Problem 60
Question
In a vacuum, two particles have charges of \(q_{1}\) and \(q_{2}\), where \(q_{1}=+3.5 \mu \mathrm{C}\). They are separated by a distance of \(0.26 \mathrm{~m}\), and particle 1 experiences an attractive force of \(3.4 \mathrm{~N}\). What is \(q_{2}\) (magnitude and sign)?
Step-by-Step Solution
Verified Answer
\(q_2 = -2.88 \, \mu\text{C}\), negative sign.
1Step 1: Identify Given and Required Information
We are given the charge of the first particle \(q_1 = +3.5 \, \mu\text{C}\), the distance between the particles \(r = 0.26 \, \text{m}\), and the force acting on particle 1 is \(F = 3.4 \, \text{N}\). We need to determine the charge \(q_2\).
2Step 2: Recall Coulomb's Law
Coulomb's Law states that the force \(F\) between two charges is given by the formula: \[ F = k \frac{|q_1 q_2|}{r^2} \]where \(k = 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2\) is Coulomb's constant.
3Step 3: Rearrange Coulomb's Law to Solve for \(q_2\)
Rearrange the formula to solve for \(q_2\):\[ |q_2| = \frac{F \cdot r^2}{k \cdot |q_1|} \]
4Step 4: Substitute Known Values
Substitute \(F = 3.4 \, \text{N}\), \(r = 0.26 \, \text{m}\), and \(|q_1| = 3.5 \times 10^{-6} \, \text{C}\) into the formula:\[ |q_2| = \frac{3.4 \cdot (0.26)^2}{8.99 \times 10^9 \cdot 3.5 \times 10^{-6}} \]
5Step 5: Calculate \(q_2\) and Determine its Sign
Calculate the value:\[ |q_2| \approx \frac{3.4 \cdot 0.0676}{8.99 \times 10^9 \cdot 3.5 \times 10^{-6}} \approx 2.88 \times 10^{-6} \, \text{C} \]Since the force is attractive, the charges must be opposite in sign. Therefore, \(q_2\) is negative, \(q_2 = -2.88 \, \mu\text{C}\).
Key Concepts
Electric ForceCharge InteractionsElectrostaticsElectric Charges
Electric Force
The electric force is a fundamental interaction between charged objects. It plays a critical role in our everyday lives, though often operating at scales unseen by the naked eye. According to Coulomb's Law, the magnitude of this force depends on:
- The amount of charge on each object.
- The distance between the objects.
- A constant known as Coulomb’s constant, denoted as \( k \).
- \( F \) is the magnitude of the force.
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges.
- \( r \) is the separation distance between the charges.
- \( k \) is a constant (\( 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2\)).
Charge Interactions
Charge interactions are key to understanding the behavior of electric forces between particles. Simply put:
- Like charges repel each other.
- Unlike charges attract each other.
Electrostatics
Electrostatics is the study of electric charges at rest. Within this realm, forces emerge due to the presence of charged bodies rather than their motion. As such, it encompasses phenomena such as:
- Charging by friction, where electrons are transferred by rubbing two different materials.
- Induction, where charges are rearranged in a material without direct contact.
- Polarization, where the positive and negative charges within an object are aligned, usually in the presence of an external charged object.
Electric Charges
Electric charges are the building blocks of electromagnetism. They come in two types: positive and negative. Typically, protons carry a positive charge, while electrons carry a negative charge. Neutrons are neutral and don't affect the charge balance.The exercise deals with charges measured in microcoulombs (\( \mu\text{C}\)), a convenient unit for small quantities of charge often encountered in problems.Key properties of electric charges include:
- Charge Conservation: Total charge remains constant in an isolated system.
- Quantization: Charge exists in discrete amounts, typically multiples of the elementary charge \( e \).
- Interaction: Opposite charges attract, while like charges repel.
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