Problem 60
Question
Solve using the square root property. Simplify all radicals. $$ (3-2 x)^{2}=70 $$
Step-by-Step Solution
Verified Answer
The solutions are \( x = \frac{3 - \sqrt{70}}{2} \) and \( x = \frac{3 + \sqrt{70}}{2} \).
1Step 1: Isolate the squared term
The given equation is \( (3-2x)^{2}=70 \). Notice that the squared term \( (3-2x)^{2} \) is already isolated.
2Step 2: Apply the square root property
To remove the square, take the square root of both sides of the equation: \[ \sqrt{(3-2x)^2} = \sqrt{70} \]. This simplifies to two equations: \( 3-2x = \sqrt{70} \) and \( 3-2x = -\sqrt{70} \).
3Step 3: Solve for x in the first equation
Solve \( 3-2x = \sqrt{70} \): \[ 3 - 2x = \sqrt{70} \] Subtract 3 from both sides: \[ -2x = \sqrt{70} - 3 \] Divide by -2: \[ x = \frac{3 - \sqrt{70}}{2} \]
4Step 4: Solve for x in the second equation
Solve \( 3-2x = -\sqrt{70} \): \[ 3 - 2x = -\sqrt{70} \] Subtract 3 from both sides: \[ -2x = -\sqrt{70} - 3 \] Divide by -2: \[ x = \frac{3 + \sqrt{70}}{2} \]
5Step 5: Simplify the solutions
The solutions are \( x = \frac{3 - \sqrt{70}}{2} \) and \( x = \frac{3 + \sqrt{70}}{2} \). Both are simplified.
Key Concepts
Solving Quadratic EquationsSimplifying RadicalsIsolation of Squared TermTaking Square Roots
Solving Quadratic Equations
A quadratic equation is an equation of the form \( ax^2 + bx + c = 0 \). In the exercise given, we have \( (3-2x)^2=70 \), which can be seen as a form of a quadratic equation. To solve any quadratic equation, there are different methods you can use, like factoring, completing the square, and using the quadratic formula. Here, we use the square root property because the equation is already in a specific squared form. This method is often faster and easier when dealing with perfect squares or expressions raised to the power of two.
Simplifying Radicals
Simplifying radicals helps make equations look simpler and more manageable. A radical expression contains a square root, cube root, or other roots. For instance, \( \sqrt{70} \) is a radical. To simplify radicals, we often look for perfect square factors. However, sometimes, like in our example, the number inside the root is already simplified because 70 is not a perfect square and doesn't have any squared factors besides 1. Thus, \( \sqrt{70} \) is already in its simplest form.
Isolation of Squared Term
Isolating the squared term means getting the \(( expression)^2\) part by itself on one side of the equation. This makes it easier to apply the square root property. In our given problem \((3-2x)^2=70\), the squared term \((3-2x)^2\) is already isolated. If it wasn't, we would first need to use algebraic operations (addition, subtraction, multiplication, or division) to get the squared part by itself. Always look for ways to clear out any coefficients or other terms standing in the way of isolating the squared expression.
Taking Square Roots
Taking the square root of both sides is a crucial step in solving equations like \((3-2x)^2=70\). The square root operation undoes the squaring, simplifying the equation. When you take the square root of both sides, remember that \( \sqrt{a^2} = \pm a \). This is why we get two equations: \(3-2x = \sqrt{70}\) and \(3-2x = -\sqrt{70}\). These have to be solved separately. Solving each one involves straightforward algebra: isolating \(x\) by moving other terms to the other side of the equation and then dividing by the coefficient of \(x\). This is how we get the solutions \( x = \frac{3 - \sqrt{70}}{2} \) and \(x = \frac{3 + \sqrt{70}}{2} \). These are the final simplified solutions.
Other exercises in this chapter
Problem 60
Find the value of a, b, or c so that each equation will have exactly one rational solution. (Hint: The discriminant must equal 0 for an equation to have one rat
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Solve each equation by completing the square. Give (a) exact solutions and (b) solutions rounded to the nearest thousandth. \((x-3)(x+1)=1\)
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Solve each equation. Check the solutions. \((t+5)^{2}+6=7(t+5)\)
View solution Problem 61
Find the value of a, b, or c so that each equation will have exactly one rational solution. (Hint: The discriminant must equal 0 for an equation to have one rat
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