Problem 60
Question
Let A be any \(3 \times 3\) invertible matrix. Then which one of the following is not always true? \(\quad\) [Online April 8, 2017] (a) \(\operatorname{adj}(\mathrm{A})=|\mathrm{A}| \cdot \mathrm{A}^{-1}\) (b) \(\operatorname{adj}(\operatorname{adj}(\mathrm{A}))=|\mathrm{A}| \cdot \mathrm{A}\) (c) \(a d j(a d j(A))=|A|^{2} \cdot(a d j(A))^{-1}\) (d) \(\operatorname{adj}(\operatorname{adj}(\mathrm{A}))=|\mathrm{A}| \cdot(\operatorname{adj}(\mathrm{A}))^{-1}\)
Step-by-Step Solution
Verified Answer
Option (d) is not always true.
1Step 1: Understanding the Adjugate of Matrix A
The adjugate (or adjoint) of a matrix \( A \), denoted as \( \operatorname{adj}(A) \), is the transpose of its cofactor matrix. For a \( 3 \times 3 \) matrix, the relationship between \( A \), its determinant \( |A| \), and its adjugate is given by \( A \cdot \operatorname{adj}(A) = |A|I \), where \( I \) is the identity matrix.
2Step 2: Verifying Option (a)
Option (a) states that \( \operatorname{adj}(A) = |A| \, A^{-1} \). Using the relationship \( A \cdot \operatorname{adj}(A) = |A|I \) and the definition of the inverse \( A^{-1} = \frac{1}{|A|} \operatorname{adj}(A) \), we find that this statement is always true for invertible matrices.
3Step 3: Verifying Option (b)
Option (b) suggests that \( \operatorname{adj}(\operatorname{adj}(A)) = |A| \cdot A \). By properties of adjugates, \( \operatorname{adj}(\operatorname{adj}(A)) = |A|^{n-2} A \) for an \( n \times n \) matrix. For a \( 3 \times 3 \) matrix, this simplifies to \( |A|A \) when \( n = 3 \). Thus, option (b) is true.
4Step 4: Verifying Option (c)
Option (c) claims \( \operatorname{adj}(\operatorname{adj}(A)) = |A|^2 \cdot (\operatorname{adj}(A))^{-1} \). We know from earlier steps that \( \operatorname{adj}(\operatorname{adj}(A)) = |A|A \). Since \( (\operatorname{adj}(A))^{-1} = \frac{1}{|A|} A \), the right-hand side becomes \( |A| A \), which agrees with our earlier findings. Hence, option (c) is true.
5Step 5: Verifying Option (d)
Option (d) indicates \( \operatorname{adj}(\operatorname{adj}(A)) = |A| \cdot (\operatorname{adj}(A))^{-1} \). From earlier, \( \operatorname{adj}(\operatorname{adj}(A)) = |A|A \) and \((\operatorname{adj}(A))^{-1} = \frac{1}{|A|} A \), thus \(|A| \cdot (\operatorname{adj}(A))^{-1} = A \). Therefore, this does not hold because the two sides do not equate. Thus, option (d) is not always true.
Key Concepts
Adjugate MatrixDeterminantInverse Matrix
Adjugate Matrix
An adjugate matrix, also known as the adjoint of a matrix, is an essential tool in matrix algebra. It's formed by taking the cofactor matrix of a given square matrix and then transposing it. Think of it as rearranging the components of a matrix in a special way that links it closely to the original matrix's determinants.
For a given matrix \( A \), its adjugate is denoted as \( \operatorname{adj}(A) \). A key identity associated with the adjugate for any invertible matrix is:
The adjugate becomes particularly useful when calculating a matrix's inverse, playing a pivotal role in the formula for inversion.
For a given matrix \( A \), its adjugate is denoted as \( \operatorname{adj}(A) \). A key identity associated with the adjugate for any invertible matrix is:
- \( A \cdot \operatorname{adj}(A) = |A|I \)
The adjugate becomes particularly useful when calculating a matrix's inverse, playing a pivotal role in the formula for inversion.
Determinant
The determinant is a scalar value that provides essential insights into certain properties of a matrix. It can be seen as a special ultra-condensed summary of the matrix, useful in determining whether a matrix is invertible or not. For a matrix \( A \), the determinant is represented as \( |A| \).
When the determinant is zero, it means the matrix is singular, or non-invertible. In other terms, there is no inverse matrix, and certain matrix operations like solving linear equations can become undefined.
For a \( 3 \times 3 \) matrix, for instance, calculating the determinant involves a formula connecting its elements which typically involves sums and products of its minors and cofactors.
When the determinant is zero, it means the matrix is singular, or non-invertible. In other terms, there is no inverse matrix, and certain matrix operations like solving linear equations can become undefined.
For a \( 3 \times 3 \) matrix, for instance, calculating the determinant involves a formula connecting its elements which typically involves sums and products of its minors and cofactors.
- The formula involves creating a cofactor matrix and operating with these cofactors and the elements from the first row or column.
Inverse Matrix
An inverse matrix is akin to the opposite of a matrix; capable of undoing the transformation that the original matrix applies. If matrix \( A \) is invertible, its inverse is denoted \( A^{-1} \), and they satisfy the equation:
The identity matrix \( I \) is the equivalent of 1 in matrix multiplication. The existence of \( A^{-1} \) depends on \( A \) being non-singular, i.e., its determinant \( |A| eq 0 \).
A practical formula for finding the inverse, especially in 3x3 matrices, relies on the adjugate matrix and the determinant:
- \( A \cdot A^{-1} = I \)
- \( A^{-1} \cdot A = I \)
The identity matrix \( I \) is the equivalent of 1 in matrix multiplication. The existence of \( A^{-1} \) depends on \( A \) being non-singular, i.e., its determinant \( |A| eq 0 \).
A practical formula for finding the inverse, especially in 3x3 matrices, relies on the adjugate matrix and the determinant:
- \( A^{-1} = \frac{1}{|A|} \operatorname{adj}(A) \)
Other exercises in this chapter
Problem 58
Suppose \(A\) is any \(3 \times 3\) non-singular matrix and \((A-3 I)(A-5 I)=O\), where \(l=I_{3}\) and \(O=O_{3}\). If \(\alpha A+\beta A^{-1}=4 I\), then \(\a
View solution Problem 59
If \(\mathrm{A}=\left[\begin{array}{cc}2 & -3 \\ -4 & 1\end{array}\right]\), then \(\operatorname{adj}\left(3 \mathrm{~A}^{2}+12 \mathrm{~A}\right)\) is equal t
View solution Problem 61
If \(\mathrm{A}=\left[\begin{array}{cc}5 \mathrm{a} & -\mathrm{b} \\ 3 & 2\end{array}\right]\) and \(\mathrm{A} \mathrm{adj} \mathrm{A}=\mathrm{A} \mathrm{A}^{\
View solution Problem 62
Let \(\mathrm{A}\) be a \(3 \times 3\) matrix such that \(\mathrm{A}^{2}-5 \mathrm{~A}+7 \mathrm{I}=0\). Statement \(-\mathrm{I}: \mathrm{A}^{-1}=\frac{1}{7}(5
View solution