Problem 60
Question
Solve each inequality in Exercises 57-84 by first rewriting each one as an equivalent inequality without absolute value bars. Graph the solution set on a number line. Express the solution set using interval notation. $$|x+3| \leq 4$$
Step-by-Step Solution
Verified Answer
The solution to the inequality \(|x+3| \leq 4\) is \([-7, 1]\) in interval notation.
1Step 1: Rewrite the Absolute Value Inequality as a Compound Inequality
An absolute value of an expression being less than or equal to a number can be written as a compound inequality where the expression is both greater than or equal to the negative of the number and less than or equal to the number. Therefore, the inequality \(|x+3| \leq 4\) can be rewritten as \(-4 \leq x+3 \leq 4\).
2Step 2: Solve the Compound Inequality for x
Next, solve the compound inequality \(-4 \leq x+3 \leq 4\) for x by subtracting 3 from all parts of the inequality. This yields \(-4-3 \leq x+3-3 \leq 4-3\), which simplifies to \(-7 \leq x \leq 1\). So all numbers x that satisfy the inequality \(|x+3| \leq 4\) are the numbers between -7 and 1, inclusive.
3Step 3: Draw the Solution Set on a Number Line
To represent this solution set on a number line, draw a line with numbers marked from -7 to 1. Since the inequality includes both -7 and 1, make a solid dot at -7 and 1 to indicate that these values are included in the solution set.
4Step 4: Express the Solution Set in Interval Notation
Lastly, to express the solution set in interval notation, write the solution set as the interval \([-7, 1]\). This means that the solution set consists of all numbers between -7 and 1, inclusive.
Key Concepts
Compound InequalitiesInterval NotationGraphing Solution SetsNumber Line Representation
Compound Inequalities
When dealing with absolute value inequalities like \(|x+3| \leq 4\), it's helpful to rewrite them as compound inequalities. Absolute value expressions can be tricky, but this method makes them more manageable. When an absolute value is less than a number, it implies the expression inside the absolute value is within a certain range. Here, we break it down into two separate inequalities:
- The expression is greater than or equal to the negative of the number.
- The expression is less than or equal to the number.
Interval Notation
Once a compound inequality is solved, it's time to express the solution using interval notation. This notation provides a concise way to represent the set of solutions to an inequality. For the inequality \-7 \leq x \leq 1\, interval notation is used to show that \(x\) can take any value from -7 to 1, inclusive.
The brackets in interval notation have specific meanings:
The brackets in interval notation have specific meanings:
- [ ] include the endpoints, meaning the values at the boundaries are part of the solution.
- ( ) exclude the endpoints, meaning the boundary values are not part of the solution.
Graphing Solution Sets
Graphing inequality solutions offers a visual aid to understanding. For \(-7 \leq x \leq 1\), we represent this on a number line to visually express the range of solutions. Start by drawing a horizontal line and mark critical points such as -7 and 1.
Here's how to graph this specific problem:
Here's how to graph this specific problem:
- Mark a solid line or shading between -7 and 1.
- Place solid dots at -7 and 1 to show these endpoints are included.
Number Line Representation
A number line provides an intuitive tool to display the solution to an inequality. For \(-7 \leq x \leq 1\), a number line helps clarify the range of viable numbers. Here's how to represent it:
- Draw a line with numbers across relevant points, especially focusing on -7 and 1.
- Create solid dots at -7 and 1 to indicate inclusiveness.
- Shade the line between these two points to show the continuous range of solutions.
Other exercises in this chapter
Problem 60
Solve each equation in Exercises \(55-64\) using the quadratic formula. $$ 5 x^{2}+x-2=0 $$
View solution Problem 60
In Exercises \(57-76,\) solve each formula for the specified variable. Do you recognize the formula? If so, what does it describe? \(V=\frac{1}{3} B h\) for \(B
View solution Problem 60
The equations in Exercises \(59-70\) combine the types of equations we have discussed in this section. Solve each equation or state that it is true for all real
View solution Problem 61
Describe similarities and differences between the solutions of $$ (x-2)(x+5) \geq 0 \text { and } \frac{x-2}{x+5} \geq 0 $$
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