set. For the first n odd numbers, the arithmetic mean is an essential step in calculating variance.
You find the mean (\(\mu\)) by summing all odd numbers in the sequence and dividing by the count of numbers, which is n. For odd numbers like 1, 3, 5, ..., (2n-1), the sum we use is \(n^2\) from statement 2's formula, leading to:
You find the mean (\(\mu\)) by summing all odd numbers in the sequence and dividing by the count of numbers, which is n. For odd numbers like 1, 3, 5, ..., (2n-1), the sum we use is \(n^2\) from statement 2's formula, leading to:
- Mean \(\mu = \frac{n^2}{n} = n\)
Other exercises in this chapter
Problem 58
Mean of 5 observations is 7 . If four of these observations are \(6,7,8,10\) and one is missing then the variance of all the five observations is : [Online Apri
View solution Problem 59
Let \(x_{1}, x_{2}, \ldots, x_{n}\) be n observations, and let \(\bar{x}\) be their arithmetic mean and \(\sigma^{2}\) be the variance. Statement-1: Variance of
View solution Problem 61
If the mean of \(4,7,2,8,6\) and a is 7 , then the mean deviation from the median of these observations is [Online May 12, 2012] (a) 8 (b) 5 (c) 1 (d) 3
View solution Problem 62
A scientist is weighing each of 30 fishes. Their mean weight worked out is \(30 \mathrm{gm}\) and a standarion deviation of \(2 \mathrm{gm}\). Later, it was fou
View solution