Problem 60
Question
Factor using the formula for the sum or difference of two cubes. $$x^{3}-27$$
Step-by-Step Solution
Verified Answer
The factored form of the expression \(x^3 - 27\) using the formula for the difference of two cubes is \((x - 3)(x^2 + 3x + 9)\).
1Step 1: Identify the Cubes
The first step is to identify the cubes in our formula. Here, \(x^3\) is our first cube (\(a^3\)) and \(27\) is our second cube (\(b^3\)). Now we need to figure out the cube roots, which are \(x\) for \(x^3\) and \(3\) for \(27\). Now we have our \(a\) and \(b\), which are \(x\) and \(3\) respectively.
2Step 2: Apply the Formula
Now we will apply the formula for the difference of two cubes: \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\). Replacing \(a\) with \(x\) and \(b\) with \(3\), we get: \(x^3 - 3^3 = (x - 3)(x^2 + 3x + (3)^2)\).
3Step 3: Simplify the Result
The final step is to simplify the expanded equation: \(x^3 - 27 = (x - 3)(x^2 + 3x + 9)\).
Other exercises in this chapter
Problem 60
Rewrite each expression without absolute value bars. $$\|-5|-|-||13$$
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Simplify each exponential expression. $$ \left(\frac{3 x^{4}}{y}\right)^{-3} $$
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simplify each complex rational expression. $$ \frac{1+\frac{1}{x}}{3-\frac{1}{x}} $$
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Evaluate each expression in Exercises \(55-66,\) or indicate that the root is not a real number. $$ \sqrt[4]{(-3)^{4}} $$
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