Problem 60
Question
\(M_{x}\) and \(M_{y}\) denote the atomic masses of the parent and the daughter nuclei respectively in a radioactive decay. The \(Q\)-value of a \(\beta^{-}\)decay is \(Q_{1}\) and that for a \(\beta^{+}\) decay is \(Q_{2}\). If \(m_{e}\) denotes the mass of an electron, then which of the following statements is correct? [NCERT Exemplar] (a) \(Q_{1}=\left(M_{x}-M_{y}\right) c^{2}\) and \(Q_{2}=\left(M_{x}-M_{y}-2 m_{e}\right) c^{2}\) (b) \(Q_{1}=\left(M_{x}-M_{y}\right) c^{2}\) and \(Q_{2}=\left(M_{x}-M_{y}\right) c^{2}\) (c) \(Q_{1}=\left(M_{x}-M_{y}-2 m_{e}\right) c^{2}\) and \(Q_{2}=\left(M_{x}-M_{y}+2 m_{e}\right) c^{2}\) (d) \(Q_{1}=\left(M_{x}-M_{y}+2 m_{e}\right) c^{2}\) and \(Q_{2}=\left(M_{x}-M_{y}+2 m_{e}\right) c^{2}\)
Step-by-Step Solution
Verified Answer
Option (a) is correct.
1Step 1: Understand the Question
We need to determine how the Q-values for β-decay are related to the masses of parent and daughter nuclei and the mass of an electron. This involves checking the mass-energy equivalence principles used in radioactive decay.
2Step 2: Review β-decay
In β⁻ decay, a neutron is converted into a proton, with the emission of an electron and an antineutrino. In β⁺ decay, a proton is converted into a neutron, with the emission of a positron and a neutrino. The Q-value represents the energy released during these decays.
3Step 3: Apply Mass-Energy Conservation for β⁻ Decay
For β⁻ decay, the Q-value, denoted as Q₁, is given by the difference in atomic masses of the parent and daughter nuclei. Since an electron is emitted, its mass affects the net energy outcome.Thus, the formula becomes: \[ Q₁ = (M_{x} - M_{y})c² \]This reflects the mass-energy equivalence without accounting for the mass of the emitted electron independently, as it's already part of the energy balance.
4Step 4: Apply Mass-Energy Conservation for β⁺ Decay
For β⁺ decay, an additional factor is the appearance of a positron. Thus, the Q-value, Q₂, considers both the mass difference and the additional mass of two electrons (a positron and an electron cancel in mass terms) which aren't part of the atomic masses.Hence, \[ Q₂ = (M_{x} - M_{y} - 2m_{e})c² \]
5Step 5: Identify the Correct Answer
Matching the calculations with the provided options, the correct option is: (a) \(Q_{1}=(M_{x}-M_{y})c^2\) and \(Q_{2}=(M_{x}-M_{y}-2m_{e})c^2\).
Key Concepts
Beta DecayQ-valueMass-Energy EquivalenceNeutron to Proton Conversion
Beta Decay
Beta decay is a fascinating process observed in radioactive substances. It involves the transformation of a neutron into a proton or vice versa. This process is driven by the weak nuclear force, one of the four fundamental forces of nature.
- Beta Minus (β⁻) Decay: In this type of decay, a neutron within the nucleus is converted into a proton.
- This transformation releases an electron (called a beta particle) and an antineutrino.
- Beta Plus (β⁺) Decay: Conversely, this process involves the decay of a proton into a neutron.
- It emits a positron (the antimatter counterpart of the electron) and a neutrino.
Q-value
The Q-value is a crucial concept in understanding nuclear reactions and decay processes. It represents the energy released or absorbed during a nuclear reaction or decay.
- Energy Release: The Q-value can be thought of as the net energy change, typically expressed in units of energy such as MeV (Mega-electronvolts).
- In a nuclear decay, a positive Q-value indicates that the process is exothermic, meaning it releases energy.
- Beta Minus Decay Q-value (Q₁): The energy released is calculated as \[ Q₁ = (M_{x} - M_{y})c^2 \]
- This reflects the mass-energy equivalence principle without directly considering the emitted electron's mass, as it's part of the energy balance.
Mass-Energy Equivalence
Mass-energy equivalence is a fundamental principle in physics, articulated by Einstein's famous equation, \( E=mc^2 \). This states that mass and energy are interchangeable; mass can be converted into energy and vice versa.
- Implications for Decay: In radioactive decay processes, such as beta decay, a tiny loss of mass results in a significant energy release.
- This released energy is what we refer to as the Q-value of the decay reaction. It reflects how the mass difference between the initial and final states translates into energy.
Neutron to Proton Conversion
Neutron to proton conversion is a key aspect of beta decay. This process is fundamental in balancing nuclear reactions and maintaining stability within a nucleus.
- Beta Minus Decay: A neutron inside the nucleus changes into a proton.
- This results in the emission of an electron (beta particle) and an antineutrino, which helps conserve the reaction's energy and momentum.
Other exercises in this chapter
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