Problem 60
Question
Multiply the binomials. $$(z-2)(4 z+3)$$
Step-by-Step Solution
Verified Answer
The product is \(4z^2 - 5z - 6\).
1Step 1: Apply the Distributive Property
To multiply the binomials \((z-2)(4z+3)\), apply the distributive property by multiplying each term in the first binomial by each term in the second. Start with: \[ z imes (4z+3) \] and \[ -2 imes (4z+3) \]
2Step 2: Expand the Binomials
Calculate the individual products for each term:- \(z \times 4z = 4z^2\)- \(z \times 3 = 3z\)- \(-2 \times 4z = -8z\)- \(-2 \times 3 = -6\)
3Step 3: Combine Like Terms
Combine the like terms from the expanded expression:- The expression is \(4z^2 + 3z - 8z - 6\)- Combine the \(z\) terms: \(3z - 8z = -5z\).- Thus, the simplified result is: \(4z^2 - 5z - 6\).
Key Concepts
Distributive PropertyCombining Like TermsPolynomial Expansion
Distributive Property
The Distributive Property is a key mathematical principle that simplifies multiplication over addition or subtraction. When multiplying two binomials, this property comes to the rescue. In our example, \((z-2)(4z+3)\), we distribute each term in the first binomial to each term in the second binomial. First, distribute \(z\) over the second binomial:
- \(z \times 4z\)
- \(z \times 3\)
- \(-2 \times 4z\)
- \(-2 \times 3\)
Combining Like Terms
Once you have used the Distributive Property to expand your binomial multiplication, your result will include several terms that can often look a bit messy. This is where combining like terms becomes essential. In our example, after distributing, we get:\(4z^2 + 3z - 8z - 6\)."Like terms" are terms that have the same variable raised to the same power. Hence, \(3z\) and \(-8z\) are like terms because they both contain \(z\). Combine these like terms by simply doing the arithmetic:
- \(3z - 8z = -5z\)
Polynomial Expansion
Polynomial expansion is the result of applying the Distributive Property to multiply out binomials or polynomials. In our specific example, \((z-2)(4z+3)\), we achieve expansion through systematic distribution and multiplication. By the end of this process, the expanded form of our original expression is \(4z^2 - 5z - 6\).This expanded form is a quadratic polynomial since it includes \(z^2\), z, and constant terms. The expansion transforms an expression that appears compact into one that displays each term distinctly. Mastering this technique is essential for simplifying expressions and solving more complex algebraic equations that involve multiple polynomial terms.
Other exercises in this chapter
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