Problem 60
Question
Find the parametric equation of the line in \(x-y-z\) space that goes through the given points. \((2,0,-3)\) and \((4,1,1)\)
Step-by-Step Solution
Verified Answer
The parametric equations are \(x = 2 + 2t\), \(y = t\), \(z = -3 + 4t\).
1Step 1: Find the Direction Vector
Identify the direction vector of the line by subtracting the first point from the second point. With point A as \((2, 0, -3)\) and point B as \((4, 1, 1)\), calculate the direction vector \(\vec{d}\): \(\vec{d} = (4-2, 1-0, 1-(-3)) = (2, 1, 4)\).
2Step 2: Write the Parametric Equations
Using the direction vector \((2, 1, 4)\) and a point on the line, say \((2, 0, -3)\), write the parametric equations. The parametric equations of the line are given by: \(x = 2 + 2t\), \(y = 0 + 1t\), and \(z = -3 + 4t\), where \(t\) is a parameter.
Key Concepts
Direction Vector3D SpaceLine Equation
Direction Vector
When we talk about a direction vector, we are referring to a vector that gives us the orientation or direction of a line. In our specific exercise, to find the direction vector, we need to calculate the difference between two given points. Imagine starting from point A and moving to point B in 3D space. The direction vector is a package of all the changes you make in each direction:
- In the x-direction, move from 2 to 4, resulting in a change of \(4 - 2 = 2\).
- In the y-direction, go from 0 to 1, making a change of \(1 - 0 = 1\).
- Finally, in the z-direction, move from -3 to 1, which changes by \(1 - (-3) = 4\).
3D Space
3D space, short for three-dimensional space, is a place that adds depth to the usual flat, two-dimensional world. Just like how we see our surroundings, it consists of three axes:
In our exercise, points like \(2, 0, -3\) and \(4, 1, 1\) represent specific locations in this 3D world. Understanding how these points relate spatially involves visualizing them in this three-dimensional coordinate system.
- The x-axis, which typically measures horizontal position.
- The y-axis, commonly showing vertical position.
- The z-axis, which adds the depth, making it the third dimension.
In our exercise, points like \(2, 0, -3\) and \(4, 1, 1\) represent specific locations in this 3D world. Understanding how these points relate spatially involves visualizing them in this three-dimensional coordinate system.
Line Equation
The line equation in 3D provides a mathematical description of a line by using points and direction. A popular form to represent it is the parametric equation. It uses a parameter \(t\) to describe points along the line. This parameter acts like a slider, adjusting it slides you along the line. For our exercise, given a point \((2, 0, -3)\) and direction vector \((2, 1, 4)\), the parametric equations for the line are:
- \(x = 2 + 2t\)
- \(y = 0 + 1t\)
- \(z = -3 + 4t\)
Other exercises in this chapter
Problem 59
Find the eigenvalues \(\lambda_{1}\) and \(\lambda_{2}\) for each matrix \(A\). $$A=\left[\begin{array}{lr}1 & -3 \\ 0 & 2\end{array}\right]$$
View solution Problem 59
Write down the inverse of \(A\). $$ A=\left[\begin{array}{rr} 2 & 1 \\ -3 & -1 \end{array}\right] $$
View solution Problem 60
Find the eigenvalues \(\lambda_{1}\) and \(\lambda_{2}\) for each matrix \(A\). $$A=\left[\begin{array}{rr}-1 & 4 \\ 0 & -2\end{array}\right]$$
View solution Problem 60
Write down the inverse of \(A\). $$ A=\left[\begin{array}{ll} 1 & 2 \\ 1 & 3 \end{array}\right] $$
View solution