Problem 60
Question
How can the vertex of a parabola be used in solving real world problems?
Step-by-Step Solution
Verified Answer
The vertex helps solve real-world problems by determining maximum or minimum values, like peak height or optimal costs, vital in decision making.
1Step 1: Understanding Parabolas
A parabola is a U-shaped graph that can open upwards or downwards. It is the graph of a quadratic function, typically written in the form \( y = ax^2 + bx + c \). Understanding parabolas is important because they often appear in various real-world scenarios.
2Step 2: Identifying the Vertex
The vertex of a parabola is the highest or lowest point on the graph (depending on its orientation). For a parabola in the standard form \( y = ax^2 + bx + c \), the vertex can be found using the formula \( x = -\frac{b}{2a} \). Once \( x \) is found, substitute it back into the equation to find the corresponding \( y \) value.
3Step 3: Application in Real World Problems
The vertex can be used to solve real-world problems where maximum or minimum values are important. For instance, it can determine the maximum height of a projectile, the minimum cost in an economic model, or the optimal design of a structure.
4Step 4: Example Scenario: Projectile Motion
Imagine a ball is thrown into the air. The path of the ball follows a parabolic trajectory, and the vertex represents the highest point of this trajectory. By finding the vertex, one can determine the time and height at which the ball reaches its peak.
5Step 5: Using the Vertex for Decision Making
The vertex can guide decision-making processes. In a profit maximization problem for a business, for example, the vertex of the revenue function can indicate the production level that yields maximum profit.
Key Concepts
Quadratic FunctionProjectile MotionProfit Maximization
Quadratic Function
A quadratic function is a type of polynomial function represented by the equation \( y = ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). The graph of a quadratic function forms a curve known as a parabola, which has a distinctive U-shape. The parabola can either open upwards if \( a > 0 \) or downwards if \( a < 0 \).
A key feature of a quadratic function is its vertex. This is the point where the parabola turns; it's either the maximum or minimum point on the graph depending on the direction the parabola opens. The vertex of a quadratic function in standard form \( y = ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \). Once the \( x \)-value is found, you substitute it back into the equation to find the \( y \)-value, giving the complete coordinates of the vertex.
Understanding the vertex is crucial because it allows for the analysis of optimal points in various real-world applications, such as finding the peak height of a projectile or maximizing business profit.
A key feature of a quadratic function is its vertex. This is the point where the parabola turns; it's either the maximum or minimum point on the graph depending on the direction the parabola opens. The vertex of a quadratic function in standard form \( y = ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \). Once the \( x \)-value is found, you substitute it back into the equation to find the \( y \)-value, giving the complete coordinates of the vertex.
Understanding the vertex is crucial because it allows for the analysis of optimal points in various real-world applications, such as finding the peak height of a projectile or maximizing business profit.
Projectile Motion
Projectile motion is a term used to describe the curved path that an object follows when it is thrown or propelled near the surface of the earth. This path is shaped like a parabola due to the influence of gravity acting on the object.
When analyzing projectile motion, the vertex of the parabolic path is of great interest since it represents the highest point the projectile will reach. To determine this peak point, we solve for the vertex of the quadratic equation that represents the projectile's path. This is crucial in situations such as determining how far a projectile will travel before reaching its peak and when it will hit the ground.
When analyzing projectile motion, the vertex of the parabolic path is of great interest since it represents the highest point the projectile will reach. To determine this peak point, we solve for the vertex of the quadratic equation that represents the projectile's path. This is crucial in situations such as determining how far a projectile will travel before reaching its peak and when it will hit the ground.
- The horizontal motion of the projectile is constant because no external horizontal forces act on it (ignoring air resistance).
- The vertical motion is influenced by gravity, pulling it downward, which makes the motion parabolic.
Profit Maximization
Profit maximization is a common goal for businesses, where companies seek to determine the level of output or sales at which their profits are highest. This maximization often involves using quadratic functions to represent cost, revenue, or profit relationships.
In these cases, the vertex of the parabola formed by the function is particularly important because it indicates the maximum profit point. The equation for profit, often given as \( P(x) = R(x) - C(x) \), where \( R(x) \) is the revenue function and \( C(x) \) is the cost function, can typically be modeled as a quadratic function.
In these cases, the vertex of the parabola formed by the function is particularly important because it indicates the maximum profit point. The equation for profit, often given as \( P(x) = R(x) - C(x) \), where \( R(x) \) is the revenue function and \( C(x) \) is the cost function, can typically be modeled as a quadratic function.
- Finding the vertex provides the production level (\( x \)) that maximizes profit.
- Identifying this point allows businesses to efficiently allocate resources and make informed decisions on production strategies.
Other exercises in this chapter
Problem 58
Evaluate the expressions, writing the result as a simplified complex number. \(\frac{3+2 i}{1+2 i}-\frac{2-3 i}{3+i}\)
View solution Problem 59
Explain the advantage of writing a quadratic function in standard form.
View solution Problem 61
Explain why the condition of \(a \neq 0\) is imposed in the definition of the quadratic function.
View solution Problem 62
What is another name for the standard form of a quadratic function?
View solution